R help - Sep 2017 - update numeric values of list with new values...

Suppose I have the following:

test <- list(a=1,b=2,c=3)

I also have a vector (or list, or something else...) with new numbers

new <- c(4,5,6)

What I'm trying to figure out is how to take the list, and update the 
numbers from {1,2,3} to {4,5,6}

So, in the end,I want the 'update' test list to look like

(a=4,a=5,a=6)

I tried a bunch of obvious things I know about 'replacing' things 
(without success), but the problem in this instance seems to be the fact 
that the list contains elements that are expressions (a=1, a=2,...), 
while the new vector is simply a set of numbers.

So, I want to change the numbers in the list, but retain the character 
parts of the expressions in the list (I need to have the list of 
expressions as is for other purposes).

Doable?

Thanks in advance...

Solved it:

test <- list(a=1,b=2,c=3)
new <- c(4,5,6)

hold <- as.list(new)
updated_test <- replace(test,c(1:3),hold)

$a
[1] 4

$b
[1] 5

$c
[1] 6



mean.parms <- as.list(mean.parms)

mm.parms <- replace(far.parms,c(1:length(far.parms)),mean.parms)

On 9/22/2017 10:34 AM, Evan Cooch wrote:
> Suppose I have the following:
>
> test <- list(a=1,b=2,c=3)
>
> I also have a vector (or list, or something else...) with new numbers
>
> new <- c(4,5,6)
>
> What I'm trying to figure out is how to take the list, and update the 
> numbers from {1,2,3} to {4,5,6}
>
> So, in the end,I want the 'update' test list to look like
>
> (a=4,a=5,a=6)
>
> I tried a bunch of obvious things I know about 'replacing' things 
> (without success), but the problem in this instance seems to be the 
> fact that the list contains elements that are expressions (a=1, 
> a=2,...), while the new vector is simply a set of numbers.
>
> So, I want to change the numbers in the list, but retain the character 
> parts of the expressions in the list (I need to have the list of 
> expressions as is for other purposes).
>
> Doable?
>
> Thanks in advance...
>
>

Well,  that's a bit like driving from Boston to New York by way of Chicago.

See ?structure

test <- list(a=1,b=2,c=3)
new <- c(4,5,6)
test.new <- structure(as.list(new), names=names(test))
test.new
$a
[1] 4

$b
[1] 5

$c
[1] 6

Cheers,
Bert




Bert Gunter

"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )

On Fri, Sep 22, 2017 at 7:51 AM, Evan Cooch <evan.cooch at gmail.com>
wrote:
> Solved it:
>
> test <- list(a=1,b=2,c=3)
> new <- c(4,5,6)
>
> hold <- as.list(new)
> updated_test <- replace(test,c(1:3),hold)
>
> $a
> [1] 4
>
> $b
> [1] 5
>
> $c
> [1] 6
>
>
>
> mean.parms <- as.list(mean.parms)
>
> mm.parms <- replace(far.parms,c(1:length(far.parms)),mean.parms)
>
>
> On 9/22/2017 10:34 AM, Evan Cooch wrote:
>
>> Suppose I have the following:
>>
>> test <- list(a=1,b=2,c=3)
>>
>> I also have a vector (or list, or something else...) with new numbers
>>
>> new <- c(4,5,6)
>>
>> What I'm trying to figure out is how to take the list, and update
the
>> numbers from {1,2,3} to {4,5,6}
>>
>> So, in the end,I want the 'update' test list to look like
>>
>> (a=4,a=5,a=6)
>>
>> I tried a bunch of obvious things I know about 'replacing'
things
>> (without success), but the problem in this instance seems to be the
fact
>> that the list contains elements that are expressions (a=1, a=2,...),
while
>> the new vector is simply a set of numbers.
>>
>> So, I want to change the numbers in the list, but retain the character
>> parts of the expressions in the list (I need to have the list of
>> expressions as is for other purposes).
>>
>> Doable?
>>
>> Thanks in advance...
>>
>>
>>
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