similar to: julian() in base depends on chron

I used to run the julian function from chron but this new version of R has also a julian function in the base package that doesn't do exactly what I need. Is there a way of telling R to run the function from chron and not from base? Thanks, Fernando __________________________ Fernando Colchero Doctoral Fellow Duke University Department of Ecology

Another beginner's question. Still trying trying to read and and plot a simple tds-value vs time. input file: onedat date time tds 1997-12-29 13:35:00 411 > onedat<-read.table("onedat",header=T) attach(onedat) > x<-chron(dates=as.vector(date),times=as.vector(time), format=c("y-md","h:m:s")) > x [1] (97-12-29 13:35:00) See my problem? Chron

I decided my earlier email on this topic was rather long and wordy; here's a condensed version. I am sitting at a Solaris computer in the US/Pacific timezone. I have a file of data having times that includes the following three values 2002-4-7 1:30:00 GMT 2002-4-7 2:30:00 GMT 2002-4-7 3:30:00 GMT I have not been able to find a way to correctly convert these to either of the POSIX

hello all, this is my reproducible example data frame test<-structure(list(date = structure(c(1262300400, 1262304000, 1262304000, 1262307600, 1262307600, 1262311200, 1262311200, 1262314800, 1262314800, 1262318400, 1262318400, 1262322000, 1262322000, 1262325600, 1262325600, 1262329200, 1262329200, 1262332800, 1262332800, 1262336400, 1262336400, 1262340000, 1262340000, 1262343600,

Hi! Is not there an standard R function to retrieve the day of the year (since 1st Jan of the same year)? I know I can make my own using julian, but find it weird that having days(), months() etc doy() does not exist as an standard function. Also, is the following not a bit inconsistent? > a <- chron("20100506",format="ymd") > a [1] 100506 > years(a) [1] 2010

Dear all, I have a problem with the function Julian, may be a bug in the function ? Here is a vector of character, which represents dates (May 18 to May 20 2000): > amj <- c("2000-05-18","2000-05-18","2000-05-18","2000-05-19","2000-05-19" > ,"2000-05-19", "2000-05-19", "2000-05-20", "2000-05-20",

I am using the "chron" package. Can anyone tell me if there is a simple way to convert a date object (obtained from the "dates" function) into a julian date (using the "julian" function)? Thanks, Al. Al Merrifield Energy Analyst Energy Modelling & Statistics Ministry of Economic Development PO Box 1473 Wellington NEW ZEALAND Phone: (04) 470 2338 Fax: (04)

Full_Name: Rick Bilonick Version: 1.6.0 OS: Linux (RH 7.1) Submission from: (NULL) (12.4.226.1) Hi. I'm using Red Hat 7.1 Linux (Intel 586). I installed the 1.6.0 rpm. No problems were reported. When I tried to load the chron library: Error in dyn.load(x, as.logical(local), as.logical(now)) : unable to load shared library "/usr/lib/R/library/chron/libs/chron.so":

Hi list, I have some questions regarding 1) conversion of date + time characters to chron 2) formatting chron object printing Regarding (1), Gabor's Rnews 2004 4/1 article has been indispensible, but I often work with files where dates and times are contained in a single field. In this case, I would like to control input/output of chron objects when each observation of date and time is

Running R 2.13.1 on Windows XP. I would like to get week of the year (1-52) for each date. library(chron) dts <- dates(c("02/27/92", "02/27/92", "01/14/92","02/28/92", "02/01/92")) dts dts.chron <- as.chron(dts) dts.chron class(dts.chron) # all of these component extractions work: months(dts.chron) weekdays(dts.chron) years(dts.chron)

> Date: Thu, 22 Feb 2001 09:46:38 -0800 > From: Jack Lewis <jl7001 at axe.humboldt.edu> > > R folks: > > What is the procedure for installing the chron package with R 1.2.1 > for Windows? I have downloaded chron_2_2-8_tar.gz from CRAN, > but the installer program (rwinst.exe) wants a .zip file and I was > unable to locate one at the CRAN site. It should be

I have two local variables: startTime and expectedStartTime. Both are chron related objects. When I look at the class for the objects I can see they are of class "times". When I print them to the console, they both read: "09:30:00" When I print them as.numeric(), they both read: 0.3958333 When I try and compare them: (as.numeric(startTime) == as.numeric(expectedStartTime)) it

I can't get the scales parameter in xyplot of lattice to work as I expected. I'm using R-2.1.0 and lattice 0.11-8. There should be year labels from 1992 to 2004 for the x axis in the plot below, but instead only a few of them appear, and in the wrong spots, as if the coordinate system has changed after finishing with the panel function. library(chron) library(lattice) # vertical grid

I was just looking for an easy way to convert between COM datetime and chron datetime (both ways.) I found examples on the list, but they involved origin. Does anyone have functions for converting COM datetime <-> chron datetimethat work "safely"? David L. Reiner > -----Original Message----- > From: Gabor Grothendieck [mailto:ggrothendieck@gmail.com] >

Hey R folks, i found some strange (to me) behaviour with chron to POSIXct conversion. The two lines of code result in two different results, on ewith the correct time zone, one without: library(chron) as.POSIXct(chron('12/12/2000'), tz = 'UTC') as.POSIXlt(chron('12/12/2000'), tz = 'UTC') Only the code below would give me a POSIXct object with the correct time

Hi all, I'm just getting started in R so bear with my newbness. I am trying to create a very simple histogram of logins by time, with data coming in from a MYSQL query. the raw data looks like this: "id" "user_id" "experience_given" "created_at" "ip_aton" "1" XXXXXXX 2445626 0 "2010-01-21 00:00:01" 1123632036 "2"

Hello, I have a list of data frames that I would like to combine to a single data frame. I typically do this with: do.call(rbind, list.of.dataframes) This time, I get Error in class(x) <- cl : cannot set class to "array" unless the dimension attribute has length > 0 I'm not sure what's happening. Each data frame has a column of chron objects and a column of float

I encountered surprising (to me, at least) behavior while using 'hours()' in package 'chron.' I will be grateful if someone can point out my error or provide an explanation and intuitive solution (I suppose I could convert chron to a character vector and use substring, but I deal mostly with newbies and kludgy approaches don't inspire much confidence). I used 2.3.0 to

Hello there, Using R 2.4.0 on Solaris (Unix): I am trying to control the X axis range on a simple time of day plot. I made a test program (below) that gets file time stamp information from the files in the directory where R starts. The goal of the test program is to plot the time of day of file creation on an x axis that spans a user-specified range (like 12:00:00 to 15:00:00). If I allow

I have date and time data which looks like this: [,1] [,2] [1,] "7/1/08" "9:19" [2,] "7/1/08" "9:58" [3,] "7/7/08" "15:47" [4,] "7/8/08" "10:03" [5,] "7/8/08" "10:32" [6,] "7/8/08" "15:22" [7,] "7/8/08" "15:27" [8,] "7/8/08"