similar to: ISOdate returns incorrect date?

Dear R-people! I am using R 1.8.0, under Windows XP. While using ISOdate() and strptime(), I noticed the following behaviour when "wrong" arguments (e.g., months>12) are given to these functions: > ISOdate(year=2003,month=2,day=20) #ok [1] "2003-02-20 13:00:00 Westeurop?ische Normalzeit" > ISOdate(year=2003,month=2,day=30) #wrong day, but returns a value [1]

Thanks for this clarification. I have learned in the meantime that it is necessary to be very careful when using all these POSIX things. As another example, here is something that made me scratch my head just yesterday: When I create a sequence of days that happens to start before and ends in daylight savings time, I seem to lose a day: > seq(from = strptime("20030329",

Dear list: working with date/times I have come across a problem that ISOdate and ISOdatetime are too slow on large vectors of data. I was surprised just until I looked at the implementation and the man page: "ISOdatetime and ISOdate are convenience wrappers for strptime". In other terms, they convert data to character representation first in order to create a POSIXlt object that is then

Dear Brian and other R-developers, I have to say that I don't understand why what I wrote should have caused any offence. A smile was what I was hoping for. You know I devote more time than I am supposed to, to support R and its users, in partial repayment of my immeasurable debt to all the Developers. It's not much, it's sometimes misguided (I later discover), and my resources

Hello! I've been trying to get this right for quite a while now and fear there is an easy solution I just don't see. I did not have this problem in Linux, and I searched r-help and Google but did not find a solution, but of course I am grateful for and resources I might not have found our not understood yet. I try to parse a time stamp with time zone. I essentially just want to parse the

I use POSIXct for datetimes. Is thee a timeAlign function that I can use where : align by year direction -1 ==> start of this year direction 1 ==> start of next year align by week direction -1 ==> date on last sunday direction 1 ==> date on next sunday align by day direction -1 ==> time at past midnight direction 1 ==> time at this comming

Dear Members, Compliments of the Season!! Below is a part of a code I use for Fourier analysis of signals. The code handles data with the format 05 01 01 8628 (year, month, day and count) 05 01 02 8589 (year, month, day and count) The sample data is attached as 2005daily.txt. I would like to adapt the code to handle data of the form: 05 01 01 00 4009

Dear All, I have a data set containing year, month, day and counts as shown below: data <- read.table("data.txt", col.names = c("year", "month", "day", "counts")) Using the formula below, I converted the data to as date and plotted. new.century <- data$year < 70 data$year <- ifelse(new.century, data$year + 2000, data$year + 1900)

I have some data that was created for import into a Lotus 1-2-3 spreadsheet and on of the columns is time. The time is akin to Julian were the value 1 is mapped "01-Jan-00 12:00:00 AM" in Lotus 1-2-3. Is there a function in an R package that can convert this numeric vector to a POSIXct vector? With best wishes and kind regards I am Sincerely, Corey A. Moffet Instructor Department

Hi Ogbos, You can just use ISOdate. If you pass more values, it will process them: ISOdate(2018,01,22) [1] "2018-01-22 12:00:00 GMT" > ISOdate(2018,01,22,18,17) [1] "2018-01-22 18:17:00 GMT" Add something like: if(is.null(data$hour),data$hour<-12 then pass data$hour as it will default to the same value as if you hadn't passed it. Jim On Mon, Jan 22, 2018 at 6:01

hi, I've troubles with some difftime objects. e.g. ISOdate(2001, 4, 26) - ISOdate(2001, 2, 26) - 2 works, telling me "Time difference of 57 days". But when I'd like to add days, such as ISOdate(2001, 4, 26) - ISOdate(2001, 2, 26) + 2 the function gives me an error. Function "as.COMDate.chron" of the Rbloomberg package doesn't work for that reason. I'm

How can I best achieve the following (works in Splus): filenames <- dos("dir *.sasb7dat /b") What I am asking, more generically, is: how can I capture the output of a DOS command in R? I have tried using system("COMMAND.COM /c dir /b", intern=T, show.output.on.console=T) where intern: a logical, indicates whether to make the output of the command an R

Hi, Given a date, how do I get the last date of that month? I have data in the form YYYYMM, that I've read as a date using > x$Date <- as.Date(ISOdate(substr(x$YearEnd,1,4),substr(x$YearEnd,5,6),1)) But this gives the first day of the month. To get the last day of the month, I tried > as.Date(as.yearmon(x$Date,frac=0)) But I don't get the last day of the month here. (Tried

Although the documentation is somewhat sketchy, I() can be used to create objects of class AsIs: > I("a") [1] "a" attr(,"class") [1] "AsIs" "character" > I(4) [1] 4 attr(,"class") [1] "AsIs" "numeric" > I(4 + 0i) [1] 4+0i attr(,"class") [1] "AsIs" "complex" > This

bug.report() tells me to email to r-bugs@r-project.org, whereas the Web site http://www.r-project.org/ points me to r-bugs@biostat.ku.dk. Which should I believe? Simon Fear Senior Statistician Syne qua non Ltd Tel: +44 (0) 1379 644449 Fax: +44 (0) 1379 644445 email: Simon.Fear@synequanon.com web: http://www.synequanon.com Number of attachments included with this message: 0 This

Hi, I just encountered a problem in R that may easily be fixed: If one uses attach for a data.frame e.g. 10000 times and forgets detach, then R gets incredibly slow (less then 10% of the original speed). My system: platform powerpc-apple-darwin6.0 arch powerpc os darwin6.0 system powerpc, darwin6.0 status major 1 minor 6.1 year 2002

I'd like to make a plot showing frequency of an event. The data is in a data from that includes Year, Month and Day (of month) fields, so I created a Date with ISOdate(Year, Month, Day, tz=''). I can plot frequencies for the year 2002 with > thisyear <- Date[Year==2002] > hist( thisyear, xaxt='n' ) > axis.POSIXct( 1, at=seq(min(thisyear), max(thisyear),

In einer eMail vom 30.08.98 05:55:16 (MEZ) - Mitteleurop. Sommerzeit schreibt samba@samba.anu.edu.au: << # export SMBPASSWD='mypasswd' # gethash 74AC99CA40DED4204A3B108F3FA6CB6D:F671043BA08E88500D2EB5279AC65E53 >> This is nice. Every other user on the system can see that hash with ps. I would not call that extended security. Detlef

I've searched on CRAN for axes, axis, and other terms I've already forgotten, without (re)discovering the reason for S using "non-joining" axes by default, instead of box("l"). MASS points me towards Cleveland (1993) but I don't have ready access to this any more. Could someone give me a one-liner to justify this choice to a sceptic? It's something to do

Sparc Solaris / UFS file system. I have some ACL's set up for a handful of users and its all worked flawlessly with every incarnation of Samba I've used over the past couple years, which would be most. Last Friday evening I upgraded from 3.0.11 to 3.0.13 and some of the users I have some ACL's set up for promptly found Monday that they couldn't save new Excel files, they'd be