similar to: variable driven summary of one column

If I use latex(summary(X)) where X is a data frame with four variables I get something like Rainfall Education Popden Nonwhite Min. :10.00 Min. : 9.00 Min. :1441 Min. : 0.80 1st Qu.:32.75 1st Qu.:10.40 1st Qu.:3104 1st Qu.: 4.95 Median :38.00 Median :11.05 Median :3567 Median :10.40 Mean :37.37 Mean :10.97 Mean :3866

Dear all When using Sweave, I'm always hitting the same bump: I want to group repetitive calls in a function, but I want both the results and the function calls in the printed output. Let me explain myself. Consider the following computation in an Sweave document: summary(iris[,1:2]) cor(iris[,1:2]) When using these two calls directly, I obtain the following output: > summary(iris[,1:2])

What is equivalent to DROP or KEEP statements of SAS in R? -- This message was sent on behalf of sarjinder at yahoo.com at openSubscriber.com http://www.opensubscriber.com/messages/r-help at r-project.org/topic.html

I have one table(profiles) where each row has many rows in another table(carriers). If I write profile.carriers I get a collection containing all carriers that belong to the current profile. My question is: how do I sort the collection profile.carriers? I would like to sort it on one of the columns (found in the table carriers). Can I override some method in the carrier model or somewhere

Hi, is there a way to receive a total summary of a numerical matrix? I'm trying to get a total overview of numerical matrix. Using summary(nummat) only hands back the Min, 1st Qu, Median, Mean, 3rd Qu and Max for each column. What I actually need is all the Information for the whole matrix. Anyone an idea how to do it? Thanks in advance, -- Anne Skoeries

I use by() to generate a summary statistics like so: Lbys <- by(dat[Nidx], dat$LipTest, summary) where Nidx is an index vector with names picking out the columns in the data frame dat. This returns a list of character arrays (see below for str() output) where the columns are named correctly but the rownames are empty strings and the values are strings prepended with the summary

Hi, is it possible to put a summary of an rpart-Object into a tktext-window? Here is what I'm trying to do: fit <- rpart(Kyphosis ~ Age + Number + Start, data=kyphosis) tt <- tktoplevel() tex <- tktext(tt) tkpack(tex) tkinsert(tex, "end", summary(fit)) But since the summary of an object is a list, I always get back the following error-message: cannot handle object of

When I attach data frames I often want to be able to refer to the whole data frame rather then one of its components. For example: attach (my.data.frame) summary(my.data.frame) That's fine but often the frame has a very long name so I'd prefer some shorthand way of referring to it by its position on the search list. This applies especially to cases where I have a nested data frame

Hello, My questions are meant to be not necessarily specific...I am looking for advice and best practices for setting up an R environment. Here's my situation: I am one of perhaps three or four individuals who will be analyzing the same data through the use of R. I would like to set up a "base" environment for our project, basically some scripts that connect to a database, load

Hi there, I'm trying to remove multiple columns by name from a data.frame. As a result I need to get back the modified data.frame without the removed columns. My columns I want to delete are listed in a vector called "delete". data <- read.csv2("data.csv") delete <- c("col1", "col2", "col3") newData <- subset(data, select =

Hi all, I've been having trouble with something that seems like it should be fairly straight forward. Any help at all from more experienced users is appreciated! I'd like to write a function that uses a column name as an argument. However, I run into problems when I try to reference this column within the function. For example, findCutoff <- function(tableName, columnName) {

dear R wizards --- would it make sense for names(d$columnname) to be "columnname"? I can preserve the columnname through x=subset(dataset, select="columnname"), of course, but it would seem that x=d$columnname could also do this. No? Sincerely, /iaw

Hi, I'm working with a data.frame containing values between 0 and 22000. Most of the values are actually between 0 and 50 and the high ones are outliers. I want to generate a boxplot and since the outliers are extremely high, I need to scale the y scale logarithmically. Otherwise one wouldn't really see the boxes of the boxplot. boxplot(dat, log="y", ylim=c(0,

I created a tex file following the example in the Sweave help which produced the following files in my working directory. Sweave-test-1-006.eps Sweave-test-1-006.pdf Sweave-test-1-007.eps Sweave-test-1-007.pdf Sweave-test-1.tex When I run latex on this, I get a latex error, log file below. I am running R 2.1.1 on Windows XP. I have installed "small MiKTeX" and I have added

Hi, I am creating a function and ran into the problem of selecting a column from a dataset. It seems as though the $ function (as in data$columnname) does not apply in the function. In simplified version: This works: testf2<-function(data,columnnumber){print(data[,columnnumber])} But this doesn't: testf<-function(data,column){print(data$column)} Even though the first solution works,

I have found Sweave() to be great for producing PDF documents. I have been experimenting with RweaveHTML (from the R2HTML) package and have had moderate success. My main issue has been that I simply want the R output to be shown verbatim in the HTML document but RweaveHTML tends to convert most output to a table, for example. So, is there a way to force the RweaveHTML driver to simply provide

Hello, In my script I would like to use a loop, which sorts the dataframe according to different columns, pointed by the string variable. id col1 col2 col3 1 10 0 4 8 2 11 1 2 2 3 12 0 8 3 4 13 0 5 5 Usually the order() function can be used like this: sorted = mytable**[order(column3) , ] which results in properly sorted table: **

hi everyone : suppose i have a matrix in which some column names are identical so, for example, TEMP "AAA", "BBB", "CCC", "DDD","AAA", "BBB" 0 2 1 2 0 0 2 3 7 6 0 1 1.5 4 9 9 6 0 1.0 6 10 11 3 3 I didn't even check yet

Hallo, I'm dynamically generating buttons depending on the number of rows of my dataframe. Every button is supposed to call a function which generates a plot with the values of one of my dataframe rows. My code looks like this: base <- tktoplevel() plotten <- function(mat, namen, titel) { midpts <- barplot(height=mat, names.arg = namen, main = titel, las=2)

Hello R users I recently learned how to use this command: lapply(datum,"[[","ColumnName") Unfortunately, I don't know how exactly it works, what it's called (in particular the "[[" part], and what other things you can do with it (retrieve multiple columns?). Given datum is a list of dataframes with the same column, but different number of rows,