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--- On Tue, 6/30/09, maram salem <marammagdysalem at yahoo.com> wrote: > From: maram salem <marammagdysalem at yahoo.com> > Subject: [R] (no subject) > To: r-help at r-project.org > Received: Tuesday, June 30, 2009, 6:34 AM > Hi Group, > I've a vector of 1000 numeric values for which I want to > draw a histogram. I've read this vector into R with no >

Hi Folks, I'd like to know how hist() decides how many cells to use when it ignores my "suggestion" to use say 'hist(...,breaks=50)'. More specifically, I have the results of 10000 simulations, each returning an 8-vector, therefore 8 variables each with 10000 values. Some of these 8 have somewhat skew distributions. Say one of these 8 variables is X. I ask for H <-

Dear list, I'm trying to do a set of generic functions do make contingency tables from data.frames. It is just running "nice" (I'm learning R), but I think it can be better. I would like to filter the data.frame, i.e, eliminate all not numeric variables. And I don't know how to make it: please, help me. Below one of the my functions ('er' is a mention to EasieR,

Hi All, I would like to make an invitation to make a collective package with all functions related to TABLES. I know that there are many packages with these functions, the original idea is collect all this functions and to make a single package, because is arduous for the user know all this functions broadcast in many packages. So, I think that the original packages can continue with its

Hi all, I've a question concerning the R 3.3.1 version. I have a long code that I used to run on versions earlier to the 3.3.1 version, and when I copied the code to the R console, I can still see the code while the loop is executing , along with the output printed after each iteration of the loop. Now, on the 3.3.1 version, after I copy the code to the console, it disappears and I only see

Hi all, I've a question concerning the R 3.3.1 version. I have a long code that I used to run on versions earlier to the 3.3.1 version, and when I copied the code to the R console, I can still see the code while the loop is executing , along with the output printed after each iteration of the loop. Now, on the 3.3.1 version, after I copy the code to the console, it disappears and I only see

Dear All, According to the Sturges rule, the number of classes of a histogram is the closest integer to 1 + logb(n,base=2) where n is the number of observations. The function hist(), by default, uses the Sturges rule. However, the code x <- 1:200 hist(x) produces a histogram with 10 classes and not 9 classes as determined by the Sturges rule. What am I missing? Thanks in advance, Paul

Hi all, I want the y-axis label to be ( in symbols) g(sigma given alpha) where given is the conditional sign. I've tried ylab=expression(g(sigma|alpha))) but it gave me g(|(sigma,alpha)) where the sigma and alpha are in greek but the conditional sign is misplaced (before the bracket) Any help would be appreciated. Maram. [[alternative HTML version deleted]]

I first answered to the email below in r-help, but as I did not see any response, and it looks like a bug/unwanted behavior, I am also posting here. I have observed this in RGui, whereas it seems not to happen in RStudio. Similar to OP, I sometimes have a problem with functions using the progress bar. Frequently, the console is cleared after x iterations when the progress bar is called in a

Buenas. Sé que en R hay multitud de datasets y me haría falta alguno que trataran de variables relacionadas con salud, sobre todo para aprender más acerca de cómo realizar una regresión logística binomial o multinomial. Gracias..

Dear All, Attached are the codes of a histogram & a kernel density estimate and the output they produced. In fact the variable q is a vector of 1000 simulated values; that is I generated 1000 samples from the pareto distribution, from each sample I calculated the value of q ( a certain fn in the sample observations), and thus I was left with 1000 values of q and I don't know the

Hi all, I've a linear equation of the form: 0.95=2 ( [3+ln(x/3)]^-13  + 4 [3+2ln(x/3)]^-13  + [3+4ln(x/3)]^-13 ) and I want to solve it for x, can I do this using R? Thanks in advance. Maram. [[alternative HTML version deleted]]

Dear all, How can I use the histogram density estimate (hist) to find the value of the cdf at a certain point? Thanks Maram [[alternative HTML version deleted]]

Hi all: As to hist,the help file says:" R's default with equi-spaced breaks (also the default) is to plot the counts in the cells defined by breaks." I wanna know how the break is calculated by R? In other words: break = (max - min)/(number of group) but how the "number of group" is calculated by R? Thanks!

Dear all, I am a newbie in R and could not find help on this problem. I am trying to plot an histogram with probabilities in the y axis. This is the code I am using: #TLC uniform n=30 mi=1; mx=6 nrep=1000 xbar=rep(0,nrep) for (i in 1:nrep) {xbar[i]=mean(runif(n,min=mi,max=mx))} hist(xbar,prob=TRUE,breaks="Sturges",xlim=c(1,6),main=paste("n =",n), xlab="Média",

Full_Name: Reinhold Koch Version: 1.6.1 OS: redhat 8.0 Submission from: (NULL) (131.152.84.111) I came across rather weird behavior of the breaks in hist: hist(1:3) gives the expected result, besides an unnecessary gap between 2nd and 3rd column hist(1:4) always merges up the first two columns, also if I resort to hist.default(1:4,breaks=1:4). hist.default(1:4, include.lowest=F) gives an

Hi folks I'm trying to plot a normalized frequency histogram of some data. After checking the docs, it seems there is no built in feature for this. from the definition for normalized frequency, I need to divide the relative frequency by the size of the intervals being used. So I could divide the series by this interval length, and then plot the relative frequency. The problem is

Hello,<?xml:namespace prefix = o ns = "urn:schemas-microsoft-com:office:office" /><o:p></o:p> I would like to create a histogram from a data collumn consisting of 4 classes (0; 0.05;0.5;25;75). Due to the difference in scale the classes 0;0.05 and 0.5 are displayed within one combined bin by default with the code:Hist(x, scale="percent",

Hi, Standard correlations (Pearson's, Spearman's, Kendall's Tau) do not accurately reflect how closely the model (GAM) fits the data. I was told that the accuracy of the correlation can be improved using a root mean square deviation (RMSD) calculation on binned data. For example, let 'o' be the real, observed data and 'm' be the model data. I believe I can calculate

Hi all, I improved a function drawing horizontal histograms (code below) which uses barplot and works fine. It does,however, need to assign a function to the global environment to later find the actual location on the vertical axis, and not the number of bars used by barplot. Hopefully, running the examples below will illustrate that. As said, it works perfectly fine and does exactly what I