similar to: How to list the all products' information of the latest month?

HI, R-Users: I got a questions. have been struggling so long time.... I have this data: > m1$Year_Month 201009 201010 201011 201101 201102 > min(m1$Year_Month) 201009 I want to calculate the following two answers, how do I program it? > difference in Month????? [1] 0 1 2 4 5 >difference in Days????? 0 31 61 .... Thank you in advance!!! Tammy [[alternative

HI, I have the pattern like "`Year_Month)201103`" I want to delete single quotes within double quetes. I want to change it into "Year_Month)201103" , how to do it in r? Thanks a lot. Tammy [[alternative HTML version deleted]]

HI, I have the following list: crosspries $crosspries[[1]] Product Year_Month prod1 A 201208 1 B 201208 2 C 201208 1 $crosspries[[2]] Product Year_Month prod1 prod2 A 201209 1 1 B 201209 2

Hello, I have created many excel files in my working dir. each excel file contain one country's data. In the excel, I have dataframe in sheet1, where each product and its relative information is in each row as following: Product PE Retail_price_Band Country Model_Fit A -2.5 0-50 CN 84% B -2.1 51-100

HI, R-Users, I have one problem: I have written the the programs which process all file in one directory: for example: setwd("C:/Documents and Settings/lma/My Documents/Vappu-saved/Log") as the start. .......... But I have many folders like "Vappu-saved" and there are a lot of files in each directory. What I want is using the same program what I write for the above

HI, I have the price and volume data from own product and competitor's product: Year_Month Volume own product's price Volume competitor's price 1 201011 17583 469.03 NA NA 2 201012 33899 489.25 NA NA 3 201101 31306

HI, Assume I have the data frame generated from R as the following: Product Price market_share A 100 10% B 110 9% C 120 20% D 90 61% What I want to do is to have this kind of excel user interface by changing price of certain products, to get the impact of market share generated from R: if I change A

Folks, This question is somewhat related to a previous posting of mine. I just can't seem to create a generic solution. Here is a function that I found searching around the internet: splitIt <- function(x, n) {split(x, sort(rank(x) %% n))} I use it like so: > splitIt(1:12, 2) $`0` [1] 1 2 3 4 5 6 $`1` [1] 7 8 9 10 11 12 Or > splitIt(1:12, 4) $`0` [1] 1 2 3 $`1` [1] 4 5 6

HI, Sorry for messing up.. I want to transform the following dataset: product min_price max_price mean_price country price_band 11 34 50 40 VN 0-300 22 10 30 15 VN 0-300 Into: product VN price_band 11 40 0-300 [34,50] 22 15

Thanks. Yes. Your approach can identify: Glaxy ace S 5830 and S 5830 Glaxy ace But you can not identify using same program: Iphone 4S 16 G Iphone 4S 16G How should I solve both in same time. Kind regards,Tammy [[alternative HTML version deleted]]

Dear R-users, I use "readLines" to read data, but when processing the large data set, there are few files which can not be readed in: 48: In readLines(name_c[i]) ... : incomplete final line found on 'C:/Documents and Settings/lma/My Documents/habitdata/244052900243997/calllog/calllog_log-20050505T121611.txt' ... Whats the problem about this? Regards, Tammy

HI, I have the list: > suu [[1]] NULL [[2]] NULL [[3]] item_id prod 1 2 [[4]] item_id prod 1 2 2 4 how to delete all "NULL" elements from suu to get only >suu [[3]] item_id prod 1 2 [[4]] item_id prod 1 2 2 4 ?? Kind regards, Tammy [[alternative HTML version deleted]]

Hi, I met this problem. Trade_Price_Band x 1 0-30 0.6237240 2 101-150 0.6743857 3 151-200 0.6778513 4 201-300 0.6640293 5 301-400 0.6630991 6 31-50 0.6314547 7 401-500 0.6776249 8 500+ 0.6557705 9 51-75 0.6621073 10 76-100 0.6623469 I want to get the following matrix

Hi, All. I have a data frame with the part as : ..... 142 2006-02-22 16:28:18 useractivity_act 8 0 143 2006-02-22 16:28:26 4 2 0 144 2006-02-22 16:28:28 3 3 0 145 2006-02-22 16:28:31 4 4 1 146 2006-02-22 16:28:35 3 159 0 147

HI, I met this problem: I have the feature data frame: Feature OS 4 2 4 1 4 3 1 2 4 1 what I want to do is to autimatically create one more column called "group": Feature OS Group 4 2 1 4 1 2 4 3

HI, R user, I generate the vectors with the same length. I want to put each vector into each column of data frame. Why it doesnt work`? rm<-data.frame() for(a in 1:6){ rm[,a]<-getmeasure(p1,a,speech) } thanks a lot Tammy _________________________________________________________________ Share your memories online with anyone you want.

HI, I have the following question: Vector a with lenght 150 A B C D......... dataframe b with dim 908X150 1 1 1 1..... 2 2 2 2 3 3 3 3 4 4 4 4 ................ final result I want is the vector with length 908: A*1+B*1+C*1+D*1+..... A*2+B*2+C*2+D*2+..... A*3+B*3+C*3+D*3+..... A*4+B*4+C*4+D*4+..... .... because of too large dimension, how can I achieve this in R?

HI, I have large dataset of many countries. I have written the program to run through each country to generate one output for each country. I want to put the output like this: one sheet has output for one country. How do I achieve it by r. I have tried this: library(xlsx) write.xlsx(nnn, "vn.xlsx", sheetName="Sheet1") [1] but when I change sheetName="Sheet2"

Dear R user: I have got the following problem: I have imported two data sets into R: one set includes price information, another one includes volume information. but I noticed the wrong data order problem in the product name, for instance, in one data set, "GALAXY ACE S 5830" in another one, it is "S 5830 GALAXY ACE" both represent same product. how do i map two name

Hello, How can I check if file is empty in R, if it is, then jump out and read next file; if it isn't, then read through? Thanks a lot for any help. Tammy _________________________________________________________________ More than messages–check out the rest of the Windows Live™. http://www.microsoft.com/windows/windowslive/ [[alternative HTML version deleted]]