similar to: hours() in 'chron': output != input

Displaying 20 results from an estimated 10000 matches similar to: "hours() in 'chron': output != input"

2008 Aug 01
1
chron objects: input/output
Hi list, I have some questions regarding 1) conversion of date + time characters to chron 2) formatting chron object printing Regarding (1), Gabor's Rnews 2004 4/1 article has been indispensible, but I often work with files where dates and times are contained in a single field. In this case, I would like to control input/output of chron objects when each observation of date and time is
2011 Jul 28
3
how to shift a chron timestamp by 6:30 hours
Dear help list, I have a timestamp in as a chron object: > (x <- chron(dates = c("12/02/11", "22/11/11"), + times = c("07:30:00", "04:00:00"), + format = c(dates = "d/m/y", times = "h:m:s"))) [1] (12/02/11 07:30:00) (22/11/11 04:00:00) Now I want to shift the timestamp by 06:30 (hh:mm) backwards, to get
2010 Dec 09
1
Bivariate kernel density bandwidth selection
I've been trying to implement bivariate kernel density estimation. For data like mine, function "kde" from package "ks" with bandwidth matrix derived by function "Hscv" seems like a very good choice. Unfortunately, Hscv seems unmanageably slow except for very small sample sizes (up to a few hundred) and my sample sizes are quite large (up to a few thousand).
2011 Aug 30
3
having trouble extracting week from chron object
Running R 2.13.1 on Windows XP. I would like to get week of the year (1-52) for each date. library(chron) dts <- dates(c("02/27/92", "02/27/92", "01/14/92","02/28/92", "02/01/92")) dts dts.chron <- as.chron(dts) dts.chron class(dts.chron) # all of these component extractions work: months(dts.chron) weekdays(dts.chron) years(dts.chron)
2002 Oct 18
1
Chron problem with R 1.6.0 (PR#2181)
Full_Name: Rick Bilonick Version: 1.6.0 OS: Linux (RH 7.1) Submission from: (NULL) (12.4.226.1) Hi. I'm using Red Hat 7.1 Linux (Intel 586). I installed the 1.6.0 rpm. No problems were reported. When I tried to load the chron library: Error in dyn.load(x, as.logical(local), as.logical(now)) : unable to load shared library "/usr/lib/R/library/chron/libs/chron.so":
2012 Jun 15
2
time zones and the chron to POSIXct conversion
Hey R folks, i found some strange (to me) behaviour with chron to POSIXct conversion. The two lines of code result in two different results, on ewith the correct time zone, one without: library(chron) as.POSIXct(chron('12/12/2000'), tz = 'UTC') as.POSIXlt(chron('12/12/2000'), tz = 'UTC') Only the code below would give me a POSIXct object with the correct time
2005 Jun 01
2
problem with chron scales in lattice
I can't get the scales parameter in xyplot of lattice to work as I expected. I'm using R-2.1.0 and lattice 0.11-8. There should be year labels from 1992 to 2004 for the x axis in the plot below, but instead only a few of them appear, and in the wrong spots, as if the coordinate system has changed after finishing with the panel function. library(chron) library(lattice) # vertical grid
2005 Nov 16
1
COM dates (was origin and "origin<-" in chron)
I was just looking for an easy way to convert between COM datetime and chron datetime (both ways.) I found examples on the list, but they involved origin. Does anyone have functions for converting COM datetime <-> chron datetimethat work "safely"? David L. Reiner > -----Original Message----- > From: Gabor Grothendieck [mailto:ggrothendieck@gmail.com] >
2011 Sep 16
1
Mystified - comparing chron times
I have two local variables: startTime and expectedStartTime. Both are chron related objects. When I look at the class for the objects I can see they are of class "times". When I print them to the console, they both read: "09:30:00" When I print them as.numeric(), they both read: 0.3958333 When I try and compare them: (as.numeric(startTime) == as.numeric(expectedStartTime)) it
2012 Nov 27
2
Some questions about chron package..
