similar to: grep help (character ommission)

Dear all, Can anyone please shed some light onto how to do this? This will give me all "intensity" columsn in my data frame: intensityindeces <- grep("^Intensity",names(dataframe),value=TRUE) This will give me the maximum intensity for the first row: intensityone <- max(dataframe[1,intensityindeces]) What I'm now looking for is how to dfo this for the whole data

Hi, Is there such a thing? If no: is it easily simulated? thanks, Joh

Why is class(spectrum[["Ion"]]) after this "factor"? spectrum <- cbind(spectrum,Ion=rep("", nrow(spectrum)),Deviation.AMU=rep(0.0, nrow(spectrum))) slowly going crazy ... Joh

>From: Johannes Graumann <johannes_graumann at web.de> >Date: 2007/12/18 Tue PM 04:40:37 CST >To: r-help at stat.math.ethz.ch >Subject: [R] All anchored series from a vector? lapply(1:length(myvector) function(.length) { c(myvector[1}:myvector[.length]) }) but test it because i didn't. >Hi all, > >What may be a smart, efficient way to get the following result:

Hi, Any ideas on how to efficiently convert > list(c(1,2,3),c(4,5,6)) to > data.frame(OriginalListIndex=c(1,1,1,2,2,2),Item=c(1,2,3,4,5,6)) Thanks for any hints, Joh

Hello R-ologists, Imagine you have a list "list" like so: >list [[1]] [1] "IPI00776145.1" "IPI00776187.1" [[2]] [1] "Something" "IPI00807764.1" "IPI00807887.1" [[3]] [1] "IPI00807764.1" [[4]] [1] "Somethingelse" What I need to achieve is a filtered list "list2" like so: >list2 [[1]] [1]

Hi, Is there any way to get an expression into a data.frame, such that "grid.table" from "gridExtra" will plot it evaluated in the table body? The docu does it for the header, but is the body possible? Thanks, Joh

Hi, Is there any way to trick R CMD check into not throwing this error after I created a dedicated "plot" incarnation for my custom function? * checking S3 generic/method consistency ... WARNING plot: function(x, ...) plot.MQUSpecMatch: function(x, mozlabel, labelcex) Thanks again, Joh

Hello, With the help of "seek" I can start "readBin" from any byte offset within my file that I deem appropriate. What I would like to do is to be able to define the endpoint of that read as well. Is there any solution to that already out there? Thanks for any hints, Joh

Hi, I fail to find "choose.dir()" in my current R install (see below)? Didn't that exist at some point? How to achieve "file.choose()" equivalent functionality for directories? Thanks for any hints, Joh > sessionInfo() R version 2.11.1 (2010-05-31) x86_64-pc-linux-gnu locale: [1] LC_CTYPE=en_US.UTF-8 LC_NUMERIC=C [3]

Hello, I'm new to this and am trying to teach myself some R by plotting biological data. The growth curve in question is supposed to be fitted to the Verhulst equation, which may be transcribed as follows: f(x)=a/(1+((a-0.008)/0.008)*exp(-(b*x))) - for a known population density (0.008) at t(0). I am trying to rework the example from "An Introduction to R" (p. 72) for my case and

<posted & mailed> Dear all, I'm trying to solve the problem, of how to find clusters of values in a vector that are closer than a given value. Illustrated this might look as follows: vector <- c(0,0.45,1,2,3,3.25,3.33,3.75,4.1,5,6,6.45,7,7.1,8) When using '0.5' as the proximity requirement, the following groups would result: 0,0.45 3,3.25,3.33,3.75,4.1 6,6.45 7,7.1

Hello again, I'm trying to do the following: subset(dataframe,list %in% strsplit(dataframe[[Field]],",")) But This returns always the complete dataframe, since the strsplit(dataframe[[Field]],",") is evaluated as one big list for the whole data frame rather than one list per row. How can I have this evaluated on a per row basis? After 1.5 h hitting head against wall -

Hello, I have a list of character vectors like this: sequences <- list( c("M","G","L","W","I","S","F","G","T","P","P","S","Y","T","Y","L","L","I","M",

Hello, Is it possible to get all "par" content calculated for "plot" without actually plotting anything? I'm missing an option "plot=FALSE" ... "type="n"" will still open a device and draw the axes ... Thanks, Joh

Hi, What is an efficient way to take this DF data.frame(A=c(1,2,NA,NA),B=c(1,NA,NA,4)) and get c(NA,"TWO","BOTH","ONE") as the result, where NA corresponds to a row without "NA"s, TWO indicates NA in the second and ONE in the first column. Thanks for any pointers. Joh

Does anybody have any insight into how to make this faster? I suspect, that the rounding going on may be an issue, as is the stepping through data frame rows using integers ... If you have the patience to teach a noob, he will highly appreciate it ;0) Joh digit <- 4 for (minute in seq(from=25,to=lrange[2])){ # Extract all data associtaed with the current time (minute) frame <-

Hello again, I'm trying to purge the indexes in i.delete from frame and end up with more rows!? Please be so kind and let me know where I screw this up ... Joh > i.delete [1] 40 45 165 212 253 270 280 287 301 352 421 433 463 467 487 [16] 517 537 542 573 594 596 612 614 621 635 650 696 699 707 732 [31] 738 776 826 891 892 936 937 935 940 976

Hi there, given a data.frame 'data' I managed to filter out entries (rows) that are identical with respect to one column like so: duplicity <- duplicated(data[column]) data_unique <- subset(data,duplicity!=TRUE) But I'm trying to extract how many duplicates each of the remaining rows had. Can someone please send me down the right path for this? Joh

> -----Original Message----- > From: William Dunlap > Sent: Tuesday, November 25, 2008 9:16 AM > To: 'johannes_graumann at web.de' > Subject: Re: [R] Efficient passing through big data.frame and > modifying select fields > > > Johannes Graumann johannes_graumann at web.de > > Tue Nov 25 15:16:01 CET 2008 > > > > Hi all, > > > >