similar to: Sampling letters

Hi, I searched the archives and did not find a good solution to that. assume I have 10 sets and I want to have the common character elements of them. how could i do that? -- Weiwei Shi, Ph.D Research Scientist GeneGO, Inc. "Did you always know?" "No, I did not. But I believed..." ---Matrix III

ng, I have a matrix (x) with binary content. Each row of the matrix holds exactly one 1, and the rest of the row is zeros. The thing is that I need to 'collapse' the matrix to one column where each row holds the original column index of the 1's (y). Sometimes, the matrix is quite large, so I have a perfomance problem. x <- matrix(c(1,0,0, 0,0,1, 0,1,0, 0,0,1, 0,1,0,

Hi everyone, My goal is to sample from a two-dimensional grid. Consider the following example of code: n.grid <- 500 muA.grid <- seq(-4,4, length=n.grid) muB.grid <- seq(-4,4, length=n.grid) mu.p <- matrix(NA, nrow=n.grid, ncol=n.grid) for(i in 1:n.grid){ for(j in 1:n.grid){ mu.p[i,j] <- dnorm(muA.grid[i], 0, 1)*dnorm(muB.grid[j], 0, 0.5) } } mu.p <-

Hi, I have an integer matrix consisting of 1's and 0's and I would like to convert this to a data.frame where each column of the matrix becomes a factor variable. Now, some columns of the matrix have only 1's or only 0's as a result there is only 1 level for those columns in the data.frame. However it is required that each factor have 2 levels. So my solution is: m <-

I use matplot to get the density curve and then I use abline(v=g$V2, col = 3 ) to get the vertical line. Goal : I want very small lines at the bottom on the x axis , if possible in the arrow forms instead of vertical lines on the whole graph. Thanks a lot. [[alternative HTML version deleted]]

Dear List, I try to order the output of a table by the frequencies of the vector I am look at. The object I am looking at is a factor with a lot of levels that were named only once. Therefore it would be much easier to order the output by the frequencies of the levels. E.g. > levels(a) "a" "b" "c" "d" Preferred outcome: table(a) b c a d 10 5 1 1

Dear R users, I have a matrix like 85 .90 86 .89 87 .98 86 .87 88 .98 90 .78 88 .76 89 .56 90 .67 95 .67 89 .89 90 .87 91 .56 96 .87 90 .76 92.98 each pair of columns present a variable name and next the value. I have matrix with more than 500 rows and column. Now I want to convert this matrix in to. 85 .90 00 .00 00 86 .00 .89 .00 .87 87 .00 00 .98 00 88 .98 00 .76

Dear Rusers, My question is about "recode variables". First, i'd like to say something about the idea of recoding: My dataset have three variables:type,soiltem and airtem,which means grass type, soil temperature and air temperature. As we all known, the change of air temperature is greater than soil temperature,so the values in those two different temperaturemay represent different

Hello R-ologists, Imagine you have a list "list" like so: >list [[1]] [1] "IPI00776145.1" "IPI00776187.1" [[2]] [1] "Something" "IPI00807764.1" "IPI00807887.1" [[3]] [1] "IPI00807764.1" [[4]] [1] "Somethingelse" What I need to achieve is a filtered list "list2" like so: >list2 [[1]] [1]

Hi R experts, I have a data recoding problem I cant get my head around - I am not that great at the subsetting syntax. I have a dataset of longitudinal toxicity data (for multistate modelling) for which I want to also want to do a simple Kaplan-Meier curve of the time to first toxic event. The data for 2 cases presently looks like this (one with an event, the other without), with id representing

Hi I have the following array: test <- array(c(1:16), dim = c(3,4,3)) test ## I call some enries using an index array test.ind <- array(rbind(c(1,2,1), c(3,3,2)), dim = c(2,3)) test[test.ind] ## suppose I want all values in the 2nd row and 4th col over ## all three 3rd dimensions test[2,4,] how to specify a test.ind array with the last index left with ',' i.e test.ind should be

Dear All, I couldn't figure and couldn't google out how to make construct a pair of \Sexpr s or a LaTeX macro that would include 5\cdot 10^{-12} into the LaTeX output istead of 5e-12 . Any ideas? Thank you G?bor

I have some matrices stored as elements in a list that I am working with. On example is provided below as TP[[18]] > TP[[18]] level2 level1 1 2 3 4 1 79 0 0 0 2 0 0 0 0 3 0 0 0 0 4 0 0 0 0 Now, using prop.table on this gives > prop.table(TP[[18]],1) level2 level1 1 2 3 4 1 1 0 0 0 2 3

Dear UseRs, I have a very simple question. I have a big matrix (say x) including probabilities (values in (0,1)). I have to store in a list the names of the row and the column where max(x) is located. How can I proceed? Thanks in advance for your assistance! mirko

In my code, I would like to replace entries in t with entries from a random normal distribution. n<-10 > nl<-round(1.5+rexp(1,rate=2) rate=2)) > nl [1] 2 > r<-1:n > s<-sort(sample(r,nl)) > t<-match(r,s) > r [1] 1 2 3 4 5 6 7 8 9 10 > s [1] 3 8 >t [1] NA NA 1 NA NA NA NA 2 NA NA t.random<-function(x) {for(i in 1:n) ifelse(x[i]!=NA,

I am struggling with R code optimization, a recurrent topic on this list. I have three arrays, say A, B and C, all having the same number of columns. I need to compute an array D whose generic element is D[i, j, k] <- sum_n A[i, n]*B[j, n]*C[k, n] Cycling over the three indices and subsetting the columns won't do. Is there any way to implement this efficiently in R or should I resign to

On Wed, 17 Feb 2016, Hisashi T Fujinaka wrote: > And in another "oh duh" moment, I think this dumped core on two different > machines and I sent you the bt from the wrong machine. Here's the one > from NetBSD-7. > > #0 0x00007f7ff630e55a in _lwp_kill () from /usr/lib/libc.so.12 > (gdb) bt > #0 0x00007f7ff630e55a in _lwp_kill () from /usr/lib/libc.so.12 >

Hello, #I have two matrices, eg.: y <- matrix( c(20, NA, NA, 45, 50, 19, 32, 101, 10, 22, NA, NA, 80, 49, 61, 190), ncol=4 ) x <- matrix( c(20, NA, NA, NA, 50, 19, 32, 101, 10, 22, NA, NA, 80, 49, 61, 190), ncol=4 ) #Whereas x contains all NA?s from y plus some additional NA?s. #I want to find the index of these additional NA?s. I think, there must be a very

On Wed, 17 Feb 2016, Hisashi T Fujinaka wrote: > > This one is failing a test assetion - there should be some more useful > > output available from the test itself. > > I think it's this: > > test_hostkeys: > regress/unittests/hostkeys/test_iterate.c:163 test #1 "hostkeys_iterate all > with key parse" > ASSERT_INT_EQ(sshkey_load_public(

Hi, How do you get the most common row from a matrix? If I have a matrix like this array(1:3,dim=c(4,5)) [,1] [,2] [,3] [,4] [,5] [1,] 1 2 3 1 2 [2,] 2 3 1 2 3 [3,] 3 1 2 3 1 [4,] 1 2 3 1 2 in which rows 1 and 4 are similar, I want to find that vector c (1,2,3,1,2). Atte Tenkanen University of Turku, Finland