similar to: changing langage [SOLVED]

WinXP-x32, R-21.13.0 Dear list, I have a problem that (I think) relates to the interaction between Windows and R. I am trying to scrape a table with data on the Hawai'ian Islands, This is my code: library(XML) u <- "http://en.wikipedia.org/wiki/Hawaii" tables <- readHTMLTable(u) Islands <- tables[[5]] The output is (first set of columns):

Thank you. The line of code you give certainly resolves several of the issues. I didn't realize that font support is such a tough matter to realize. Let me express my gratitude to those who provide this for us in R. On 04-05-11, Prof Brian Ripley <ripley at stats.ox.ac.uk> wrote: Oh, please! This is about the contributed package XML, not R and not Windows. Some of

Hi, I'd like to know if there is an equivalent for #ifdef (Clangage) in R. I 'd like to do something like: useDebug = defmacro(DEBUG, expr=(DEBUG==1)) if(useDebug(0)){ #Here I do not use debug mode make_addition = function(a, b) { c=a+b plot(c) return(c) } }else{ #here I use debug mode c=a+b } I assume this would work... The problem is : if

In the latest windows binary (2007-04-03 r41023) pdf() with an argument paper="a4" gives an error, this was still ok in (2007-03-18 r40854) Jan Oosting > pdf("test.pdf",paper="a4") Error in pdf("test.pdf", paper = "a4") : invalid paper type 'a4' (pdf) > sessionInfo() R version 2.5.0 alpha (2007-04-03 r41023) i386-pc-mingw32

Dear R-users, For a data frame (say in this example X) I want to look up the corresponding value in a 'look-up data frame' (in this example Y). The for-loop works but is very time-consuming because 'X' in reality is very big. Therefore I would like to have a solution with apply. However, I do not succeed. Any suggestions? Thanks in advance, Hanneke

I use 2 packages that both implement a S4 plot method, where one package depends on the other (the bioconductor package globaltest which depends on multtest). When the plot method is used from within the package, it seems the default plot method is used, and an error is generated. When the method is invoked from the console, the plot is created correctly. I have reproduced this with 2 small

Dear all, I've been getting different results from the sparse and dense version of model.Matrix when used with sparse contrasts and interactions between factors. The same happens when using model.matrix and sparse.model.matrix. When calculating list.contrasts I get the same results for sparse and dense contrasts (except the type of the matrix is different of course). However, when I use these

bonjour, je vous écris pour savoir si vous aviez trouver réponse pour l'écriture du test de Newman & Keuls sous R car j'en ai aussi besoin merci encore cordialement. --------------------------------- [[alternative HTML version deleted]]

See library(multcomp) and ?glht ?contrMat for several procedures for multiple comparisons. The Newman Keuls test is not on the list. The related Tukey method is on the list.

Hola a todos: La pregunta ha quedado clara en el asunto, pero: ¿existe alguna función que convierta un objeto temporal (TS) a matriz o data.frame? En algunos cálculos que estoy haciendo me viene bien convertir un objeto temporal a matriz para poder hacer cálculos parciales por meses o años (aplicando apply en la matriz) pero no he encontrado ninguna función que haga la conversión. He

Estimado Rubén Gómez Antolí En mi caso en particular al trabajar con fechas, me encontré con inconvenientes, algunos de ellos fueron mejorados en R, hoy estoy desactualizado, pero creo que en el siguiente lugar http://cran.r-project.org/web/views/TimeSeries.html hay referencia actualizada, esperando que en esta encuentre lo que necesite lo saludo muy atentamente. Javier Marcuzzi

Thanks for this clarification. I have learned in the meantime that it is necessary to be very careful when using all these POSIX things. As another example, here is something that made me scratch my head just yesterday: When I create a sequence of days that happens to start before and ends in daylight savings time, I seem to lose a day: > seq(from = strptime("20030329",

hi, I've troubles with some difftime objects. e.g. ISOdate(2001, 4, 26) - ISOdate(2001, 2, 26) - 2 works, telling me "Time difference of 57 days". But when I'd like to add days, such as ISOdate(2001, 4, 26) - ISOdate(2001, 2, 26) + 2 the function gives me an error. Function "as.COMDate.chron" of the Rbloomberg package doesn't work for that reason. I'm

Dear R-people! I am using R 1.8.0, under Windows XP. While using ISOdate() and strptime(), I noticed the following behaviour when "wrong" arguments (e.g., months>12) are given to these functions: > ISOdate(year=2003,month=2,day=20) #ok [1] "2003-02-20 13:00:00 Westeurop?ische Normalzeit" > ISOdate(year=2003,month=2,day=30) #wrong day, but returns a value [1]

Although the documentation is somewhat sketchy, I() can be used to create objects of class AsIs: > I("a") [1] "a" attr(,"class") [1] "AsIs" "character" > I(4) [1] 4 attr(,"class") [1] "AsIs" "numeric" > I(4 + 0i) [1] 4+0i attr(,"class") [1] "AsIs" "complex" > This

Hi Ogbos, You can just use ISOdate. If you pass more values, it will process them: ISOdate(2018,01,22) [1] "2018-01-22 12:00:00 GMT" > ISOdate(2018,01,22,18,17) [1] "2018-01-22 18:17:00 GMT" Add something like: if(is.null(data$hour),data$hour<-12 then pass data$hour as it will default to the same value as if you hadn't passed it. Jim On Mon, Jan 22, 2018 at 6:01

On Sat, 2007-04-07 at 08:40 +0200, Kurt Hornik wrote: > Dear maintainers of CRAN packages, > > This concerns the packages <snip /> > > And now keep the updates rolling in ... Dear R Developers, I was recently emailed by the CRAN maintainers about warnings for my two packages, analog and cocorresp, that are on CRAN. I have built both packages (the versions on CRAN plus

Hola, Si no te entiendo mal, necesitas la conversión a matriz como paso intermedio para agregar por meses (o cualquier unidad temporal). Si es así, te aconsejo que uses el paquete zoo y el método aggregate para la clase zoo. Por ejemplo: library(zoo) dats <- data.frame(date=seq(as.Date('2012-01-01'), by='day', length=3*365), A=rnorm(3*365),

In today's pre1.5.0 > ISOdate(2002,1,1) [1] "2002-03-01 04:00:00 PST" > ISOdate(2002,1,1)==ISOdate(2002,3,1) [1] TRUE It doesn't seem to happen for days other than 1/1 -thomas > version _ platform i686-pc-linux-gnu arch i686 os linux-gnu system i686, linux-gnu status Under development (unstable) major 1 minor 5.0 year 2002 month

Hi, Given a date, how do I get the last date of that month? I have data in the form YYYYMM, that I've read as a date using > x$Date <- as.Date(ISOdate(substr(x$YearEnd,1,4),substr(x$YearEnd,5,6),1)) But this gives the first day of the month. To get the last day of the month, I tried > as.Date(as.yearmon(x$Date,frac=0)) But I don't get the last day of the month here. (Tried