similar to: legend/plotmath/substitute problem

Displaying 20 results from an estimated 4000 matches similar to: "legend/plotmath/substitute problem"

2008 Dec 10
2
how to merge panel data stored by variable?
Hi, I have two datasets stored in tab-separated format in the following way file1: country year1 year2 Germany var1 var1 Hungary var1 var1 file2: country year1 year2 Germany var2 var2 Hungary var2 var2 I can easily read in these files, but how can I merge them as a panel dataset? Thanks, Viktor
2010 Aug 24
2
chisq.test on samples of different lengths
Hello, I am trying to see whether there has been a significant difference in whether people experienced damages from wildlife in two different years. I therefore have two columns: year 1: yes no no no yes yes no year 2: no yes no yes I wanted to do a chisq.test, but if I enter it this way: chisq.test(year1, year2) I get the error saying the columns are two different lengths. So then I tried
2010 Jan 30
2
drawing a line that shifts from solid to broken
I am graphing longitudinal data from three time points. I'd like to draw a solid line from point 1 to point 2, and then a dashed line from point 2 to point 3. It works if I do it in two steps: > first.vector <- c(mean(year1$variable1), mean(year2$variable1)) > second.vector <- c(NA, mean(year2$variable1), mean(year3$variable1)) > plot(first.vector, type="b",
2006 Aug 24
1
Using a 'for' loop : there should be a better way in R
I need to apply a yearly inflation factor to some wages and supply some simple sums by work category. I have gone at it with a brute force "for" loop approach which seems okay as it is a small dataset. It looks a bit inelegant and given all the warnings in the Intro to R, etc, about using loops I wondered if anyone could suggest something a bit simpler or more efficent? Example:
2012 Jun 24
2
Defining multiple variables in a loop
Good day, For lack of a better solution (or perhaps I am ignorant to something more elegant), I have been bootstrapping panel data by hand so to speak and I would like to know if there is a way to define multiple variables in a loop using the loop variable. I found a post (here: https://stat.ethz.ch/pipermail/r-help/2002-October/026305.html ) that discussed naming multiple variables but it
2013 Apr 03
1
linear model coefficients by year and industry, fitted values, residuals, panel data
Hi R-helpers, My real data is a panel (unbalanced and with gaps in years) of thousands of firms, by year and industry, and with financial information (variables X, Y, Z, for example), the number of firms by year and industry is not always equal, the number of years by industry is not always equal. #reproducible example firm1<-sort(rep(1:10,5),decreasing=F) year1<-rep(2000:2004,10)
2007 Jun 29
1
Assign name to a name
I would like to know how I can assign a name to a name. I have a dataset that has different years in it. I am writing scripts using R and I would like to give a month a generic name and then use the generic name to do different analysis. The reason for the generic name would be so that I only have to change one thing if I wanted to change the year. For example. Year1 = 1999 datayear <-
2010 Aug 20
1
Shifting of Principal amount while calculating Present Value
Dear R Helpers I have following data - cash_flow = c(7, 7, 107)  # 107 = Principle 100 + interest of 7% t = c(1,2,3) and zero rate table as rating         year1           year2           year3 AAA            3.60            4.17              4.73 AA              3.65            4.22              4.78 A                 3.72           4.32              4.93 BBB            4.10           
2011 Dec 01
0
Error message: object 'A' not found
I ran the following code: And I run into problems with the last line of code (when it says hn<-......). I keep getting an error code: Error in distsamp(~hab ~ 1, peldist, keyfun = "halfnorm", output = "density", : object 'A' not found I would appreciate any and all help. rm(list=ls(all=TRUE)) #clear the computer's
2010 Feb 24
1
Remove missing observations
Hi everyone I have the following problem: My dataframe has 3 variables: ID, Year and and an outcome variable. The dataframe contains repeated measurements because the subjects filled out a questionnaire every year. The time span covers 2 years. Now I want to check if there is a significant change in the outcome over the 2 years with a paired wilcox.test. The problem: Not every subject
