similar to: Combinations

  Dear R helpers   Suppose I have two sets of ranges (interest rates) as   Range 1 : (7 – 7.50, 7.50 – 8.50, 8.50 – 10.00) with respective probabilities 0.42, 0.22 and 0.36.     Range II : (11-12, 12-14, 14-21) with respective probabilities 0.14, 0.56 and 0.30 respectively.     My problem is to form the combinations of these ranges in a decreasing order of joint probabilities. It is assumed that

Hi! Suppose I have a dataset as follows pd = c(10,7,10,11,7,11,7,6,8,3,12,7,7,10,10) I wish to calculate the mean, standard deviation, median, skewness and kurtosis i.e. regular standard statistical measures. average = mean(pd) stdev    = sd(pd) median = median(pd) skew    = skewness(pd) kurt     =  kurtosis(pd) Q. No (1) How do I get these at a stretch using some R package? I came across

Dear R helpers   After executing the R code, where the last few lines of the code are something like given below.     ## Part of my R code     n = 20   ........ .........   final_output = data.frame(Numbers = numbers, ABC = data1, XYZ = data2, PQR = data3)           write.csv(data.frame(Scenario = paste("Sc_", 1:n, sep = ""), final_output'), 'result.csv', row.names

Dear R helpers   Suppose e.g. I have a csv file having three variables defined and each of these variables have data items of say 40, 50, 45 length. When I open this csv file in 'R', I get 10 trailing 'NA's under first column and 5 'NA' s in case of 3rd column.   How do I get rid of these NA's s.t. when I read the first column, there should be only 40 data items, 2nd

Dear 'R' friends I have a sort of stupid question to ask. I have a matrix say of the order 4 X 3 as 83    98    90 21    83    84 70    39    56 65    29    38 Is there any command in R which will reverse the order i.e. I need to have same 4 X 3 matrix but as given below 65    29    38 70    39    56 21    83    84 83    98    90 i.e. the last row becomes first row, second - last row

I have a data set something like this: "YYYY", "Value" 1972 , 117 1984 , 73 1969 , 92 1976 , 113 1999 , 80 1996 , 78 1976 , 98 1984 , 106 1976 , 99 it could be created with: > dafSamp <- data.frame(cbind(c(1972,1984,1969,1976,1999,1996,1976,1984,1976),c(117,73,92,113,80,78,98,106,99))) The real dataset is of cause much larger, app. 100.000 samples

Dear R helpers   Following is a part of R code.   data_lab <- expand.grid(c("R11", "R12", "R13"), c("R21", "R22", "R23"), c("R31", "R32", "R33"), c("R41", "R42", "R43"), c("R51", "R52", "R53"), c("R61", "R62", "R63"),

Greetings, I am a very novice user with R, and in the course of running a linking procedure : P.old<- function (a, c, b, xi){ #a contains a parameters #c contains c parameters #b contains b parameters #xi is a one column vector containing quadrature points for xi(=theta-gamma)for one item tmp <- a*(xi-b)

Dear R helpers   I have some variables say ABC, DEF, PQR, LMN and XYZ. I am choosing any three varaibles at random at a time for my analysis and name these files as input1.csv, input2.csv and input3.csv. So if I choose variables say ABC, DEF and PQR, I am passing the specifications of these variables to input1.csv, input2.csv and input3.csv respectively.   This means in another case even if I

Hi, I am trying to draw a perpendicular line from a point to two points. Mathematically I know how to do it, but to program it, I encounter some problem and hope can get help. Thanks. I have points, A, B and C. I calculate the slope and intercept for line drawn between A and B. I am trying to check whether I can draw a perpendicular line from C to line AB and get the x,y value for the point D

hi, is there any wait function in R. I am running one R script to plot many graphs it is in the for loop. its showing no error but its not plotting well I think i can solve this problem with a wait function. Please help me in this regards. If u need any clarification about programme. u can find the script below. best regards, Deepak.M.R Biocomputing Group University of Bologana. #!/usr/bin/R

Dear all, I would like something simple to do in R that I do not know how I should search for it. Let's say that I have a list of a<-c(1,2,3,4,5) b<-(6,7,8) and I want to get back all their possible cominations like 1,6 1,7 1,8 2,6 2,7 2,8 3,6 3,7 3,8 and so on. How I can do that? B.R Alex [[alternative HTML version deleted]]

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Hi I know there is a function - I have used it before - but I always forget what it is called... I need the combination of two character vectors, i.e: x <- c("a", "b") y <- c("x", "y") z <- THEFUNCTION(x, y) z == c("ax", "ay", "bx", "by") I promise I will

Hi all, I'm using regular analog phones with * and an ATA186, and I plan to move to cordless phones. But cordless phones usually have no way to flash hook cause there is no hook :-) I seem to recall there is a way to simulate a flash hook using dtmf tones in *, but I can't find which combination to use. More generally, where can I find all those magic cominations to put people on hold,

Hi I have used the amelia command from the Amelia R package. this gives me a number of imputed datasets. This may be a silly question, but i am not a statistician, but I am not sure how to combine these results to obtain the imputed dataset to usse for further statistical analysis. I have looked through the amelia and zelig manuals but still can not find the answer. This maybe because I dont

Hi everybody, I am quite new to data imputation, but I would like to use the R package ' Amelia II: A Program for Missing Data '. However, its unclear to me how the input for amelia should look like: I have a data frame consisting of numerous coulmns, which represent different experimental conditions, whereby each column has 3 replicates. I want amelia to perform an imputation across

I am fairly new at using R/programming in general so I apologize if I am leaving crucial parts of the puzzle out, but here goes. First and foremost this is the error I am receiving: Error in muPriors[priors[, 1:2]] <- priors[, 3] : NAs are not allowed in subscripted assignments This occurs only when I am using observational priors and some number of nominal variables, it does not

Hello R-sig-debian and (hopefully) Dirk: On Debian wheezy, I have the R packaging that CRAN (you) provide. I run into a little trouble while trying to fiddle with alternative BLAS. I know you and I went around on this last year and I think perhaps I've found something wrong in the framework, or I've just done something wrong. I installed the packages openblas-base and openblas-dev, and

i have time series as 1.3578511 0.5119648 1.3189847 0.9214787 1.2272616 4.9167998 1.2272616 1.2272616 0.8854192 2.3386331 1.6132899 0.2030302 0.8426226 1.2277843 NA 1.3189847 1.3578511 0.8530141 2.3386331 1.0541099 0.7747481 0.5764672 1.3189847 1.2160533 1.2272616 0.6715839 0.9651803 1.6132899 1.2006974 0.6875047 1.3245534 1.2006974 0.8221709 1.3101684 1.6132899 1.6132899 1.2006974 1.3189847

Dear all. First of all, my english isn't verry good, but I hope I can convey my concern. I've a general question about the Amelia algorithm. I'm no mathematician or statistician, but I had to use R and impute and analyse some data, and Amelia showed results that fitted my expectations. I'll have to defend my choice soon, but I haven't totally grasped what Amelia does. I'm