Hello, I have questions while reviewing "chron" package(e.g.,chron.R). 1. What is the differences between 3 kinds of function definition ? 1) "name" &lt;- function(... 2) 'name' &lt;- function(... 3) name &lt;- function(... Do you know Why author used various kinds of definitions ? Is there no functional differences between them ? 2. I
2006 Nov 20
1
a little help needed plotting chron object
Hello there, Using R 2.4.0 on Solaris (Unix): I am trying to control the X axis range on a simple time of day plot. I made a test program (below) that gets file time stamp information from the files in the directory where R starts. The goal of the test program is to plot the time of day of file creation on an x axis that spans a user-specified range (like 12:00:00 to 15:00:00). If I allow
2006 Jul 14
2
chron vs. POSIX
Hi, One of the big decisions when writing code is how to handle dates and times. Gabor Grothendieck provided an excellent overview of the issue in his R News 4/1 (2004) article, and many users and developers are probably using it as a guide. The proposed guideline is to use the simplest class required; as Gabor put it "use Date if possible, otherwise use chron, and otherwise use
2008 Dec 09
1
chron - when seconds data not included
I have date and time data which looks like this: [,1] [,2] [1,] "7/1/08" "9:19" [2,] "7/1/08" "9:58" [3,] "7/7/08" "15:47" [4,] "7/8/08" "10:03" [5,] "7/8/08" "10:32" [6,] "7/8/08" "15:22" [7,] "7/8/08" "15:27" [8,] "7/8/08"
2000 Feb 16
1
chron and mysql
R 0.90.1 chron 2.2-2 MySQL 3.22.30 Attempts to create a chron object fail when using date and time data from a mysql database. It appears that chron does not like 4 digit years. Is this the problem? my data look like: > c.time[1:10,] Date Time 1 2000-02-14 10:15:02 2 2000-02-14 10:17:03 3 2000-02-14 10:18:03 4 2000-02-14 10:19:03 5 2000-02-14 10:20:04 6 2000-02-14
2006 Jun 23
2
problem with hist() for 'times' objects from 'chron' package
Hello dear useRs and wizaRds, I encountered the following problem using the hist() method for the 'times' classes from package 'chron'. You should be able to recreate it using the code: library(chron) # pasted from chron help file (?chron) dts <- dates(c("02/27/92", "02/27/92", "01/14/92", "02/28/92", "02/01/92")) class(dts)
2013 May 01
3
Chron format question h:m not working
R 2.12.2 on Scientific Linux 6.4 #works chron(times.="15:00:00", format=c(times="h:m:s")) #doesn't work chron(times.="15:00", format=c(times="h:m")) From chron Manual: The times format can be any permutation of "h", "m", and "s" separated by any one non-special character. The default is "h:m:s". what am I
2005 May 17
2
cumsum on chron objects
Hi, Is there some alternative to cumsum for chron objects? I have data frames that contain some chron objects that look like this: DateTime 13/10/03 12:30:35 NA NA NA 15/10/03 16:30:05 NA NA ... and I've been trying to replace the NA's so that a date/time sequence is created starting with the preceding available value. Because the number of rows with NA's following each available
2005 Aug 02
1
cut.Date functionality for chron date/time objects
Hello, I've encountered the need to cut some chron objects of the form: R> mychron <- chron(sort(runif(10, 0, 10))) R> mychron [1] (01/01/70 16:36:20) (01/02/70 00:08:46) (01/03/70 16:54:49) [4] (01/04/70 06:45:00) (01/07/70 06:21:24) (01/07/70 18:28:44) [7] (01/08/70 00:47:05) (01/08/70 05:11:44) (01/10/70 01:07:53) [10] (01/10/70 17:46:53) into arbitrary (e.g. a given number
2006 Jun 12
1
cumulative time durations of specified periods (chron)
Hi, Say we have two chron vectors representing start and end date/times of an event, respectively: R> (xfrom <- chron(seq(1.25, 11, 3.25))) [1] (01/02/70 06:00:00) (01/05/70 12:00:00) (01/08/70 18:00:00) [4] (01/12/70 00:00:00) R> (xto <- chron(as.numeric(xfrom) + seq(1.5, 2.25, 0.25))) [1] (01/03/70 18:00:00) (01/07/70 06:00:00) (01/10/70 18:00:00) [4] (01/14/70 06:00:00) and we
2012 Jun 01
1
Missing times chron
Dear all, As a novice user of R I ran into a problem that's quite hard for me to resolve. I have a database containing data of a clinical trial in which patients are included that survived or died: x <- matrix(data=c(1:5,0, "1/1/2012 00:00:00",0,0,"1/7/2012 00:00:00"), nrow=5, ncol=2, dimnames= list(NULL,c("ID", "dateofdeath"))) My file is a .csv