2013 Jun 07
4
matched samples, dataframe, panel data
I R-helpers #I have a data panel of thousands of firms, by year and industry and #one dummy variable that separates the firms in two categories: 1 if the firm have an auditor; 0 if not #and another variable the represents the firm dimension (total assets in thousand of euros) #I need to create two separated samples with the same number os firms where #one firm in the first have a corresponding
2012 May 24
1
svychisq using two frames
Hello, I?m hoping you have a few minutes to help out someone very new to R. I?ve done some searching, but cannot find this particular issue. I have survey data from two different time periods (years). Both years are stratified samples and have the same variables (and variable names), but are different people in the community answering in the different years. Everything loads into the survey
2008 Oct 12
0
false convergence (8) after removal of the two-way interaction
Dear All, I am working with a generalized linear mixed-effects model with poisson error using the lme4 package in R. I created a model with the lmer function including some main effects, three two way interactions and two random effects. The model works well, but I have troubles when removing on of the two-way interactions. The Warning message: "In mer_finalize(ans) : false convergence
2009 Mar 24
3
Annoucing Citrix Project Satori
Citrix Project Satori is the result of a collaborative agreement between XenSource and Microsoft, and was carried forward after XenSource was acquired by Citrix Systems. The base Satori components are released by Microsoft as the Linux Integration Components for Hyper-V, and provide support for paravirtualized XenLinux guests running on Hyper-V. The Linux Integration Components can be downloaded
2009 Mar 24
3
Annoucing Citrix Project Satori
Citrix Project Satori is the result of a collaborative agreement between XenSource and Microsoft, and was carried forward after XenSource was acquired by Citrix Systems. The base Satori components are released by Microsoft as the Linux Integration Components for Hyper-V, and provide support for paravirtualized XenLinux guests running on Hyper-V. The Linux Integration Components can be downloaded
2009 Mar 24
3
Annoucing Citrix Project Satori
Citrix Project Satori is the result of a collaborative agreement between XenSource and Microsoft, and was carried forward after XenSource was acquired by Citrix Systems. The base Satori components are released by Microsoft as the Linux Integration Components for Hyper-V, and provide support for paravirtualized XenLinux guests running on Hyper-V. The Linux Integration Components can be downloaded
2011 Aug 03
1
Need help with xyplot
Consider I have the following data: AgeRange AgeOfPerson PersonNo FriendsAtYear0 FriendsAtYear1 FriendsAtYear2 FriendsAtYear3 FriendsAtYear4 FriendsAtYear5 10 - 12 11 1 0 1 2 2 3 3 10 - 12 12 2 0 1 2 2 3 3 15 - 18 13 3 1 2 3 4 6 7 15 - 18 14 4 1 3 4 5 7 7 30 - 40 33 5 3 5 5 6 8 9 30 - 40 36 6 4 4 4 4 4 4 I want to plot the number of friends against number of years, as to show how friendships
2011 Jul 27
2
for loop help
I am having a hard time putting the below into a loop, where it pulls out ppt from all he stations I have versus having to go through and hard code the data to the specific stations. I tried stnID <- stnid[which(duplicated(stnid)==FALSE)] for(i in 1:length(stnID)) { ppt[i] <- ppt[which(stnid==[i])] } but it doesn't like to use the which function inside a for loop? Any idea's here is
2003 Nov 17
1
Generalized linear model
Hi all! I am fitting a Poisson model, using the following command: > fit2<-glm(canc~id1+year1+time+lnpa,family=poisson) where 'id1', 'year1' and 'time' are factors. I defined them with: > id1<-C(factor(id1), treatment) and 'lnpa' is a continuous variable. The 'summary' function gives me all the effects estimates, that is, for id1, I
2004 Oct 23
1
Legend/Substitute/Plotmath problem
Hello, I seem unable to construct a legend which contains a substitution as well as math symbols. I'm trying to do the following: strain2 <- "YJG48" legend.txt <- c( substitute( strain * %==% * "YJG45, rpn10" * %Delta%, list(strain=strain2) ), "Verhulst/Logistic", "Malthus" ) legend( 100,2.5, legend.txt, cex=0.75,