similar to: Writing list object to a file

I have time series observation on daily frequencies : library(zoo) SD=1 date1 = seq(as.Date("01/01/01", format = "%m/%d/%y"), as.Date("12/31/02", format = "%m/%d/%y"), by = 1) len1 = length(date1); data1 = zoo(matrix(rnorm(len1, mean=0, sd=SD*0.5), nrow = len1),  date1) plot(data1) Now I want to calculate 1. Quarterly statistics like mean, variance etc

Hi all, Suppose I have following dataset : library(zoo) SD = 1 date1 = seq(as.Date("01/01/90", format = "%m/%d/%y"), as.Date("12/31/08", format = "%m/%d/%y"), by = 1) len1 = length(date1); data1 = zoo(matrix(rnorm(len1, mean=0, sd=SD*0.5), nrow = len1), date1) Now I want to extract monthly observation. obs =

Dear r-users, Suppose I have two data sets data set-1 Date height ------------------------ 1/11/2005 10 2/11/2005 23 3/11/2005 54 4/11/2005 21 5/11/2005 22 data set-2 weight -------- 32 45 11 Now I want to combine this two data sets. i.e. i want to see: Date height weight ------------------------------------------- 3/11/2005 54

Hi everybody, I am beginer in R and I need your precious help. I want to create a small function in R as in sas to retrieve date. I have a file with data that import in R. DATE PAYS nb_pays.ILI. 1 24/04/2009 usa 0 2 24/04/2009 usa 0 3 24/04/2009 Mexique 0 4 24/04/2009

Dear aDVISOR, Hope I am not disturbing you. Can you tell me how I can perform Multivariate Garch analysis in R. Also please, it is my humble request let me know some resource materials on Multivariate Garch analysis itself. Sincerely yours, -- Arun Kumar Saha, M.Sc.[C.U.] S T A T I S T I C I A N [Analyst] Transgraph Consulting [www.transgraph.com] Hyderabad, INDIA Contact # Home:

Dear all R users, I want to insert the R logo in every graphic that I made in my Statistical analysis using R. Can anyone tell me whether is it possible or not and if possible how to do this? your help will be highly appreciated. Thanks and Regards, Arun [[alternative HTML version deleted]]

Dear all, I have a variable 'x' like that: > x [1] "2005-09-01" Here, 2005 represents year, 09 month and 01 day. Now I want to create three variables naming: y, m, and d such that: y = 2005 m = 09 d = 01 can anyone tell me how to do that? Regards, [[alternative HTML version deleted]]

Hi, Try this: el<- read.csv("el.csv",header=TRUE,sep="\t",stringsAsFactors=FALSE) ?elsplit<- split(el,el$st) ? datetrial<-data.frame(date1=seq.Date(as.Date("1930.1.1",format="%Y.%m.%d"),as.Date("2010.12.31",format="%Y.%m.%d"),by="day")) elsplit1<- lapply(elsplit,function(x)

Hi all, I wrote some user defined function for my own. Now I want to get a mechanism so that every time I start R, those function will automatically be loaded in R without manually copying pasting. Can gurus here pls tell me how to do that? Or I have to build my own packages bundled with those functions. However I am not familiar in writing R package yet. Regards, [[alternative HTML version

HI Fares, You could try this: dat1<- read.table(text=" date????? donation 3jan2003?? 20235 4jan2003?? 25655 5jan2003?? 225860 6jan2003?? 289658 7jan2003?? 243889 8jan2003?? 244338 9jan2003?? 243889 ",sep="",header=TRUE,stringsAsFactors=FALSE) The post is not very specific as to what you need.? I hope this works for you. library(xts)

Dear all R users, I am wondering whether there is any way to replace all "NA" values in a data frame by some numerical value, suppose 1000? Thanks and Regards [[alternative HTML version deleted]]

Hi Elisa, Try this: date1<-format(seq.Date(as.Date("1991.1.1",format="%Y.%m.%d"),as.Date("1996.12.31",format="%Y.%m.%d"),by="day"),"%Y.%m.%d") ?length(date1) #[1] 2192 mat1<-matrix(c(.314,.314,.273,.273,.236,.236,.236,.236,.273,.314,.403,.314),ncol=1) res1<-

Dear all, It is not a R related problem rather than statistical/mathematical. However I am posting this query hoping that anyone can help me on this matter. My problem is to get the Geometrical Interpretation of Eigen value and Eigen vector of any square matrix. Can anyone give me a light on it? Thanks and regards, Arun [[alternative HTML version deleted]]

Here I am in a simulation study where I want to find different values of x and y such that f(x,y)=c (some known constant) w.r.t. x, y >0, y<=x and x<=c1 (another known constant). Can anyone please tell me how to do it efficiently in R. One way I thought that I will draw different random numbers from uniform dist according to that constraints and pick those which satisfy f(x,y)=c. However

Dear all R-users, I would like to draw a tangent of a given function for a particular (given) point. However the straight line representing it should not cut any axis, it should be a small line. Can anyone tell me how to do this? Thanks, Arun [[alternative HTML version deleted]]

I have and XTS time series object that has date and time. I started with 1 minute data and used apply.daily(x, sum) to sum the data to one cumulative value. This function works just fine however it leaves a time for the last summed value which looks like this 2006-07-19 14:58:00. I need to just have the date and to remove the time value of 14:58:00 just leaving the date value of 2006-07-19 .

Dear all r-users, Suppose I have two data frame: A 1 3 4 5 2 and B 5 6 3 5 Now I want combine this two data frames without losing any value from either data frame. More precisely I want to see A B 1 5 3 6 4 3 5 5 2 NA I tried with cbind function but failed, as it only works when two data frames have equal number of rows. Can anyone suggest me any code that can be used for any

Hi, ?In the example you provided, it looks like the dates in Date2 happens first.? So, I changed it a bit.? DataA<- read.table(text=" ID,Status,Date1,Date2 ??? ??? ?????? 1,A,3-Feb-01,15-May-01 ??? ??? 1,B,15-May-01,16-May-01 ??? ??? 1,A,16-May-01,3-Sep-01 ??? ??? ??? ??? ??? 1,B,3-Sep-01,13-Sep-01 ??? ??? ??? ??? ??? 1,C,13-Sep-01,26-Feb-04 ??? ??? ??? ??? ???

Suppose I have a Variance-covariance matrix A. Is there any fast way to calculate correlation matrix from 'A' and vice-versa without emplying any 'for' loop? [[alternative HTML version deleted]]

There is "if-else" loop if I have to choose 1 item from a 2-item list. However if I have a list of 4 items (let say) then how i can choose a single item without employing 'if-else' loop? I mean in VBA I can use "select-case", is there any equivalent in R as well? Regards, [[alternative HTML version deleted]]