Displaying 20 results from an estimated 2000 matches similar to: "MA / RMA / Type II regression?"
1999 Oct 05
1
WANTED: Q&A
First, I am really liking what I have seen so far in R. The demos are
quite fascinating, and I look forward to doing some really neat stuff
over the next little while with R.
Being but an intiate to R, I am having quite a bit of trouble figuring
out how to use the leaps library. Rather than ask several questions to
the list at large, I would rather explain what I'm trying to do to
someone in
1999 Oct 25
2
leaps: XHAUST returned error code -999
Hi there,
This problem has been dogging me for a bit, and I'm trying to
figure out why. When running the the subsets function in the leaps
library, R is giving me the following error message
> lvodsub <- subsets(pred, resp$LVOD)
Warning message:
XHAUST returned error code -999 in: leaps.exhaustive(a, really.big =
really.big)
but this still happens if I add the really.big option:
1999 Sep 29
1
Is there an R-SQUARE function?
Hi there, I realize that this is a bit of a strange question, but here
goes.
In SAS, one can use the REG procedure to carry out a least-squares
regression analysis. By specifying the R-SQUARE option in the SELECTION
command, the program carries out regressions for every combination of
every independant variable against the dependant variable. This is
useful in smaller datasets, though difficult
2000 Feb 09
0
Comparing Type 2 regressions
> Date: Wed, 09 Feb 2000 10:11:20 -0500
> From: "Pete St. Onge" <pete at seul.org>
> Subject: Comparing Type 2 regressions Was: [R] Ancova in R?
>
> For starters, thanks to everyone who responsded to my previous request for
> help about Type 2 regression.
>
> > > I see the R-sm has the ancova thing happening, but I kind of doubt that
> > >
2000 Jan 04
1
correlation matricies: getting p-values?
I have to admit that I'm at a bit of a loss here; any pointers would be
greatly appreciated.
I've been making correlation matricies from some of my datasets, and
have been instructed to get the probability values for each of these
correlations.
I've checked the online help for info on both the cor and cov functions,
but I was unable to find any relevant info on finding how to obtain
2000 Apr 01
0
space in user dir?
This is obviously not a long term acceptable solution. Could someone
please enlighten me as to the permanent solution, or at least see why it
doesn't work? This is not my problem, therefore I have not had the
opportuntity to test - I don't have a version that old. Let me know if it
is solved in a newer version as well. Thanks.
It is a workable solution, although the generally accepted
2004 Oct 21
2
RMA question
Can anybody explain why RMA has to have a default normalization method:
quantile-quantile? Why don't leave the choices to users?
If I just want to use RMA to do a background correction without
normalization, how should I specify the ? in the normalize.method="?" ?
Hairong
[[alternative HTML version deleted]]
2009 Dec 26
1
[BioC] How to do RMA without summary to probeset level?
I think that you misunderstood me.
As far as I know, RMA does three things: background correction,
quantile normalization, and summary from probes to probesets. I want
the probe values after background correction and quantile
normalization but before the summary.
On Sat, Dec 26, 2009 at 12:07 PM, Benilton Carvalho <bcarvalh at jhsph.edu> wrote:
> pm(data)
>
> b
>
> On Dec
2011 Jul 18
1
Extract confidence intervals from rma object (metafor package)
Dear R-experts!
I am working on some meta-analysis using the metafor package. I would like
to extract values of the confidence intervals of the effect sizes of the
single studies from an rma object. Those values are printed out when
plotting a forest plot using the forest function on the rma object, however
I was not able to locate them.
Many thanks for your help!
Jokel
[[alternative HTML
2011 Sep 08
1
predict.rma (metafor package)
Hi
(R 2.13.1, OSX 10.6.8)
I am trying to use predict.rma with continuous and categorical variables. The argument newmods in predict.rma seems to handle coviariates, but appears to falter on factors. While I realise that the coefficients for factors provide the answers, the goal is to eventually use predict.rma with ANCOVA type model with an interaction.
Here is a self contained example
2006 Mar 03
3
Sipura RMA
Anyone have any luck RMAing a Sipura phone since the Cisco take over?
