similar to: Dates in C api

Hello, I would like to post the below position on your site. Thanks, Quantitative Analyst/Quantitative Developer MSIM Global Risk & Analysis, Quantitative Research & Model Review group Morgan Stanley Investment Management (MSIM), together with its investment advisory affiliates, has more than 680 investment professionals around the world and approximately $279 billion in assets under

Greetings, I'm learning R and I'm stuck on a basic concept: how to specify a logical condition once and then perform multiple transformations under that condition. The program below is simplified to demonstrate the goal. Its results are exactly what I want, but I would like to check the logical state of gender only once and create both (or any number of) scores at once.

Hi all, this one left me a bit puzzled, as I don't seem to find a function to perform this easily. I must have overlooked the obvious, so sorry in advance. I have a list of dates in numerical format (i.e. 34576), defined as the number of days that passed since january 1st 1900. So I apply the function : > MyDate <-as.Date(34576,origin="1900-01-01") > MyDate [1]

Hi! I've made great progress in my R programming, but I am again stuck on a beginner's problem. I would like to start R with a command line that loads a file, and if possible, executes a function. Can anyone give me an example of how to do this? For example, in lisp, I would say: $ lisp -load toto.lisp -eval '(do-something $PORT)' to load the file "toto.lisp", then

i'm doing a bar plot and there are 16 column variables. is there a way to make the variable names go down instead of across when you do the barplot ? because the names are so long, the barplot just shows 3 names and leaves the rest out. if i could rotate the names 90 degrees, it would probably fit a lot more. or maybe i can use space to make the horizontal width longer ? I looed up ?barlot but

I would like to use POSIX classes to store dates and extract components of dates. Following the example in Spector ("Data Manipulation in R"), I create a date > mydate = as. POSIXlt('2005-4-19 7:01:00') I then successfully extract the day with the command > mydate$day [1] 19 But when I try to extract the month > mydate$mon [1] 3 it returns the wrong month. And

It seems like this should be pretty straight forward, but for some reason the answer escapes me. I have a normal distribution S made up of two normal distributions C and C-bar. I need to find the percentage of the area of S that both C and C-bar occupy. Any suggestions? Thanks in advance, Alan Gibson

I have comma delimited asci data with each row being in the format : 2006-01-24 02:41:24.00011,1.22930000,5,1.22950000,7 . . . . and i'm trying to use read.zoo ( which is similar to read.table ) to read in the data. the data goes all the way out to milliseconds and i can't figure out what to put for the format field. if i put nothing, then read.zoo gets rid of the the whole time and

I did a ?do.call but i don't think i understand it. if a, b,c,d are numeric vectors then could someone explain the difference between do.call("cbind",list(a,b,c,d)) and cbind(a,b,c,d). or point to an archive on it. the return value of cbind is a matrix or dataframe depending on what is sent in but i don't understand wheen it would be useful to use do.call. i realize it

I have two numeric vectors each of length 17 and each is named the exact same way. so obsnum ppppp ppppm pppmp . dot dot dot...... temp1 is 1417 52 63 85 obsnum ppppp ppppm pppmp . dot dot dot...... temp2 is 1213 41 50 97 what i want to have is a resultant matrix with 2 rows and 16 columns where the 16

hello all thanks a lot for the info, I just actually needed to remove that comma in my command line what i had typed in was t.test(temp.matrix[,1:11],temp.matrix[,12:22],paired=TRUE) what i needed to do was t.test(temp.matrix[1:11],temp.matrix[12:22],paired=TRUE) thanks Petr, saw your comment later. nameeta

Hi All, I created a two variable lm() model slm<-lm(y[1:3000,8]~y[1:3000,12]+y[1:3000,15]) I made two predictions predict(slm,newdata=y[201:3200,]) predict(slm,newdata=y[601:3600,]) there is no error message for either of these. the results are identical, and identical to slm$fitted as well. if this is not the right way to apply the model coefficients to a new set of inputs, what is

this one is not a false alarm like my previous message. i have cut and paste the code below so if anyone could run it would be appreciated. basically, my question is why the horizontal axis of the acf plot is labelled with such huge numbers when the labels should be 1 through 10 since may lag.max = 10 ? i looked at the cdoe of acf but it was pretty much beyond me. i think it has something to

I have some time series data like 01/02/1990 0.531 0.479 01/03/1990 0.510 0.522 01/06/1990 0.602 0.604 there is no weekends and holidays. how do I graph them in a single plot that the x-axis is the dates and the y-axis is the time series? Thank you Regards, Jincai Jiang (Office) 212-761-3984 -------------------------------------------------------- This is not an offer (or solicitation

i have the following code below and at the end there are some plotting statements. it actualy looks quite nice when you run it but there is just one strange thing happening that don't know how to fix. the three things being plotted are aggfxdata[,logbidask] which has its own set of times ( it's a zoo object ). rollmeanlogbidask which has a subset of the times that aggfxdata has.

Hello R-user bug seekers are needed! In order to perform these simple tasks you have to use a copy of SPSS and obviously R. The problem is that date conversion of data coming from SPSS gives wrong results, if we follow ?as.POSIXct ## SPSS dates (R-help 2006-02-17) z <- c(10485849600, 10477641600, 10561104000, 10562745600) as.Date(as.POSIXct(z, origin="1582-10-14",

Hi, I have some confusion in applying a function over a column. Here's my function. I just need to shift non-March month-ends to March month-ends. Initially I tried seq.dates, but one cannot give a negative increment (decrement) here. return(as.Date(seq.dates(format(xdate,"%m/%d/%Y"),by="months",len=4)[4]) ) Hence this simple function: > mydate <-

would someone be kind enough to paste the code below into an R session ( ir you can paste it into a file and just source it ) and take a look at it ? I must be doing something wrong but i can't find it. I start out with a zoo object that has 100 elements in it. then, i only want to keep the rows in which the bid and the ask are both grester than zero. ( maybe my logic is wrong there ? ).

Hello! I am aggregating using a formula in aggregate - of the type: aggregate(cbind(var1,var2,var3)~factor1+factor2,sum,data=mydata) However, I actually have an object (vector of my variables to be aggregated): myvars<-c("var1","var2","var3") I'd like my aggregate formula (its "cbind" part) to be able to use my "myvars" object. Is it

Dear Listers, Apologize to pile up on the 'tz' issue in POSIX objects. I have a 'simple' thing on which I must make up my mind but cannot do it from the existing R-help threads. I am currently working on dog telemetry in China, and download time information from GPS collars. I would like to set up the corresponding POSIXxx variables in R to a given time zone. Eg Pekin