similar to: plot color question

I'm trying to overlay a density plot on a previously plotted histogram. However, i need to use the same axis as of the 1st(histogram) plot to plot the second. My second plot is creating its own axis and causing my plot to extend the entire histogram instead of getting a subplot on a portion of the histogram. I tried 'fig' and 'new' parameters with no luck. Thanks in advance.

Dear R users, Following some of the recent questions and discussions about the R plotting abilities, it occurred to me again that it would be very valuable to have an R graph gallery. Eric Lecoutre made a very nice example in: http://www.stat.ucl.ac.be/ISpersonnel/lecoutre/stats/fichiers/_gallery.pdf It would be very useful to many beginners, but probably also advanced users of R, to have an

I've created a perspective plot using 'persp' in the graphics package. I'd like to add a second plane of z values to the existing plot, but I cannot seem to do this using 'persp'. Is there an analogue to 'lines' or 'points' for perspectives? Corey. corey.bradshaw at cdu.edu.au

Is there a command to get cluster criterion for the cluster methods? SAS has its criterion, but I prefer to do it in R. If there is not a command is there code to produce criteria to choose the number of clusters? Adrian Katschke Statistics Grad Student University of Nebraska-Lincoln [[alternative HTML version deleted]]

Hi, I would like to bound the lower limit of my y scale to zero, and let R chose an upper limit. Something like plot(x,ylim=c(0,)) or plot(x,ylim=c(0,na)) but nither of these do the job. I searched the docs, but I can't see a way to do this. Naturally its nothing I can't do 'by hand', I would just like to know if a correct syntax exists.

Hello, I'd like to remove color bar from "filled.contour" plot. Is it possible and how? I also want to overlay "contour" plot on filled.contour but due to scaling of the "filled.contour" to account for the color bar, aspect ratio for "contour" is different from "filled.contour". Can this problem be solved? Thanks, Mark

Hi, there. Suppose I have a bivarariate data matrix y1 and y2. I want to plot a 3-D picture of the estimated density f(y1, y2) against y1 and y2? How can I do that? Do I use persp() or density()? Thanks for your help. Yulei $$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$ Yulei He 1586 Murfin Ave. Apt 37 Ann Arbor, MI 48105-3135 yuleih at umich.edu 734-647-0305(H) 734-763-0421(O) 734-763-0427(O)

Hi, I am using the Strucchange package in R to test for structural change in regression coeffcient. Given a model y = b0 + b1*X + b2*Z, the Fstats test whether there is a change in both b1 and b2 over a time period. Is there any way where I can restrict the test to hold b2 constant and test for break in only b1? That is, instead of a pure structural change, could I test for partial structural

Hi All R-helpers This is my first (but probartly not last ;-) mail to R-help, so hello to everybody. My problem: Is there a way to give colors to the labels (sample labels) in plots for a hclust object for better visualization? I have looked through plot, points, hclust and more but cannot find anything on label color. Anybody know if this is doable? Best regards Jeppe

Dear R users, I'm interested in a combination of a scatterplot and an image graph. I have two large vectors. Because in the scatterplot some areas are sparsely and others densely populated, I want to see the points, and I also want their color to be changed based on their density (similar to a heat map). Is there a function that can do that? Thank you, b.

Hello I've another question :-) I would like to transform a list to a integer. I must be sure that the number entered by the user is an integer! Thus, I've made : repeat{ cat("Effectif des populations (integer):") n<-scan("",n=1,what=list(0),quiet=TRUE) if (is.integer(n[[1]])==TRUE) break print("L'effectif des population doit etre un entier")

hi, I would like to subsample the array c(1:200) at random into ten subsamples v1,v2,...,v10. I tried with to go progressively like this: > x<-c(1:200) > v1<-sample(x,20) > y<-x[-v1] > v2<-sample(y,20) and then I want to do: >x<-y[-v2] Error: subscript out of bounds.

Hi Sorry to ask such a basic question. I have a list, each element of which is a vector of two values. What I actually want is a matrix with two columns, and one row per element of the list. Obviously I have tried as.matrix(), and as.vector() but I didn't expect the latter to work. I feel so lame asking this. Any suggestions? Mick

I understand that I need to have a (in this case) square matrix with all the data. But the question now is; - can the contourplot not interpolate the missing values or alternatively - I have fit a model to the z data (z = 100 + 0.5x + 0.5y). How can I make from this model a "square" matrix z to make a contour plot? Kind regards, Darius Blaszijk ----- Original Message ----- From:

Is there a R function for sort a data frame by a variable ? I know sort a vector, but I don't know sort a data frame by a column. Can you help me ? the sort() function don't work with data frame.

Hi how is it possible to use more than one command when i'm didn't want use R CMD BATCH for specific reason? $ echo "(x<-1:10)" | R --vanilla works $ echo "(x<-1:10 ;y<-20:30 ;lm(y ~ x))" | R --vanilla works not. Is it further possible using bash variables like $i from a loop in the bash echo call i.e. dm$x$i$k <-

Hi all: I have a question on how to go about creating a correlation matrix. I have a huge amount of data....21 variables for 3471 times. I want to see how each of the variables correlate to each other. Any help would be appreciated, including which package and which functions I should use to do this. Thanks, Jessica Higgs Masters Student Department of Meteorology Penn State University

I'm about to present a report (for internal use of governmental agency). I used extensively R , contibuted packages, as well as communications on the R-list As well as citing R, I would like to know how to cite the contributed packages (it is not so easy, as some have been used exensively, other marginally, some are called from another package and some were not used as softwares but gave me

Hello useRs and helpRs, Some time ago, in a gallaxy far away (here is the thread : http://finzi.psych.upenn.edu/R/Rhelp02a/archive/46532.html ) we discussed about a graph gallery showing the power of R in that domain. I did some work around that, and there is a (pretty advanced) draft here : http://addictedtor.free.fr/graphiques/displayGallery.php For instance, there are some of my graphs,

Dear All, is there a simple way to print a data.frame without its row.names? example: datum <- as.Date(c("2004-01-01", "2004-01-06", "2004-04-12")) content <- c('Neujahr', 'Hl 3 K.', 'Ostern') df1 <- data.frame(datum, content) print(df1) datum content 1 2004-01-01 Neujahr 2 2004-01-06 Hl 3 K. 3 2004-04-12 Ostern Can I get