similar to: Is this a bug of pweibull()?

Please allow me to add just a little more about this: nothing wrong with pweibull(), namely, the two cases I reported: pweibull(3:10, 2) and pweibull(3:10, 2.1), in rw1041 and earlier version. I wonder this might just due to the change from rw1041 to rw1050, however, I can't find anything relevant (seems to me) in the News or Readme. Thanks Sundar for the suggestion of using 1 -

Full_Name: M Welinder Version: 1.4 OS: (src) Submission from: (NULL) (192.5.35.38) It seems to me that pweibull can be improved in the lower_tail=TRUE and log_p=FALSE case by using expm1. Something like -expm1(-pow(x / scale, shape)), I think. -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-devel mailing list -- Read

Dear R and ESS users, I got the following error when trying to load a source file (smart.R in directory E:\R\) into XEmacs through the menu iESS and "Load source file": Error in file(file, "r") : unable to open connection In addition: Warning message: cannot open file `E:Rsmart.R' It seems the slash "/" or "\" being missing, but I don't know

Hello, I am working with the nls() function and inserting a formula into it that uses the pweibull function. However the pweibull function is annoyingly producing NaNs, which nls() refuses to handle. I have put a sample of the code below. Is there a way to prevent these NaNs from interfering, for example a method to catch them? I get the following error when I try to run the code: res.nls <-

Dear R-Friends, How can I calculate a double integral like \int_a^b \int_c^y g(x, y) dx dy where a, b, c are constants, g(x, y), e.g., g(x, y) = tan(x + y). I tried to nested integrate() and adapt(), but none of them working, seemingly due to the limits can not be specified constants. Best regards, C. Joseph Lu Department of Statistics National Cheng-Kung University Voice:

Dear all - I have followed the thread the reply to which was lead by Thomas Lumley about using pweibull to generate fitted survival curves for survreg models. http://tolstoy.newcastle.edu.au/R/help/04/11/7766.html Using the lung data set, data(lung) lung.wbs <- survreg( Surv(time, status)~ 1, data=lung, dist='weibull') curve(pweibull(x, scale=exp(coef(lung.wbs)),

Dear all, I found that the plotmath seems won't work on xlab in plot (and other plot functions including matplot, contour, ...): > plot(1:10, 1:10, xlab=expression(alpha)) the plot shows nothing for x-label. My R-version is R.1.1.0 > version _ platform Windows arch x86 os Win32 system x86, Win32 status major 1

Dear R-friends, For the following data: > xy x y i 1 731 0.313 2 2 739 0.340 2 3 790 0.373 2 4 855 0.451 2 5 980 0.608 2 6 575 0.156 1 7 608 0.207 1 8 630 0.249 1 9 670 0.332 1 10 838 0.377 1 11 964 0.466 1 > coplot(y ~ x|i, data=xy) coplot gives 3 panels, rather than 2, namely one for i=1 and one for i=2. Futhermore, when I extand data fram xy to have i=3 as follows:

Dear R-Friends, Sorry to bother everyone with my earlier question: "Do we have similar R function to work like Minitab's INDICATOR?" I found the way to make things work: e.g., > x <- c(2,2,5,3,6,5,NA) > model.matrix(~ factor(x) - 1) factor(x)2 factor(x)3 factor(x)5 factor(x)6 1 1 0 0 0 2 1 0 0 0

Full_Name: M Welinder Version: 1.4 OS: (src) Submission from: (NULL) (192.5.35.38) It seems to me that pexp can be improved in the lower_tail=TRUE and log_p=FALSE case by using expm1. Something like -expm1 (-x / scale); I think. -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-devel mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send

Hello everyone, I have a quick question but I am stuck with it and I do not know how to solve it. Imagine I need the distribution function of a Weibull(1,1) at t=3, then I will write pweibull(3,1,1). I want to keep the shape and scale parameters in a list (or a vector or whatever). Then I have parameters<-list(shape=1,scale=1) but when I write pweibull(3,parameters) I get the following

On a recent FreeBSD 8.0-CURRENT (i386) building R (any version) breaks with the following messages: ---------------------------------------------------------------------- [...snip...] gcc -std=gnu99 -I. -I../../src/include -I../../src/include -I/usr/local/include -DHAVE_CONFIG_H -g -O2 -c wilcox.c -o wilcox.o gcc -std=gnu99 -I. -I../../src/include -I../../src/include -I/usr/local/include

Dear R gurus, I have the following code, but I still not know how to estimate and extract confidence intervals (95%CI) from resampling. Thanks! ~Adriana #data penta<-c(770,729,640,486,450,410,400,340,306,283,278,260,253,242,240,229,201,198,190,186,180,170,168,151,150,148,147,125,117,110,107,104,85,83,80,74,70,66,54,46,45,43,40,38,10) x<-log(penta+1) plot(ecdf(x),

I wonder if something like this has been reported before: > pexp(85:86,0.438) [1] 1 -Inf --please do not edit the information below-- Version: platform = i386-pc-mingw32 arch = i386 os = mingw32 system = i386, mingw32 status = major = 1 minor = 5.0 year = 2002 month = 04 day = 29 language = R Windows NT 4.0 (build 1381) Service Pack 6 Search Path: .GlobalEnv,

Dear all, I'm trying to fit a curve to some 1 year failure-time data, so that I can extrapolate and predict failure rates up to 3 years. The data is in the general form: Treatment Time Status Treatment A 28 0 Treatment B 28 0 Treatment B 28 0 Treatment A 28

I have an R function (about 1000 lines long) that takes more than 20 times as long to run under R Windows 1.9.0 and 1.8.1 than it does under 1.7.1. Profile results indicate that the $<-.data.frame operation is the culprit, but I don't understand exactly what that is (assignment of data frame elements to another variable?), or why it's only a problem under 1.8.1 and 1.9.0. Any advice?

OK this is bound to be something silly as I'm completely new to R - having started using it yesterday. However I am already warming to its lack of 'proper' GUI... I like being able to rerun a command by editing one parameter easily... try and do that in a Excel Chart Wizzard! I eventually want to use it to analyse some chemotherapy response / survival data. That data will not be

(1) ...need to speed up a monte-carlo sampling...any suggestions about how I can get R to use all 8 cores of a mac pro would be most useful and very appreciated... (2) spent the last few hours trying to get pnmath to compile under os- x 10.5.4... using gcc version 4.2.1 (Apple Inc. build 5553) as downloaded from CRAN, xcode 3.0... ...xcode 3.1 installed over top of above after

My Rgui crashes quite a lot when entering certain characters. I put a freshly extracted msvcrt.dll into the rw1050\bin directory, but this did not fix the problem. Perhaps, as stated in the FAQ section, I need also "put the rw1050\bin directory early in your path" but I do not know how to do it in Windows Me. Please could you give me some help? E. Barahona

Dear all, I have a question regarding performing test if the data fits chi-squared distribution. For example, using ks.test() I found in the examples how to fit it to gamma or weibull x<-rnorm(100) ks.test(x, "pweibull", shape=2,scale=1) for the gamma, pgamma can be used But I cannot find the value of this second parameter for the chi-squared distribution. Maybe someone