Displaying 20 results from an estimated 10000 matches similar to: "Test for treatment effect in a logistic regression"
2009 Feb 06
1
Joint test
Dear All,
I am estimating a Cox proportional hazard model, with several interactions
of the type a*z + a*y + a*x + b*z + b*y + b*x.
I need to know if the first three (the "a"s) are jointly significantly
different from the last three (the "b"s). I have tried several approaches,
but have been unsuccessful.
Here's the model, and the code I came up with, with the obvious
2014 May 12
2
Duda_TEST DE WALD
Buenos días,
Gracias Carlos, siguiendo el ejemplo que comentas, esto es lo que he
introducido en el Scrip de RStudio:
*library(xlsx)*
*library(xlsxjars)*
*library(rJava)*
*library(aod)*
*R<-read.csv("2002.CSV", sep=";", dec=",", header=T)*
*attach(R)*
*group<-gl(2,670,1340,labels= c("AVE", "Log.Imports.Value.in.1000.USD"))*
2012 Nov 30
3
(no subject)
Hello R usuer,
The code given below superimposes a pie diagram on another plot
containing some points. However, I would like to center the pie
diagram on the xy location on the plot, but not on the center. is
there any way to re-center pic diagram.
Any suggestion or better alternative are highly appreciated.
Thank you in advance for your help.
Regards,
Bibke
library(visualFields)
library(car)
2013 Jan 18
3
longitudinal study
Hello R user,
I have a data set from a longitudinal study ( sample below) where
subjects are followed over time. Second column (status) contains info
about if subject is dead or still in the study and third column is
time measured in the week. Here is what I need: if status is not dead
or unknown take the last week, if status is dead or unknown I need to
have corresponding week.
Desired resulst:
2014 May 10
2
Duda_TEST DE WALD
Hola a todos y todas,
Gracias por vuestro apoyo en cantidad de preguntas anteriores, de nuevo os
escribo para compartir una duda:
Estoy trabajando con un modelo bien sencillo, es una regresión simple, pero
me gustaría comprobar la significación estadística de cada uno de los
coeficientes de regresión en el modelo. La idea es hacer un contraste de
hipótesis.
Me he descargado el paquete
2012 Oct 01
3
(no subject)
Hello,
I am a new R -user and request your help for the following problem.
I need to merge two dataset of longitudinal study which has two column
(id and respose) common. when I used merge option to join the datas
side be side, because of the repeated subject id, I got larger data
set which is not accurate.
I would like to connect twi data sets by id and response in such a
way that data are
2012 Apr 05
0
Warning message: Gamlss - Need help
Hi,
I am running a negative binomial model using Gamlss and when I try to include random effect, I get the following message:
Warning messages:
1: In vcov.gamlss(object, "all") :
addive terms exists in the mu formula standard errors for the linear terms maybe are not appropriate
2: In vcov.gamlss(object, "all") :
addive terms exists in the sigma formula standard
2011 Feb 15
0
Delta method using numerical derivatives
Dear all,
Is there a fairly general R implementation of the delta method that uses
numerical derivatives?
I realise that the delta method has been implemented using symbolic
derivatives (e.g. alr3::delta.method, emdbook::deltamethod,
msm::deltamethod and survey:::nlcon), however possibly non-linear
estimators using the delta method with numerical derivatives can be
quite useful (e.g. predictnl
2015 Apr 10
1
RFC: sigma() in package:stats ?
I'm proposing to add something like this to the stats package :
----------------------------------------------------------
### "The" sigma in lm/nls - "like" models:
sigma <- function(object, ...) UseMethod("sigma")
## works whenever deviance(), nobs() and coef() do fine:
sigma.default <- function (object, use.fallback=TRUE, ...)
2011 Nov 01
1
low sigma in lognormal fit of gamlss
Hi,
I'm playing around with gamlss and don't entirely understand the sigma
result from an attempted lognormal fit.
In the example below, I've created lognormal data with mu=10 and sigma=2.
When I try a gamlss fit, I get an estimated mu=9.947 and sigma=0.69
The mu estimate seems in the ballpark, but sigma is very low. I get similar
results on repeated trials and with Normal and
2007 Aug 20
1
rv package, rvnorm function
In an attempt to learn to use the rv package, I have been working
through the examples in Jouni Kerman and Andrew Gelman's "Using Random
Variables to Manipulate and Summarize Simulations in R" (July 4, 2007).
