similar to: Paginate with joins messing with id

Hi all, Is there a way to create pagination with a complex SQL, more complex than the :conditions option will support? I have two databases, houses and images. Houses has_many images, and each Image belongs_to house. I''m creating a search engine for the house records and I''d like to be able to filter out all the houses without any associated images. So far I''m

I''m sure I''m missing something completely obvious here, so I hope someone can point me in the right direction! I''ve implemented a basic search with AAF, which works as expected; I''m running a ferret drb server, and using will_paginate to page results. The code in my search_controller.rb: search_text = params[:query] || " " @products =

Hi Guys, I am trying to paginate the results from a search. When I use actual constants in the search conditions, it works fine: def query @k2_result_pages, @k2_results = paginate (:k2_results, :conditions => [''e_date >= ? AND e_date <= ?'', ''2006-07-12'', ''2006-08-12''],

> Unfortunately I still get the same error. Here is my code now (the > commented line works): > > def list > @upload_pages, @uploads = paginate(:uploads, :per_page => > 20, :order > => ''id'') > # @upload_pages, @uploads = paginate(:uploads, :per_page => 20) > end You may have an older version, try using the order_by clause

Why does it seem like I''m having so much trouble with this? I created a topics table, and a replies table. In my Topic model I used the following lines of code: has_many :replies has_one :first_reply, :class_name => ''Reply'', :order => "created_on" has_one :last_reply, :class_name => ''Reply'', :order => "created_on DESC"

i''ve figured out how to use the next and previous links with the paginator class but now i''m trying to figure out how to display all the page numbers in between. looking through the rails api, i found paginator.each() but i''m not sure how to use it, or if that''s even what i am looking for. also, is there a way to limit the amount of pages like some sites

Hi there, Is there a neat and easy way to implement pagination with letters rather than numbers eg : A B C D ... Z Rob

Ahoy, I checked the API and did some forum searches but didn''t find anything good on table sorting. Is there a "railish" way to do this? My current method really is lacking (i''m on like rails day 2) <th><%= link_to ''Name'', :action => ''list'', :order => ''name'' %></th>

Hello, maybe that I''m a stupid, but I don''t know how I can working with pagination. In all examples is written (for example) next: def user_list @user_pages, @users = paginate(:users, :order_by => ''name'') end So, it''s OK (as a scaffold) for all set of users. But I need a little other functionality. For example I need paginate only a little bit

I''m trying to figure out how to change the order of a list view and it''s obvious to me that I don''t understand what I get from a simple scaffold to know enough to alter it. If someone would be so kind to tell me what this means ... def list @placment_pages, @placements = paginate :placements, :per_page => 10 end @placement_pages, # I am guessing that this

Hi all, I have n independent variables A_1, A_2, A_3,......,A_n, and each with known variances var(A_1), var(A_2),..., but unknown mean. How can I get the approximation of the variance of the product of the variables using numerical computation, i.e. var(A_1*A_2*A_3*.....*A_n)? Thanks. Sincerely, Yanwei Zhang Department of Actuarial Research and Modeling Munich Re America Tel: 609-275-2176

emperors1000@aol.com wrote: > > This is being sent on behalf of emperors1000@aol.com > as part of the mailing list that you joined. > List: emperorsclothes > URL: http://www.emperors-clothes.com > ------------------------------------------------------------ > > URL for this article: http://emperors-clothes.com/interviews/dekkers.htm > > Join Emperor's Clothes

I am trying to use pagination with the order option. I am following examples I''ve seen all over the web, but I am getting an error. My code seems simple: def list @upload_pages, @uploads = paginate :uploads, :per_page => 20, :order => ''id'' end Yet I keep getting this error: ___________________________________________

because I am a grasshopper... Now that I can sort my ''list''...is there a logical way of not repeating myself to having essentially the same list view with multiple sorts? i.e. def list_cl # ordered by clients last name @placement_pages, @placements = paginate( :placements, :include => [:client], :order_by =>

I''m trying to create a paginated list that will take note of the "end_date" field in my table. This is what I have: @post_pages, @posts = paginate(:posts, :per_page => 10, :order_by => ''end_date'') in the controller. And for the view: <h1>Posts ending soon</h1> <ul><% for post in @posts do %> <strong>Post Title:

Hey all, I''m using a simple search function. It''s working great except for foreign keys. I have one table pets (id,name,owner_id) and another table people(id,name) owner_id being a foreign key of pet pointing to people name. here it is on the pet controller: @paginator, @pets= paginate(:pets, :conditions =>["name OR owner_id like

I''m playing around with Rails, and I can''t get this to work. I just can''t seem to wrap my brain around it. I''m having some trouble doing an Ajax navigation column. Here''s what I have: view layout: <div id="navigation"> <%= render(:partial => "navigation", :collection => @categories) %> </div> My

I have a controller and list page for region object. My list page has a ''name'' text input that can be used to limit the list. It works except that the paginate gets the full set of regions unqualified by my search term. I believe this full list is contained in :regions symbol which I dont seem to be allowed to modify or replace (yes I am a ruby and rails newb). How can I

Hi I''m wondering if there''s a way I can gather data from multiple tables from the child table by using the paginate method? I would have done it using select_by_sql but I need it to paginate. My table structure is: Records is a child of Date and Account Date Account | | ^ ^ Records I want to be able to print a table using the Records controller that will

There must be a better way to write this code: @project_pages, @projects= paginate :project, :per_page => 10, :conditions => ["account_id = ?", account] ?! If only I could pass the sub-collection account = ... @projects = account.project to paginate, instead of letting it extract it with a find :all + sql conditions Alain. -- Posted via