similar to: Problem with

I know that maybe it will be stupid question. What iswrong with it (i think that i have to do the "stop moment", but i dont know how) fibbonacci=function(x) { while(x>0) { if (x==1 || x==2) { return(1) } else fibbonacci(x-1)+fibbonacci(x-2) } } -- View this message in context: http://r.789695.n4.nabble.com/Problem-with-recursion-tp4649162.html Sent from the R help mailing list

On the surface this seems pretty simple, but I flummoxed. I have two sets of numbers they bounce around zero, positive one and negative one. They have a relationship between them, where one diverges away from the other. I want create a second set of numbers that tracks that divergence. #Lets make some data like mine, kinda Firstset <- runif(100, min = -1 , max =1) Secondset <- runif(100,

> On Aug 14, 2017, at 5:17 AM, peter dalgaard <pdalgd at gmail.com> wrote: > > >> On 14 Aug 2017, at 13:43 , Spencer Graves <spencer.graves at effectivedefense.org> wrote: >> >> >> >> On 2017-08-14 5:53 AM, peter dalgaard wrote: >>>> On 14 Aug 2017, at 10:13 , Troels Ring <tring at gvdnet.dk> wrote: >>>>

Thanks Adrian and Thierry (from the previous answer). I was aware of the all.equal function, but there is nothing similar for <= (e.g. all.smallerEqual)? cheers, jo On 05 Apr 2016, at 14:31, Adrian Du?a <dusa.adrian at unibuc.ro<mailto:dusa.adrian at unibuc.ro>> wrote: Yes, that does have to do with floating point representation. I use this function for these types of

The following 1460 x 1460 matrix can be throught of as 16 distinct 365 x 365 matrices. I'm trying to set off-diaganol terms in the 16 sub-matrices with indices more than +/- 5 (days) from each other to zero using some for loops. This works well for some, but not all, of the for loops. The R code I"m using follows. For some reason the third loop below zero's-out everything in the

Hi all, I am back with a new question ! I recorded the occurence of 4 differents event on 20 places for a given time period. Now, I want to do some barplot of the frequency of theses events for each place, so it should be easy. My problem is that I want to see the frequencies of the 4 events on my barplots even if the frequency of some of them is 0. How could I do that ? Thanking you in advance

> On 14 Aug 2017, at 13:43 , Spencer Graves <spencer.graves at effectivedefense.org> wrote: > > > > On 2017-08-14 5:53 AM, peter dalgaard wrote: >>> On 14 Aug 2017, at 10:13 , Troels Ring <tring at gvdnet.dk> wrote: >>> >>> Dear friends - I hope you will accept a naive question on lm: R version 3.4.1, Windows 10 >>> >>> I

Hi guys, i need help. I have an axis that runs from -100 -75, -50, -25, 0 25, 50, 75, 100. I need to somehow hide or remove the '-' in the axis label. Is there anyway to do this?? I would still like R to think of the left side of my graph as negatives, but visually appear as though they are not negative values (if that makes sense!) . -- View this message in context:

Hi Elisa, I hope this is what you wanted. dat1<-read.csv("peaks.csv",sep=",") #Subset dat2<-dat1[1:5,] res1<-do.call(cbind,lapply(seq_len(nrow(dat2)),function(i) do.call(rbind,lapply(split(rbind(dat2[i,],dat2[-i,]),1:nrow(rbind(dat2[i,],dat2[-i,]))), function(x) {x1<-rbind(dat2[i,],x);

On 2017-08-14 5:53 AM, peter dalgaard wrote: >> On 14 Aug 2017, at 10:13 , Troels Ring <tring at gvdnet.dk> wrote: >> >> Dear friends - I hope you will accept a naive question on lm: R version 3.4.1, Windows 10 >> >> I have 204 "baskets" of three types corresponding to factor F, each of size from 2 to 33 containing measurements, and need to know if the

