similar to: (no subject)

Hi Group, I've a vector of 1000 numeric values for which I want to draw a histogram. I've read this vector into R with no variable name.I mean only the 1000 values, which makes V1 the name of the variable by default?? Then I tried > hist(V1, breaks = "Sturges", +      freq = NULL, probability = !freq, +      include.lowest = TRUE, right = TRUE, +      density = NULL, angle =

I have no idea to be honest. I have never used the package, I simply did a search for it. Hopefully a more experienced user can help --- On Sun, 7/12/09, maram salem <marammagdysalem at yahoo.com> wrote: > From: maram salem <marammagdysalem at yahoo.com> > Subject: Re: [R] (no subject) > To: "John Kane" <jrkrideau at yahoo.ca> > Received: Sunday, July 12,

I would like to ask once more if this is reproducible also for others? If yes, should I submit it as a bug-report? Best, Jon On 11/28/2016 11:26 AM, Jon Skoien wrote: > I first answered to the email below in r-help, but as I did not see > any response, and it looks like a bug/unwanted behavior, I am also > posting here. I have observed this in RGui, whereas it seems not to >

I first answered to the email below in r-help, but as I did not see any response, and it looks like a bug/unwanted behavior, I am also posting here. I have observed this in RGui, whereas it seems not to happen in RStudio. Similar to OP, I sometimes have a problem with functions using the progress bar. Frequently, the console is cleared after x iterations when the progress bar is called in a

Dear list, I'm trying to do a set of generic functions do make contingency tables from data.frames. It is just running "nice" (I'm learning R), but I think it can be better. I would like to filter the data.frame, i.e, eliminate all not numeric variables. And I don't know how to make it: please, help me. Below one of the my functions ('er' is a mention to EasieR,

Hi Folks, I'd like to know how hist() decides how many cells to use when it ignores my "suggestion" to use say 'hist(...,breaks=50)'. More specifically, I have the results of 10000 simulations, each returning an 8-vector, therefore 8 variables each with 10000 values. Some of these 8 have somewhat skew distributions. Say one of these 8 variables is X. I ask for H <-

Hi All, I would like to make an invitation to make a collective package with all functions related to TABLES. I know that there are many packages with these functions, the original idea is collect all this functions and to make a single package, because is arduous for the user know all this functions broadcast in many packages. So, I think that the original packages can continue with its

Hi all, I want the y-axis label to be ( in symbols) g(sigma given alpha) where given is the conditional sign. I've tried ylab=expression(g(sigma|alpha))) but it gave me g(|(sigma,alpha)) where the sigma and alpha are in greek but the conditional sign is misplaced (before the bracket) Any help would be appreciated. Maram. [[alternative HTML version deleted]]

Hi all, I've a question concerning the R 3.3.1 version. I have a long code that I used to run on versions earlier to the 3.3.1 version, and when I copied the code to the R console, I can still see the code while the loop is executing , along with the output printed after each iteration of the loop. Now, on the 3.3.1 version, after I copy the code to the console, it disappears and I only see

Hi all, I've a question concerning the R 3.3.1 version. I have a long code that I used to run on versions earlier to the 3.3.1 version, and when I copied the code to the R console, I can still see the code while the loop is executing , along with the output printed after each iteration of the loop. Now, on the 3.3.1 version, after I copy the code to the console, it disappears and I only see

Dear group, Thank u so much 4 ur help. I've tried the link, http://finzi.psych.upenn.edu/R/library/quantreg/html/akj.html for adaptive kernel density estimation. But since I'm an R beginer and the topic of adaptive estimation is new for me, i still can't figure out some of the arguments of akj(x, z =, p =, h = -1, alpha = 0.5, kappa = 0.9, iker1 = 0) I've a vector of 1000 values

Hi all, I've a linear equation of the form: 0.95=2 ( [3+ln(x/3)]^-13  + 4 [3+2ln(x/3)]^-13  + [3+4ln(x/3)]^-13 ) and I want to solve it for x, can I do this using R? Thanks in advance. Maram. [[alternative HTML version deleted]]

Dear All, Attached are the codes of a histogram & a kernel density estimate and the output they produced. In fact the variable q is a vector of 1000 simulated values; that is I generated 1000 samples from the pareto distribution, from each sample I calculated the value of q ( a certain fn in the sample observations), and thus I was left with 1000 values of q and I don't know the

Dear all, How can I use the histogram density estimate (hist) to find the value of the cdf at a certain point? Thanks Maram [[alternative HTML version deleted]]

Dear all, I have the cdf of the following power fuction distribution: F(y)=(y/350)^a               ,0<y<350, where " a " is some parameter with range a>0. I want to use it as the argument of the discretize function of the actuar package. So I think I need to define this function to R so that if I entered a=1, I get the following F(y)=(y/350) and if I entered a=4.5, I get the

Hi all, I've a trivial question. If (q) is a continous variable,actually a vector of 1000 values. how to calculate the probability that q is greater than a specific value, i.e. P(q>45)?? Thanks Maram [[alternative HTML version deleted]]

Hi all, I'm using a certain  procedure to calculate the value of some variable(Bayes risk),B. So I got the values B1, B2, ........, B1000, each under certain input values and using a long procedure. Now, I want to put the values I got in a nummerical vector and find their minimum value. I think c( ) should work.For example if I have only 10 values I could have used

Dear All, I have a matrix m of the form  m             [,1]             [,2]   [1,]  9072.302 0.00000004462366   [2,]  9086.811 0.00000005628169   [3,]  9101.320 0.00000007126347   [4,]  9115.830 0.00000008986976   [5,]  9130.339 0.00000011260000   [6,]  9144.848 0.00000014018405   [7,]  9159.357 0.00000017344229   [8,]  9173.866 0.00000021363563   [9,]  9188.375 0.00000026389996  [10,]  9202.884

Sorry, I didn't mean a linear equation, of course this equation is not linear, I meant an equation in one unknown. Hi all, I've a linear equation of the form: 0.95=2 ( [3+ln(x/3)]^-13? + 4 [3+2ln(x/3)]^-13? + [3+4ln(x/3)]^-13 ) and I want to solve it for x, can I do this using R? Thanks in advance. Maram. ? ? ? ??? [[alternative HTML version deleted]] -------------- next

Dear All, I have a variable q which is a vector of 1000 simulated positive values; that is I generated 1000 samples from the pareto distribution, from each sample I calculated the value of q ( a certain fn in the sample observations), and thus I was left with 1000 values of q and I don't know the distribution of q. Hence, I used the given code for kernel density estimation to estimate the