similar to: about colnames

Hello sir: There are 2 questions about string. 1 How to calculate the width of a string? e.g string "abc"'s width is 3; 2 How can I get the "substring" in such kind of condition: "f:\\JPCS_signal.txt" "f:\\PC1_signal.txt" "f:\\PC2_signal.txt" What I wanna get is "JPCS" "PC1" "PC2".How can I achieve them by R

Hello sir: group1:1,2,3,4 group2:1,3,4,5 group3:2,4,8,9 .. ... group1000:9,3,8,2 I wanna get the "intersection set" and "union set". I've tried command "setdiff"and "union",but only two groups is permited.How can I deal with multi groups to find the "intersection set" and "union set"? Thanks a lot! My best

Hi all: I wanna know how to expoort ".xls" file. And in the exported ".xls" file, how to set different cells with different color? Thanks a lot! My best. ------------------------------ ******************************************* Xin Meng Capitalbio Corporation National Engineering Research Center for Beijing Biochip Technology BioPharma-informatics & Software

Hello sir: I use Rcmd to execute R code,such as : "C:\\Program Files\\R\\R-2.2.1\\bin\\Rcmd.exe" BATCH globalLowessRun.r globalLowessRun.r is a R function written by myself. But I wanna make the "globalLowessRun.r" changeable,such as globalLinearRun.r or gridbasedLowessRun.r,and so on. How can I achieve this goal via Rcmd.exe BATCH ? The only finding is: Rcmd BATCH

As to the function"pnorm",the default degree of freedom(df) is infinite. I wanna know how to set the df as I want. Help on pnorm doesn't have df setting.The only choice are:"mean, sd, lower.tail, log.p",but no df. For instance: sample size=6 df=6-1=5 t value=9.143 I wanna to the corresponding p value by using function "pnorm". How can I do it? Thanks a lot

Hello sir: Here's a question: x<-1:5 y<-c(2,1,4) I wanna get the different elements between x & y,i.e. 3,5. How can I get the result(3,5) via R function? Thanks a lot for your help. My best! ------------------------------ ******************************************* Xin Meng Capitalbio Corporation National Engineering Research Center for Beijing Biochip Technology

Hello sir: How can I perform McNemar (paired chi square test) by using R? Thanks! ------------------------------ ******************************************* Xin Meng Capitalbio Corporation National Engineering Research Center for Beijing Biochip Technology BioPharma-informatics & Software Dept. Research Engineer Tel: +86-10-80715888/80726868-6438 Fax: +86-10-80726790 Email??xmeng

Hello sir: As to the 2*2 table format for reporting results comparing a new test to true diagnosis,when I got the sensitivity and specificity,how can I calculate the exact 95% confidence intervals (based on the binomial distribution) for sensitivity and specificity via R? Thanks a lot! My best! ------------------------------ ******************************************* Xin Meng Capitalbio

Dear All, I created a script to calculate averages - two groups: "parcel" and "date" - and, based on these averages, make a graph. The problem is that 'R' does not recognize the first column even if I try to insert one. A brief example Raw data: Data <- sample(1:100, 30, replace = FALSE, prob = NULL) Date <-

Hello,sir: Here's a little question about R which needs your help.Thanks in advance. If I wanna make a sequence just like a,b,c,d (In other words,a vector consists of 4 characters :a,b,c,d ).How can I do it in a shortcut manner? Yes,I can do it as following: c("a","b","c","d") and the result is:[1] "a" "b" "c"

Hi, I want to use the value of variable to quote elements in matrix. For example, I have a matrix like:               y1   y2m1         1      2m2         3      4 where y1,y2,m1,m2 are column and row names.  I have two random character variable, say x,  that could be either  y1 or y2  and  y that could be either m1 or m2.  So can I  do like   Matrix[y,x] to quote elements?  I've tried this

Hello sir: a data with 2 columns: id x a 1 b 2 c 3 I wanna get such kind of plot: x: a b c y:1 2 3 But the plot command doesn't permit string character as x. How can I get it ? Thanks a lot ! My best

Hello, I can`t figure out how can increase the velocity of the fitting data by nls. I have a long data .csv I want to read evry time the first colunm to the other colunm and analisy with thata tools setwd("C:/dati") a<-read.table("Normalizzazione.csv", sep=",", dec=".", header=F) for (i in 1:dim(a[[2]]]) { #preparazione dati da analizzare

Hi all: My data:data(sleep) If I wanna calculate each group's extra,what I can do is: #method1 attach(sleep) mean(extra[group==1]) mean(extra[group==1]) #method2 result<-matrix(,0,2) g<-split(sleep,sleep$group) for(i in 1:length(g)) { result<-rbind(result,data.frame(unique(g[[i]]$group),mean(g[[i]]$extra))) } colnames(result)<-c("name","mean") But the above

hi all: If there's a dataframe: x y 1 a 2 b 3 c The info of the data such as : name date author The result I want is: name date author x y 1 a 2 b 3 c In other words,I wanna add the info above the dataframe. How can I do it ? Thanks a lot! My best

Hello sir: Here's the result of repeated measures ANOVA. $"Error: Within" Df Sum Sq Mean Sq F value Pr(>F) t 2 524177 262089 258.24 1.514e-06 *** Residuals 6 6089 1015 --- Signif. codes: 0 `***' 0.001 `**' 0.01 `*' 0.05 `.' 0.1 ` ' 1 My question is: How to extract the F value only? If the result is a

I have the following code: ----------------------------------------------------------------------------------------------------- result <- matrix(NA, nrow=1, ncol=5) for(i in 1:(nsnp-1)) { for(j in (i+1):nsnp){ tempsnp1 <- data.lme[,i] tempsnp2 <- data.lme[,j] fm1 <- lme(trait~sex+age+rmtemp.b+fc+tempsnp1+tempsnp2+tempsnp1*tempsnp2, random=~1|famid, na.action=na.omit) fm2 <-

Hello sir: Here's a question on covariance analysis which needs your help. There're 3 experiments,and x refers to control while y refers to experimental result. The purpose is to compare the "y" values across the 3 experiments. experiment_1: x:0.1 0.2 0.3 0.4 0.5 y:0.5 0.6 0.6 0.7 0.9 experiment_2: x:1 2 3 4 5 y:3 4 6.5 7.5 11 experiment_3: x:10 20 30 40 50 y:18 35 75 90

Hi I'm seeing some "odd" behaviour with cbind(). My code is: > cat <- read.table("cogs_category.txt", sep="\t", header=TRUE, quote=NULL, colClasses="character") > colnames(cat) [1] "Code" "Description" > is.factor(cat$Code) [1] FALSE > is.factor(cat$Description) [1] FALSE > is.factor(rainbow(nrow(cat))) [1]

Hi, I would like to add a prefix to colnames in a matrix but I can't get the prefix option in colnames to work. What am I doing wrong? > X<-matrix(NA,3,4) > colnames(X)<-c("test","test","test","test") > colnames(X)<-colnames(X,prefix="PREFIX.") > X test test test test [1,] NA NA NA NA [2,] NA NA NA NA