similar to: Question

Dear All I can not download R for Linux. I do not know which file I should install? Best Regards, Soheila

Dear All Is there any function for "median test" in R? Best Regards, Soheila [[alternative HTML version deleted]]

Dear All How can I transform 1 column to 2 columns in R? 211217_s_at GO:0005249 211217_s_at GO:0005251 211217_s_at GO:0005515 211217_s_at GO:0015271 211217_s_at GO:0030955 211217_s_at GO:0005249 211217_s_at GO:0005251 211217_s_at GO:0005515 211217_s_at GO:0015271 211217_s_at GO:0030955 Best Wishes, Soheila [[alternative HTML version deleted]]

var1 var2 var3 var4 var5 var6 var7 var8 var9 var10 gold 2 3 1 2 4 0 1 4 4 3 2 2 4 2 4 3 4 2 4 4 4 2 3 3 0 0 4 1 0 2 4 4 2 1 4 0 3 2 0 0 2 4 4 2 3 4 0 2 2 0 0 0 3 4 2 2 2 3 2 2 0 0 0 2 4 2 2 4 1 1 2 0 0 3 3 3 2 3 4 1 4 0 0 0 0 3 4 2 3 1 0 2 2 1 0 2 3 3 2 0 3 1 1 1 1 2 1 2 3 2 1

Dear All I want to chose just spacial columns in R. (read table) data1<- read.table("/home/Documents/data.txt",header=F,sep = "\t", as.is =F) data.2<-data1[sub.data[,1],] The dimension of data.2 is correct but my data are transformed NA head(data.2) V1 V2 V3 V4 V5 V6 V7 V8 V9 V10 V11 V12 V13 V14 V15 V16 V17 V18 V19 V20 V21 V22 V23 V24 NA <NA> NA NA NA

Dear All I want to arrange our output in 3 columns in R. Example: N 04320 03010 00514 00604 00563 03430 03022 V 22.000000 0.000000e+00 15.0000000 15.0000 13.0000 1.300000e+01 51.0000000 p 0.640625 2.910383e-11 0.4257812 0.4375 0.6875 3.356934e-04 0.2434998 N 03060 04140 03050 00562 00565 V 20.0000000 62.00000000 273.0000000

Dear All I have 54000 plots in R, How can I observe them? If I‌ have to save them one-by-one? Soheila [[alternative HTML version deleted]]

Unable to resolve error in seq.default(which(text == "")[1] + 1, length(text), 1): wrong sign in 'by' argument I am trying to run this code get.msg <- function(path) { con <- file(path, open = "rt", encoding = "latin1") text <- readLines(con) # The message always begins after the first full line break msg <- text[seq(which(text ==

Dear ALL I have this function in R: func_LN <- function(data){ med_ge <- matrix(c(rep(NA,nrow(data)*ncol(data))), nrow = nrow(data), ncol=ncol(data), byrow=TRUE) T <- matrix(c(rep(NA,length(n)*ncol(data))), nrow = length(n), ncol=ncol(data), byrow=TRUE) Tdiff<- matrix(c(rep(NA,length(n)*ncol(data))), nrow = length(n), ncol=ncol(data), byrow=TRUE) T1<- c(rep(NA,ncol(data)))

Dear All, Hello! I have some questoins in R programming as follows: Question 1- How to take the integral of this function with respect to y, such that x would appear in the output after taking integral. f(x,y)=(0.1766*exp(-exp(y+lnx))*-exp(y+lnx))/(1-exp(-exp(y+lnx))) y in (-6.907,-1.246) It is doable in maple but not in R. At least I could not find the way. p.s: result from maple is:

--- On Tue, 15/7/08, haani hanni <maaryam_khan@yahoo.com> wrote: From: haani hanni <maaryam_khan@yahoo.com> Subject: how i can install Rgraphviz in R2.7.1 To: "Nabble" <support@nabble.com> Cc: r-help-request@r-project.org Date: Tuesday, 15 July, 2008, 1:39 PM hello i am a new user of R.i have window XP Proffessional in my P.C.i wanted to make the graphs of my

Hi dear, I want to estimate d.f for Chi-squared distribution: est.chi[i,]<-c( fitdistr(as.numeric(data2[,i]),"chi-squared",start=list(df=1))$estimate)Warning message:In optim(x = c(7.86755, 7.50852, 7.86342, 7.70589, 7.70153, 7.58272, : one-diml optimization by Nelder-Mead is unreliable: use "Brent" or optimize() directly Who can help me to solve this problem? Best

Hello! Can someone please help me in building debug version of klibc ? I've cloned git://git.kernel.org/pub/scm/libs/klibc/klibc.git , but failed to build it with debug info added "-g" to HOSTCFLAGS in Makefile, but $ make -j KLIBCKERNELSRC=`pwd`/../linux-2.6/usr still strips every debug symbol , and i'm failed to change scripts/Kbuild.klibc and Makefile to remove strip

Dear all, I''m trying to write a function, that will take as an argument, some aligned genome sequences, and using a sliding window, do pairwise comparisons of sequence similarity. Coding the sliding window I think I can manage but what I''m trying to get to grips with is getting it so as every pairwise comparison is made, no matter how many genomes are added, from 3 to N. So if

Dear sirs, I have tried to find a command to fit(plot) a regression line but I haven't found any command on the html.help. My question is if I am using a regression for instance reg<-lm(y~x) and I would like to make a regression line, to see how well my data is fit. Can you please help me with this?? Yours Sincerely Soheila Zad

I'm looking to switch to Mac platform. Anyone had any experience with that? I'm expecting on a power G4 laptop later this week.... hope R behaves... -- dok

Hola Javier, Intenta los siguientes cambios g4 <- function(codigo_llega, n_caracteres){ codigo_llega <- as.character(codigo_llega) if(n_caracteres == 6) res <- substr(codigo_llega, start=0, stop=4) else res <- codigo_llega res } g4 <- Vectorize(g4) x <- c('Jorge Velez','Javier Marcuzzi','Daniel Merino','Susana deus Alvarez', 'Carlos

Hi, Has anyone had success using a TE410P card in an HP-Compaq DL380 G4 server? For me the card is detected fine, but the system just never sees an interrupt from the card. I've tried everything I can think of. The card definitely works. Its Fedora Core, but we also tried a stock 2.6.10 kernel. We tried with and without Hyperthreading, with "noapic", we disabled all the

This is an operating system question, but it is with the intent of using R on that operating system. I have an ibook G4 Power PC that I am going to install linux on. Is there a better, worse, or perhaps easier (I am a linux newby migrating from mac) distribution that I should look at. I appreciate your help. I didn't post this in the sig-mac because I don't know if it fits there better

Hi I am using the following script to average a set of data 0f 62 columns into 31 colums. The data consists of values of ln(0.01) or -4.60517 instead of NA's. These need to be averaged for each row (i.e 2 values being averaged). What I would I need to change for me to meet the conditions: 1. If each run of the sample has a value, the average is given 2. If only one run of the sample has a