similar to: better define: matrix comparison and cbind issue

Hello, I'm doing some scripting and I've noticed that R doesn't seem to have an if (cond){ do }ifelse (cond) { do } else { do } type block. Is this correct or am I missing something. THX Paul -- Research Technician Mass Spectrometry o The / o Scripps \ o Research / o Institute

Dear All, I have a matrix with data that is not organised. I would like to go through this and extract it. Each feature has 2 vectors which express the data. I also have an index of the places where the data should be cut. eg. >class(cc) "matrix" >cc [,1] [,2] [1,] 1 26 [2,] 2 27 [3,] 3 28 [4,] 4 29 [5,] 5 30 [6,] 6 31 [7,] 7 32

Hello, I apologise if someone has already answered this but I searched and googled but didn't find anything. I have a matrix which gives me the similarity of each item to each other. I would like to turn this matrix into something like what they have in the graph package with the nodes and edges. http://cran.r-project.org/doc/packages/graph.pdf . However I cannot find a method to

Hello, I hope this doesn't turn into a statistics question but here I go. I am using the nls function with a Gaussian distribution, see coding below. When I run the nls I get an error back saying that I have a linear gradient. I then, of course am unable to do anything else. The data that I am using are intensity values from some mass spectrometry data. Is there something I can

Hello all and thank you, I will try to make this as clear as I can. I have a matrix, at the top of the matrix are 4 time points, the first col describes the sample, then under each time point I have the intensity values of that sample. So : Samples 0 10 30 120 <- time A 200 300 400 1000 <- data B 100 400 200 100 C 500 400 200 1000 ^ | samples I would like to plot these however, all I

Dear all, Thank you for any help. I have a data.frame and would like to plot it in 3D. I have tried wireframe() and cloud(), I got scatterplot3d(xs) Error: could not find function "scatterplot3d" > wireframe(xs) Error in wireframe(xs) : no applicable method for "wireframe" > persp(x=x, y=y, z=xs) Error in persp.default(x = x, y = y, z = xs) : (list)

hello all, Quick question, how do I get the p value out of the anova? Thanks, Paul > pb<-aov(as.numeric(diff[5,16:33]) ~ grF) > summary(pb) Df Sum Sq Mean Sq F value Pr(>F) grF 3 2.7860e+10 9.2867e+09 4.2236 0.02534 * Residuals 14 3.0783e+10 2.1988e+09 --- Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 '

Hello all, I know this is a pretty easy question but I can't find it in S poetry or R help. How can I make a negative number positive. Such as -5 to be +5 I tried +(-5), but that didn't work. So no, I don't mean taking a -5^2 just to get a positive number. This is in a function so it's not just -5 it's x. :) Thanks, Paul -- Research Technician Mass Spectrometry o The

Thanks again everyone, I have a problem trying to install RMySQL on Suse 10.0. I have used both the install.packages() and the 'R CMD INSTALL RMySQL..." neither worked. I get the error message telling me that it cannot find mysql. So I have set the flags using export PKG_CPPFLAGS="-I</usr/bin/>" export PKG_LIBS="-L</usr/lib/mysql>" After that I run R

Hello, This should be a fairly simple question. I have 2 matrix's and I want to get the difference between them and then remove the difference from one of them. So A vs B, anything I see in B I want to remove from A, and then print out the final matrix. I have some code here but at the moment I'm getting stuck on the creating a matrix, cbind problems. clean <- function (A, B,

Umm sorry to bother everyone again but I'm having trouble with my if statement. I come from a perl background so that's probably my problem! :) So here is my code: if (any(lgAB>4) | any(lgAB<-4)){ freq_AB<-hist(lgAB, type="o", plot=F) else freq_AB<-hist(lgAB, breaks=br,type ="o", plot=F) } And I get > source("E:/R/GMDA-1.1.R") Error in

Hello all, I consider myself pretty new to the whole OO based programming so I'm sorry if I'm doing something stupid. > xml<-read.metlin(url) Error in function (classes, fdef, mtable) : unable to find an inherited method for function "read.metlin", for signature "url" >read.metlin standardGeneric for "read.metlin" defined from package

Dear all, Just a quick one, hopefully. I have a histogram made from the method 'hist()'. How do I get labels on the bars? Such that the bars will have the x axis on the bar, not the frequency of the point but the number of the point itself. To make a quick summary, I want the the numbers from 'losses' (below) to be on the bar's. Thanks, Paul

So thanks for the help, I have a matrix (AB) which in the first column has my bin numbers so -4 - +4 in 0.1 bin units. Then I have in the second column the frequency from some data. I have plotted them and they look roughly Gaussian. So I want to fit them/ find/optimize "mu", "sigma", and "A". So I call the nls function : nls_AB <- nls(x ~ (A/sig*sqrt(2*pi))*

Hello everyone, I have an overlay plot it's nice but you can't see all the data. I would like to know if there is a way to get a plot that gives a side by side plot so that each plot would be next to each other. The two plots have the same data are of different species. At the moment this is the code I'm using: exp<-cbind(abs(round(rnorm(10),2)*10), seq(100, 200, by=10))

Hello all, I'm looking for a way to be able to read a text file into R. It's a csv file but when I do "txt <-read.table("F00.csv", header=T, sep=",")" It doesn't read the file properly, and I only get 2 columns. If I open it up in OOc or Excel it open right with 7 columns. What I would really like to do is read the file as text and then split it and

Hello R users -- If I have a dataframe such as the following, named "frame" with the columns intended to be named col1 through col6, > frame col1 col2 cmlo3 col4 col5 col6 [1,] 3 10 2 6 5 7 [2,] 6 8 4 10 7 1 [3,] 7 5 1 3 1 8 [4,] 10 6 5 4 9 2 and I want to correct or otherwise change the

Dear all, I have a dataframe which looks like this (dummy): date<-c("jan", "feb", "mar", "apr", "may", "june", "july", "aug","sep","oct","nov","dec") col1<-c(8.2,5.4,4.3,4.1,3.1,2.5,1.1,4.5,3.2,1.9,7.8,6.5) col2<-c(3.1,2.3,4.7,6.9,7.5,1.1,3.6,8.5,7.5,2.5,4.1,2.3)

Hi all, It seems like I cannot use normal 'if' for data frames. What would be the best way to do the following. if data$col1='high' data$col2='H' else if data$col1='Neutral' data$col2='N' else if data$col='low' data$col2='L' else #chuch a warning? Note that col2 was not an existing column and was newly assigned for this

Hi all, I put up an exhaustive model to use R's "step" function: ------------------------ mygam=gam(col1 ~ 1 + col2 + col3 + col4 + col2 ^ 2 + col3 ^ 2 + col4 ^ 2 + col2 ^ 3 + col3 ^ 3 + col4 ^ 3 + s(col2, 1) + s(col3, 1) + s(col4, 1) + s(col2, 2) + s(col3, 2) + s(col4, 2) + s(col2, 3) + s(col3, 3) + s(col4, 3) + s(col2, 4) + s(col3, 4) + s(col4, 4) + s(col2, 5) + s(col3,