Displaying 20 results from an estimated 1000 matches similar to: "Looking for simpler solution to probabilistic question"
2002 Nov 26
1
Reshape by multiple variables
Dear list
I'm using the reshape command and want to reshape a wide data set to a
long one
e.g. I have the variables y1,y2,y3,age1,age2,age3,sex,ethnic
I want my new long data set to consist of the variables y (which has
been created from y1,y2,y3), age (which has been created from
age1,age2,age3), sex and ethnic
I have tried to use the command:
2008 May 12
1
Standard error of combination of parameter estimates
Hi,
Is there a simple command for computing the standard error of a
combination of parameter estimates in a GLM?
For example:
riskdata$age1 <- riskdata$age
riskdata$age2 <- ifelse(riskdata$age<67,0,riskdata$age-67)
model <- glm(death~age1+age2+ldl,
data=riskdata,family=binomial(link=logit))
And we want to find the standard error of the partial linear predictor
for
2008 Nov 06
3
unlist & dataframes
Dear all,
I would like to know whether it is possible to unlist elements and keep the
original format of the data.
To make it more clear, let me give an exemple:
I have a list l of dataframes that I created with apply but which looks like
this:
x1=data.frame(Name=LETTERS[1:2],Age=1:2)
x2=data.frame(Name=LETTERS[3:4],Age=3:4)
l=list(x1,x2)
l
[[1]]
Name Age
1 A 1
2 B 2
[[2]]
Name
2005 Aug 12
2
coercing created variables into a new data frame using na.omit()
Hi,
I am an R newbie and one thing I am having trouble with binding variables that
I have created within one data frame into a new data frame when using
na.omit(). To illustrate this problem I will give the example I am working on
and the approah I have been using:-
data.frame1<-filepath....
attach(data.frame1)
#create a new variable using a function
new.variable<-rep(1,length(weight3))
2011 Oct 05
1
calling a variable which in turn calls many more variables
Hi all,
I am running regressions with many covariates, most of which remain the same
each time (control variables). Instead of writing 30 demographic variables
every regression, is there a way I could call them all at once using a
variable called, perhaps "demog"?
I have tried:
> demog <- list(age1, age2, age3) but I get an error when I try to call a
list in a regression.
I also
2007 Mar 05
1
Matrix/dataframe indexing
Hi all,
I am hoping someone can help me out with this:
If I have dataframe of years and ages and the first column and first row
are filled with leading values:
Df<- age1 age2 age3
Yr1 1 0.4 0.16
Yr2 1.5 0 0
Yr3 0.9 0 0
Yr4 1 0 0
Yr5 1.2 0 0
Yr6 1.4 0 0
Yr7 0.8 0 0
Yr8 0.6 0 0
Yr9 1.1 0 0
Now the rest of the cells need to be filled according to the previous
year and age
2003 Dec 17
5
beginner programming question
Hi all,
The last e-mails about beginners gave me the courage to post a question;
from a beginner's perspective, there are a lot of questions that I'm
tempted to ask. But I'm trying to find the answers either in the
documentation, either in the about 15 free books I have, either in the
help archives (I often found many similar questions posted in the past).
Being an (still actual)
2010 Sep 12
3
reshape matrix entities to columns
Greeting R helpers J
I am not familiar with R but I have to use it to analyze data set that I have
(30,000 20,000)
I want to change the structure of the dataset and I am wondering how that might
be possible in R
A main data looks like this: some entities are empty
Age No. Age No. Age No.
Center1 5 2 8
7
2008 Aug 21
1
Interpreting Logistic Regression
Hi !
This is Madhavi from Mumbai, India. Incidently this is my first post.
I am working on Credit Scoring Model and using R, I have run the logistic regression. I have received following Output.
I have two questions
(a) What is the significance of "family = binomial(link = logit)". Why do I have to mention Binomial? Is it because my dependent variable assumes only two values 0 and 1?
2007 Nov 02
3
writing a categorical var. with condition
Hello,
I want to create a new variable which includes 4 age categories in this way:
if (age>=12 && age<32) age1==1
if (age>=32 && age<52) age1==2
if (age>=52 && age<72) age1==3
if (age>=72 && age<100) age1==4
but I get the results only for the first observation.
how can I apply this condition to all observations?
Thanks in advance,
2010 Feb 11
1
Rounding multinomial proportions
I present you with a function that solves a problem that has bugged me for
many years. I think the problem may be general enough to at least consider
adding this function, or a revamped version of it, to the 'stats' package,
with the other multinomial functions reside.