Sipura only has support via email or fax to end users and I haven't
gotten a response to either for over 2 months.
Linksys Support will jump you through all their scripted hoops to
resolve your problem (they hope if they speak with a thick enough accent
and make repeat the same steps over and over again that you will just
2004 May 14
2
rma and gcrma do not work in R 1.9.0
I run R 1.9.0 on windows 2000, and have the following libraries installed:
affydata_1.3.1
affy_1.4.23
Biobase_1.4.10
DynDoc_1.3.14
gcrma_1.0.6
hgu133acdf_1.4.3
hgu95av2cdf_1.4.3
hgu95av2probe_1.0
matchprobes_1.0.7
moe430acdf_1.4.3
multcomp_0.4-6
mvtnorm_0.6-6
rae230acdf_1.4.3
reposTools_1.3.29
rgu34acdf_1.4.3
tkWidgets_1.5.1
widgetTools_1.2.7
1. The rma function (in affy library) always crashes.
2011 Mar 29
0
Plotting 95% Confidence Intervals around RMA slope
Hi,
I'm regressing various body dimensions upon body mass using the 'lmodel2' function, as I'm keen to obtain both OLS and RMA slope values. I also wish to create a plot of the regressions, with the 95% confidence interval of both the slope and intercept. I know how to plot 95% ci bands of the OLS slope using lm with the 'predict' function and 'matlines'. Does
2011 Oct 16
0
background normalization in rma() in the affy package
Hi,
i was looking into the documentation for the rma() function in affy()
package, and was trying to figure out how exactly the background
normalization is done. I read all three papers cited in the rma()
documentation, but the most detailed explanation i could find was in Irizary
et al., 2003, where they state that they compute
B(PM_{ijn}) = E[s_{ijn} | PM_{ijn}]
where s_{ijn} is assumed to
2002 Sep 20
0
Linksys EFG20, RMA XH01210298
Forwarded to: ismtp[samba@samba.org]
cc:
Comments by: Charles J. Huenke@Admin@SAC
Comments:
Please offer any input you may have on the issue described below.
Thank you.
Chuck Huenke
Delaware Statistical Analysis Center
(302) 739-3680
-------------------------- [Original Message] -------------------------
We received a replacement EFG20 on the referenced
2008 Aug 18
1
exonmap question: rma (or justplier) crashes
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2009 Jul 20
1
package lmodel2: p-value RMA fitting?
Hi *,
is there a way to obtain some kind of p-value for a model fitted with RMA
using the lmodel2 package?
I know that p-values are discussed and criticized a lot and as you can image
from my question I'm not
very much of a statistican (only writing my bachelor thesis).
As fare as I understood the confidence interval statistic correctly, a
coefficient is regarded as statistically
significant
2006 Jul 11
1
test regression against given slope for reduced major axis regression (RMA)
Hi,
for testing if the slope of experimental data differs from a
given slope I'm using the function
"test_regression_against_slope" (see below).
I am now confronted with the problem that I have data which
requires a modelII regression (also called reduced major axes
regression (RMA) or geometric mean regression). For this I use
the function "modelII" (see below).
What
2012 Jul 24
1
Annotate forest plot 'forest.rma()' for meta-analysis with metafor package
Dear R-experts,
The forest.rma() function from the metafor package creates nice forest
plots for presenting the results of a meta-analysis. These plots can be
annotated for e.g. giving names to the columns. E.g. as in the
documentation of the package:
data(dat.bcg)
### meta-analysis of the log relative risks using a random-effects model
res <- rma(ai=tpos, bi=tneg, ci=cpos, di=cneg,
2009 Dec 04
1
z to r transformation within print.rma.uni and forest from the package metafor
Dear R community,
I'm using the ,metafor'-package by Wolfgang Viechtbauer (Version: 0.5-5) to
calculate random-effects meta-analyses using Correlations and Sample Sizes
as the raw data.
(By the way: Really a nice piece of work, Wolfgang! Thanks heaps.)
I specified the "rma.uni' function so that it looks like this:
MAergebnis<-rma.uni(ri=PosOutc, ni=N,