similar to: Automating binning for chisq.test()

Hello, I am having problem with binning the data. I have a 50X3 matrix and I binned the data for all the 3 columns. Using table command I got the total no. of elements in a particular bin. Could you please tell me how to see that what all elements are there in a particular bin and then create a different matrix for each bin? Thanks. Regards, Sumit [[alternative HTML version deleted]]

Hi, I'm trying to setup some complicated binning with statistics and could use a little help. I've found the bin2 function from the ash package, but it doesn't do everything I need. My intention is to copy some of their code and then modify as needed. I have a vector of two columns: head(data) r1 r2 [1,] 0.03516559 0.03102128 [2,] 0.02162539 0.14847034

Using R-2.12.1 and latticeExtra-0.6-14, I would like to understand why a rootogram displaying samples from the Poisson distribution looks like I expected it, whereas a rootogram using the normal distribution does not: library(latticeExtra) rootogram(~rpois(1000, lambda = 50), dfun = function(x) dpois(x, lambda = 50)) rootogram(~rnorm(1000), dfun = function(x) dnorm(x,mean(x),sd(x))) I

before I accuse somebody to "overbill" I would like you to calculate with me: Rate: 0.0189 for calling Taiwan via NuFone Duration: 930 seconds Lets vote for the answers: 0.7269 or 0.2929 ??? bye Ronald Wiplinger

Hello, I have created two histograms with: hist2d(gps2, nbins=200, col = c("white",heat.colors(16))) Both of them have the same range and the same number of bins. Now I would like to compare them bin by bin and plot the results. Could someone please tell me how to do that. I searched the man pages and the web, but couldn't find anything. Thank you very much. Phil

Dear R - help, I am working on the Credit scorecard model. I am using the Logistic regression to arrive at the regression coefficients model. I want to use the Hosmer - Lemeshow test . In order to understand the use of R - language, I had referred the following URL       http://www.stat.sc.edu/~hitchcock/diseaseoutbreakRexample704.txt The related data 'diseaseoutbreak' is available

Peter, I thought this one was noted and fixed, but I could be wrong. R : Copyright 1999, The R Development Core Team Version 0.63.3 (March 6, 1999) .... [Previously saved workspace restored] > tabulate(1:10, 5) Process R:1 segmentation fault at Sat Apr 3 17:48:34 1999 -- (The following contact details become official on 1 May 1999, but the email

Hello, This sounds like a problem to which many solutions should exist, but I did not manage to find one. Basically, given a list of datapoints, I'd like to keep those within the X% percentile highest density. That would be equivalent to retain only points within a given line of a contour plot. Thanks to anybody who could let me know which function I could use! Best, Emmanuel

Hi, I posted a message earlier entitled "How to fit a line through the "Mountain crest" ..." I figured loess is probably the best way, but it seems that the problem is the robustness of the fit. Below I paste an example to illustrate the problem: tmp=rnorm(2000) X.background = 5+tmp; Y.background = 5+ (10*tmp+rnorm(2000)) X.specific = 3.5+3*runif(1000);

dear helplist, my student has fifty trees, numbered one to fifty, and a vector recording which tree a certain possum slept in on 12 nights. R> c [1] 3 14 17 22 26 26 17 40 43 25 46 46 R> Thus it slept in tree #3 on Monday, then tree #14 on Tues, and so on. I wish to test the null hypothesis that the animal chooses trees randomly; try R> table(c) c 3 14 17 22 25 26 40 43 46 1 1

Hola a todos, Al ejecutar el código que veis más abajo:  library(OptimalCutpoints)prediccion<-c(0.49165923,0.52759793,0.30213400,0.33468349,0.14979703,0.47401846,0.52216404,0.42018794,0.92168073,0.76893929,0.83362668,0.38251162,0.70803701,0.49165923,0.94462558) real<-c(0,1,0,0,0,0,1,1,1,1,1,0,1,0,1)datos_OPTIMO<-cbind(prediccion,real) cutpoint1 <- optimal.cutpoints(X =

Hi, I'm wondering how can I change the position of xlab in truehist. For example, the following code creats a histogram with 4 bins for my discrete data. I want each bin to be labelled as 0, 1, 2, or 3 in the middle, so that it's clear each bin corresponds to each of the discrete case. I was thinking of first delete xlab and then add marks myself, but it doesn't look like it's

Hi David/Galina, FYI, I found one big reason why self-hosting bots fail long after the offending commit is tested: dirty builds. In a dirty build (no make clean), when a file X is changed that breaks file Y, the bot will only accuse the failure when file Y is changed, too, so that stage1 with modified X will compile file Y, and break. At hindsight, it's obvious. But I hadn't connected

Hi, I'd like to ask you a question again. It is basically about data frames, NAs and tabulate function. I have this data frame. I already used this in one of the previous questions of mine. It intentionally looks this simple, my real 'df' dataframe is much bigger actually and again, I am not willing to annoy anyone with huge databases... So, my database: id

Hi all, I have a question about apply function. Is that possible to pass some non-default arguments in the function we want to apply ? For example: if "mat" is a matrix and I want to use the "tabulate" function on its row. The command apply(mat,1,tabulate) works but I have problem with this one apply(mat, 1, tabulate(nbins=4)). Any clue ? Thanks, Eric -- Eric

I have subscribed to this list for about a month now. I am just a MarkDown user; new to it. Using it within *Ema Personal Wiki & Epistle* for Android. I am not trying to implement this cool little light language into an app I am developing; maybe someday. I signed up because I thought I might get some MarkDown use tips. *I have learned nothing from this list.* I have witnessed a lot of

tabulate has .C("R_tabulate", as.integer(bin), as.integer(length(bin)), as.integer(nbins), ans = integer(nbins), PACKAGE="base")$ans The implementation of R_tabulate has if(x[i] != R_NaInt && x[i] > 0 && x[i] <= *nbin) and so copes with (silently drops) NA. Perhaps the .C could have NAOK=TRUE? This is useful in apply'ing tabulate to

Dear R-wizards, I'm trying to plot "binned scatterplots", or 2d histograms, if you wish, for a number of groups by using the lattice functionality it works fine for one group at a time, and probably I could find a work-around, but I prefer to do it the elegant way here's an example of what I want, what I tried and where it goes wrong: require(gregmisc) require(lattice) #toy

I am trying to do binning on three variables (3d binning). The bin boundaries are specified by the user separately for each variable. I used the bin2 function in the 'ash' package for 2d binning that involves only two variables but didn't any package for similar binning with three variables. Are there any packages or codes available for 3d binning?? Thank you. -- View this message in

On Nov 9, 2015, at 11:42 AM, David Blaikie via llvm-dev <llvm-dev at lists.llvm.org> wrote: > > > On Mon, Nov 9, 2015 at 4:32 AM, Renato Golin <renato.golin at linaro.org <mailto:renato.golin at linaro.org>> wrote: > Hi David/Galina, > > FYI, I found one big reason why self-hosting bots fail long after the > offending commit is tested: dirty builds. >