I'm using R to export data to text files, which are input data for an
external model written in C++. Parts of the
2007 Feb 09
2
LM Model
Dear R-Users,
How can I put a pre-defined regression model into to an object of class lm
in order to use the predict.lm function.
A simplified example:
I would normally run a regression analysis on a dataset,
> germany<-lm(RENT~AGE1, in.mi01)
> summary(germany)
Call:
lm(formula = RENT ~ AGE1, data = in.mi01)
Residuals:
Min 1Q Median 3Q Max
2006 May 27
1
Trouble passing list or non-list to function using ...
Hello,
Simply put, I'm trying to call a function "testme" with value "age=NA". I wish to use "dotlist<-list(...)" inside the function and have dotlist become:
$age
[1] NA
I'm modifying existing code and need to minimize changing that code so it's easiest to conform
how I call the existing function.
My sample code fragment, results, and R.version
2018 Feb 16
0
analysis of covariance and constrained parameters
Consider an analysis of covariance involving age and cohort. The goal is
to assess whether the influence of cohort
depends upon the age. The simplest case involves data as follows
value Age Cohort
x1 ????? 1?????? 3
x2?????? 1?????? 4
x3?????? 1?????? 5
x4 ????? 2 ????? 3
x5 ????? 2 ????? 4
x6 ????? 2 ????? 5
etc.
Age is a factor. The numeric response variable is value and Cohort is a
2009 Sep 21
2
cox memory
Hi there,
I have a rather large data set and perform the following cox model:
test1 <- list(tstart,tstop,death1,chemo1,radio1,horm1)
out1<-coxph( Surv(tstart,tstop, death1) ~ chemo1+chemo1:log(tstop+1)+horm1+horm1:log(tstop+1)+age1+grade1+grade1:log(tstop+1)+positive1+positive1:log(tstop+1)+size1+size1:log(tstop+1), test1)
out1
Up to here everything works fine (with each covariate
2006 Dec 01
1
Box Tidwell / Error Message
Dear R-Users,
I used the box.tidwell () function of the car Package.
When I used the following formula:
semi.sub.in.mi1.boxtidwell_h<-box.tidwell(RENT_LG ~ I(age+1)+I(age2+1)+X06A
+ I(X08B+1) + I(X22+1) + I(X24+1) + X31A, ~B_YEAR + C_X01 + C_X14 + C_X19 +
C_X29A +C_X21 + C_X23 + D_X12 + D_X17 + D_X18 + D_X25 + D_X27 + D_X30 +
D_X32 + D_X35, data = semi.sub.in.mi1)
everything is
2010 Feb 17
1
Ordered Logit in R
I'm trying to run an ordered logistic regression model. I've run the following code, but the output does not provide the p-values. Is there some command to include the p-values in the output.
reg2 <- polr(trade1 ~ age2 + education2 + personal2 + economy2 + partisan2 + employment2 + union2 + home2 + market2 + race2 + income2)
summary(reg2)
Re-fitting to get Hessian#
Call:
2002 Jul 11
1
nls() singular graident matrix error
R-helpers;
I used Proc Model in SAS to fit the following model to data:
proc model data = dbsmv;
a = a1*F**2;
b = b1*F + b2*T + b3*F*T;
tph2 = tph1 *((1 - exp(-a*age2)) / (1 -
exp(-a*age)))**-b;
fit tph2;
and yielded the following estimated parameters after iterations:
a1 = -0.15943, a2 = -1.8177, b1 = -0.01911, b2
2003 Apr 18
1
Help with nlme--freq weights, logit model, and more
Below you will find the output from a failed multi-level model run. I am
trying to estimate the following model:
Pr(PLFP=1)= logistic regression ->
B1_j * bm + B2_j * wm + B3_j bf + B4_j wf + B5 yrsed+ B6 age+ B7 age^2+e_ij
B1_j = G01 + G11 bmxd + d1
B2_j = G02 + G12 wmxd + d2
B3_j = G03 + G13 bfxd + d3
B4_j = G04 + G14 wfxd + d4
d1-d4 freely correlated
Note that there is no
2013 Jan 10
1
Semi Parametric Bootstrap
Greetings to you all,
I am performing a semi parametric bootstrap in R on a Gamma Distributed
data and a Binomial distributed data. The main challenge am facing is
the fact that the residual variance depends on the mean (if I am correct).
I strongly feel that the script below may be wrong due to mean-variance
relationship
#####R code#######
fit1s