Hi I have measured the UV absorbance (abs) of 10 solutions of a substance at known concentrations (conc) and have used a linear model to plot a calibration graph with confidence limits. I now want to predict the concentration of solutions with UV absorbance results given in the new.abs data.frame, however predict.lm only appears to work for new "conc" variables not new "abs"

Hello, I analyse some free-sorting data so I use hierarchical clustering. I want to compare my proximity matrix with the tree representation to evalute the fitting. (stress, cophenetic correlation (pearson's correlation)...) "The cophenetic similarity of two objects a and b is defined as the similarity level at wich objects a and b become members of the same cluster during the course of

I'm have a (minor) problem and a question. Problem: The following code creates 5 clusters of dots of different colors. However, I need the second call outside the data.frame call to get the colors to change for some reason. I assume there's an error in the data.frame() call, but I don't know what. Question: Is there is a way to cause the resulting graphic to rotate on it's

Hi, Try this: #mat1 is the data res<-do.call(cbind,lapply(seq_len(nrow(mat1)),function(i) {new1<-do.call(rbind,lapply(seq_len(nrow(mat1[-i,])),function(j) {x1<-rbind(mat1[i,],mat1[j,]); x2<-(abs(x1[1,1]-x1[2,1])*abs(x1[1,5]-x1[2,5]))+(abs(x1[1,2]-x1[2,2])*abs(x1[1,6]-x1[2,6]))+(abs(x1[1,3]-x1[2,3])*abs(x1[1,7]-x1[2,7]))+(abs(x1[1,4]-x1[2,4])*abs(x1[1,8]-x1[2,8]))}));new1}))

From: Christian Hesse <mail at eworm.de> Signed-off-by: Christian Hesse <mail at eworm.de> --- sshkey.c | 47 ++++++++++++++++++++++++++++++++++++----------- 1 file changed, 36 insertions(+), 11 deletions(-) diff --git a/sshkey.c b/sshkey.c index cfe5980..47511c2 100644 --- a/sshkey.c +++ b/sshkey.c @@ -44,6 +44,9 @@ #include <stdio.h> #include <string.h> #include

Le 06/07/15 12:33, Alex Bligh a ?crit : > On 6 Jul 2015, at 11:05, Christian Hesse <list at eworm.de> wrote: > >> +#ifdef HAVE_LOCALE_H >> + char *locale; >> + char *border_utf8[] = { "?", "?", "?", "?", "?", "?" }; >> +#endif >> + char *border_ascii[] = { "+", "-",

Hello, I'm new here, but will try to be as specific and complete as possible. I'm trying to use “lm“ to first estimate parameter values from a set of calibration measurements, and then later to use those estimates to calculate another set of values with “predict.lm”. First I have a calibration dataset of absorbance values measured from standard solutions with known concentration of

Hi,   I am trying to compare two values using "==" operand, please take a look of the following example (I copied ALL what I did here without deleting any line)   >    bb<-1 > cc<-50 > cc==abs(bb+52) [1] FALSE > C<-53 > C<-53 > c<-53 > cc==abs(bb+52) [1] FALSE              I am expecting to see a TRUE here. Then I tried another way,   > abs(1+52)

From: Christian Hesse <mail at eworm.de> Signed-off-by: Christian Hesse <mail at eworm.de> --- log.c | 2 +- sshkey.c | 77 +++++++++++++++++++++++++++++++++++++++++++++++----------------- 2 files changed, 58 insertions(+), 21 deletions(-) diff --git a/log.c b/log.c index 32e1d2e..90c1232 100644 --- a/log.c +++ b/log.c @@ -444,7 +444,7 @@ do_log(LogLevel level, const char *fmt,

Hi, This is a question of a newbie getting into the exciting world of R. I have several dataframes in the same format as NAD: > NAD[1:3,1:3] Sample.Id Main.abs..1 Main.abs..2 148 10a 0.04836 0.04994 167 11a_1109 0.32245 0.36541 173 11b_1109 0.29293 0.32815 What I want to do is to replace the Sample.Id with a corresponding number.The number