I am using a Dell Precision 380n computer running Gentoo Linux and R
2.2.1 (the latest available through Gentoo's portage/emerge system).
Everything worked well until I
2009 Apr 27
0
VIF's in R using BIGLM
Dear R-help
This is a follow-up to my previous post here:
http://groups.google.com/group/r-help-archive/browse_thread/thread/d9b6f87ce06a9fb7/e9be30a4688f239c?lnk=gst&q=dobomode#e9be30a4688f239c
I am working on developing an open-source automated system for running
batch-regressions on very large datasets. In my previous post, I posed
the question of obtaining VIF's from the output of
2015 Jun 26
1
[R-pkg-devel] Guidelines for S3 regression models
Stephen,
thanks for your effort. The more appropriate list for this discussion is
probably R-devel (as far as I understand it) so I've moved the discussion
there.
Related topics have already been discussed in the past. Specifically, I
remember contributions by Paul Johnson ("rockchalk" package) and John Fox
("effects" and "car" package) as their packages
2012 Oct 14
0
multivariate lognormal distribution simulation in compositions
Dear All,
thanks to Berend, my question posted yesturday was solved succesfully here: http://r.789695.n4.nabble.com/hep-on-arithmetic-covariance-conversion-to-log-covariance-td4646068.html . I posted the question with the assumption of using the results with rlnorm.rplus() from compositions. Unfortunatelly, I am not getting reasonable enough outcome. Am I applying the results wrongfully? The
2024 Sep 05
1
Calculation of VCV matrix of estimated coefficient
sigma(model)^2 will give the correct MSE. Also note that your model
matrix has intercept at
the end whereas vcov will have it at the beginning so you will need to
permute the rows
and columns to get them to be the same/
On Wed, Sep 4, 2024 at 3:34?PM Daniel Lobo <danielobo9976 at gmail.com> wrote:
>
> Hi,
>
> I am trying to replicate the R's result for VCV matrix of
2018 Mar 03
2
lmrob gives NA coefficients
Dear list members,
I want to perform an MM-regression. This seems an easy task using the
function lmrob(), however, this function provides me with NA coefficients.
My data generating process is as follows:
rho <- 0.15 # low interdependency
Sigma <- matrix(rho, d, d); diag(Sigma) <- 1
x.clean <- mvrnorm(n, rep(0,d), Sigma)
beta <- c(1.0, 2.0, 3.0, 4.0)
error <- rnorm(n = n,
2008 Jan 28
0
(no subject)
Hi all
I am trying to generate a normal unbalanced data to estimate the coefficients of LM, LMM, GLM, and GLMM and their standard errors. Also, I am trying to estimate the variance components and their standard errors. Further, I am trying to use the likelihood ratio test to test H0: sigma^2_b = 0 (random effects variance component), and the t-test to test H0:mu=0 (intercept of the model Yij = mu
2018 Mar 03
0
lmrob gives NA coefficients
> On Mar 3, 2018, at 3:04 PM, Christien Kerbert <christienkerbert at gmail.com> wrote:
>
> Dear list members,
>
> I want to perform an MM-regression. This seems an easy task using the
> function lmrob(), however, this function provides me with NA coefficients.
> My data generating process is as follows:
>
> rho <- 0.15 # low interdependency
> Sigma <-
2012 Jul 24
0
[R-sig-ME] lmer() - no applicable method for 'profile' under R version 2.15.1
Hi all,
I was working with the "MEMSS" & "mle4" library's under R version 2.15.1.
apparently some practical functions of do not work under R 2.15.1.
After searching the archives i found a mail thread on this subject,
stating that these problems were partialy solved for "R 2.12.0" but only
for "lmer()" not for "glmer()".
Is someone aware
2018 Mar 04
0
lmrob gives NA coefficients
Hard to help you if you don't provide a reproducible example.
On Sun, Mar 4, 2018 at 1:05 PM, Christien Kerbert <
christienkerbert at gmail.com> wrote:
> d is the number of observed variables (d = 3 in this example). n is the
> number of observations.
>
> 2018-03-04 11:30 GMT+01:00 Eric Berger <ericjberger at gmail.com>:
>
>> What is 'd'? What is