similar to: cummax / cummin for complex numbers

Hi, The function cummax() seems to have a bug. > x <- c(NA, 0) > storage.mode(x) <- "integer" > cummax(x) [1] NA 0 The correct result of this case should be NA NA. The mistake in [ https://github.com/wch/r-source/blob/trunk/src/main/cum.c#L130-L136] may be the reason. Best Regards, Dongcan -- Dongcan Jiang Team of Search Engine & Web Mining School of Electronic

Hi, I have two questions want to ask. 1. If I have a matrix like this, and I want to figure out the rows whose value in the 3rd column are less than 0.05. How can I do it with R. hsa-let-7a--MBTD1 0.528239197 2.41E-05 hsa-let-7a--APOBEC1 0.507869409 5.51E-05 hsa-let-7a--PAPOLA 0.470451884 0.000221774 hsa-let-7a--NF2 0.469280186 0.000231065 hsa-let-7a--SLC17A5

Dear all, at UseR! 2013, the FastR project was announced by Tomas Kalibera, Petr Maj, and Jan Vitek. FastR is an implementation of the R programming language in Java using AST interpretation and specialisation for improved performance. Since, the implementation has been extended to support JIT compilation, leading to performance improvements. The goal of the project is to further the R community

Hello, I'm a bit puzzled by what looks (to me) like a discrepancy between documentation and implementation. The documentation for [] says this about the indices: "Numeric values are coerced to integer as by as.integer (and hence truncated towards zero)." > as.integer(-3.1) [1] -3 Good. But: > x <- c(1,2,3) > x[-3.1] [1] 1 2 3 Given the documentation, I'd have

Hi! I noticed that cumsum behaves different than the other cumulative functions wrt. NaN values: > values <- c(1,2,NaN,1) > for ( f in c(cumsum, cumprod, cummin, cummax)) print(f(values)) [1] 1 3 NA NA [1] 1 2 NaN NaN [1] 1 1 NaN NaN [1] 1 2 NaN NaN The reason is that cumsum (in cum.c:33) contains an explicit check for ISNAN. Is that intentional? IMHO, ISNA would be better

Hello, I'm dealing with financial time series. I'm trying to find out X in this sentence: The most recent close is the lowest level since X(date). Here's an example of what I'm looking for: library(fBasics) data(DowJones30) tail(DowJones30[,1:5],n=10) I need to come up with a vector that would look like this AA AXP T ... 2000-12-21

Hi, I'm currently in the process of writing an R-installation SOP for my company. As part of that process I'm using the recommendations from the 'R Installation and Administration' document, section 3.2, "Testing an installation". This is done on an XP machine, using the latest binary of 2.11.0. The binary is downloaded and then installed from the installer. I then

Hello, given that `*tmp*` is removed after a replacement, how can code like this work? Is there some special handling for a variable named `*tmp*` when it comes to make element assignments? > x<-c(1,2) > x[1]<-42 > `*tmp*`[1]<-7 # I would expect this one to fail > `*tmp*` Error: object '*tmp*' not found Confused greetings, Michael -- Dr. Michael Haupt Principal

Dear all, we are offering an internship position at Oracle Labs, in Redwood Shores (CA) or Potsdam (Germany). An outline of the job description can be found below. Additional details can be found at https://irecruitment.oracle.com (search for IRC2419637). Best regards, Michael Haupt "In the context of the Alphabet Soup project, Oracle Labs is contributing to an open-source optimised

Looks like my first question a couple of days ago wasn?t very clever asked, at least very sucessfull.... So, anyway...i will try it again: I have to prefix that I am far away from fully understanding the overall concept yet, and there?s no way to get some hints in the www so far, at least my resaerches dont lead to any helpfull stuff. image_controller.rb: def create MiddleMan.new_worker

In my view code, I have <%= datetime_select "in_out", "time_in" %> which returns in params :in_out: !map:HashWithIndifferentAccess time_in(1i): "2006" time_in(2i): "6" time_in(3i): "12" time_in(4i): "20" time_in(5i): "24" and I want to save that datetime to a column in the db... if

Got a weird situation with an update put to a controller with a form with nested attributes. On the data below, I am updating data for both items (''0'' and ''1'') in rosters_attributes (in the example below I am updating the ''name'' attribute to a new value in both cases. What I am stuck on is that ''1'' gets its data updated,

-------------------------- Question 1 -------------------------- I am dealing with a database that holds products and it has a datetime field called "active_at". so I have the following for active_at: <%= f.datetime_select :active_at %> It gives me 5 different params: params[:product][:active_at(1i)] params[:product][:active_at(2i)] params[:product][:active_at(3i)]

I see that if I use the date_select helper in my view, then in the generated page, my selects are named obj[datetime_field(1i)] (and 2i and 3i for the other parts). These auto-populate the date portion of my datetime_field. I have another datetime field that I''m presenting the time from and I would like to use a similar scheme to autopopulate it. Currently, I''ve used the

Parameters: {"bestandsliste"=>{"typ"=>"bumffer", "KundanName"=>"parikshit", "Abgeholt"=>"", "LieferLand"=>"", "Kaufmann"=>"birla", "Marge"=>"", "Erzieltervk"=>"", "LieferOrt"=>"",

I append below a suggested update for p.adjust(). 1. A new method "yh" for control of FDR is included which is valid for any dependency structure. Reference is Benjamini, Y., and Yekutieli, D. (2001). The control of the false discovery rate in multiple testing under dependency. Annals of Statistics 29, 1165-1188. 2. I've re-named the "fdr" method to "bh" but

I am using the date_select helper to generate date select elements in a form. I notice that the generated HTML shows that these selects have the following names: Month: current_job[StartDate(2i)] Day: current_job[StartDate(3i)] Year: current_job[StartDate(1i)] I''m assuming that the Xi identifiers somehow specify the appropriate date part from a date or time value. Can anyone

Hola, Tenía una versión anterior de R, la 2.10.1 en la cual podía cargar perfectamente el paquete "lme4". Actualicé la versión del R a 2.14.0 y aún volviendo a descargar la nueva versión del paquete mencionado cuando intento cargarlo me da el siguiente error : > library(lme4) Error: package ‘lme4’ is not installed for ''arch=i386'' Hay alguna solución para esto o

Hi. Suppose I have a vector that I partition into disjoint, contiguous subvectors. For example, let v = c(1,4,2,6,7,5), partition it into three subvectors, v1 = v[1:3], v2 = v[4], v3 = v[5:6]. I want to find the maximum element of each subvector. In this example, max(v1) is 4, max(v2) is 6, max(v3) is 7. If I knew that the successive subvector maxima would never decrease, as in the example,

[Same question for max(.), cummin(.) and cummax(.)] In S, S-plus and R, this currently gives NA. I wonder if it wouldn't make more sense to follow common mathematical/logical reasoning here: min { empty set } = +Inf max { empty set } = -Inf (For integers, these would be INT_MAX and INT_MIN, respectively). Maybe this is a real ``first time'': I am proposing a change which