similar to: Trust: Samba or windows problem?

I need a pointer to what Fine Manual I should go read to set up my netbios name resolution, because all my attempts to use netbios names are being resolved against dns ... I have one subnet (192.168.2/24), with several Fedora 11 machines and several Windows XP machines, and a couple SMB/CIFS NAS units which also share printers. No domain, it's all just a workgroup. The WinXP machines

I'm not sure who is responsible for quantile(), but I assume they read this list. Ivan Frohne and I have produced a revision of the quantile.default() function which enables the computation of alternative sample quantile definitions. The code and .Rd file are attached. This enables the user to produce quantiles that are equivalent to those in various statistics package. There is a type

I got a vector of probabilities like, probs<-c(0.001,0.5,0.02,1,.....) Is there any nice and easy builtin function to get the number of occurences within some specified probabality range. Like with 2% it would be occur[1] = sum(probs[probs>0&probs<0.02]) occur[2] = sum(probs[probs>0.02&probs<0.04]) ... occur[50] =sum(probs[probs>0.09] & probs<1) (If it was a

Habría que buscar la vuelta, yo no lo se, pero posiblemente lo siguiente da una pista. Nota: al mismo código le sume una línea al final datos<-c(2,3,4,5,6,7,8) quantile(datos) quantile(datos,probs = c(0.25, 0.75, 0.85, 0.90, 0.95)) as.matrix(quantile(datos,probs = c(0.25, 0.75, 0.85, 0.90, 0.95))) as.data.frame(quantile(datos,probs = c(0.25, 0.75, 0.85, 0.90, 0.95))) # ¿ y si solo solicita

Full_Name: Clay B Version: 2.5.0 (2007-04-23) OS: Solaris Nevada Build 55b Submission from: (NULL) (65.101.229.198) I find that running this script causes R to segfault reliably. However, running just for one system at a time (modifying the for loop updating iter to run just for a system at a time works). The system is a Sun W2100z with 12 GB of ram, and R segfaults using only around 360 MB of

hi rowland *OK, you were asked 'Was this pc a member of any NT4 Domain in the past?'You replied with:'nope ..'* well all the pc who had trust relationship problem is new PC with windows 7 or earlier .. they never connected to PDC in clear OS i think i need to tell you my story 3 years ago when i upgraded the PDC to samba4 AD , maybe it related or maybe it will be out of topic

Hello all, Consider the following problem: There is a matrix of probabilities: > set.seed(1) > probs <- array(abs(rnorm(25, sd = 0.33)), dim = c(5,5), dimnames = list(1:5, letters[1:5])) > probs a b c d e 1 0.21 0.27 0.50 0.0148 0.303 2 0.06 0.16 0.13 0.0053 0.258 3 0.28 0.24 0.21 0.3115 0.025 4 0.53 0.19 0.73 0.2710 0.656 5 0.11 0.10 0.37 0.1960

Hi, I have a data frame containing a column of human judgments, some of which are missing: > pr[3] label 1 4 2 4 3 4 4 4 5 NA 6 3 7 3 8 3 9 3 10 NA 11 NA 12 NA 13 2 14 2 15 2 16 NA 17 1 18 -1 19 -1 20 -1 Accompanying this is a matrix containing multinomial probabilities for the missing values, note that they

Gracias, Javier. Es lo que hice, en efecto, para salir del paso. Requerir de a uno por vez. El problema es que no entiendo por qué debo hacerlo así si quantile es una función más, como cualquier otra, que podría utilizar en un tapply (porque necesito los datos según provincia, que obviamente es un factor) El 8 de julio de 2013 17:25, Marcuzzi, Javier Rubén <

Dear r-help, Unfortunately I cannot find in the documentation what determines ranges of a 'box' in the box-and-whisker plot. It is said in "Simple R" (http://www.math.csi.cuny.edu/Statistics/R/simpleR) that they are 1st and 3rd Qus usually. I tried to add to boxplot lines with (quantile(x,probs=0.25)), but lines do not coincide with edges of boxes.

Hi all, I am running into a snag using quantile function in stats. Basically, I don't understand why the loop below throws the error that it does. test.data <- rnorm(1000, 0, 1) for (i in seq(0.00001, 0.001, 0.00001)){ test <- quantile(test.data, probs=seq(0,1,i)); print(i); } It runs fine from 1e-05 to 0.00024, but then throws the error Error in quantile.default(test.data,

Estimado Mauricio Monsalvo Le paso una idea, no es un código muy lindo que digamos, pero al correrlo seguramente se dará cuenta de mi sugerencia. datos<-c(2,3,4,5,6,7,8) quantile(datos) quantile(datos,probs = c(0.25, 0.75, 0.85, 0.90, 0.95)) as.matrix(quantile(datos,probs = c(0.25, 0.75, 0.85, 0.90, 0.95))) as.data.frame(quantile(datos,probs = c(0.25, 0.75, 0.85, 0.90, 0.95))) # ¿ y si solo

Le 11/04/2017 ? 18:11, Jonathan Billings a ?crit : > Maybe we should just jump right to the end that we always have each > time this comes up. systemd is the death of linux and you're leaving > for FreeBSD/devuan/whatever. Lets just move along now. I've been using CentOS 5.x almost exclusively for a few years on both servers and desktops, and then I went back to Slackware Linux

Dear, I want to make an application to calculate quantile within a For() I tried the following without success: ej. date p_val <- matrix(sample(10, 1000, replace=TRUE), 200,5) test 1 rr <- paste("p_val$",names(p_val[1]), sep="") quant <- quantile(rr, probs = c(0, 10, 20, 30, 40, 50, 60, 70, 80, 90, 100)/100, na.rm=FALSE, type=1) test 2 rr <-

Hi, I have reconstructed ancestral character states on a phylogeny using MuSSE in the diversitree package and plotted the character state probabilities as pie charts on the nodes. I would, however, like to colour the character states of my extant species, i.e. the tip labels, the same colours as my pie charts, such that all species in state 1 are e.g. blue, species in state 2 red and species in

Hi, R users I am trying to use EM algorithmto estimate a latent class model of discrete choice. The basic model is a logit model which has two variables X=(X1,X2) and the utility is defined as v = Beta*X. There are 3 classes of individuals each has its own Beta values, so Beta is a 3*2 matrix. For each individual, (there are 1000), he make a choice between two randomly generated choice

Greetings, all: I'm having trouble working out a printing problem between my Samba box, and my Windows 2000 client. Here's the background: Network: Home network with a Slackware 8 box running Samba, 1 Windows 2000 client, 1 Windows 98 client, and a LEAF Project firewall providing Internet access. The Samba server should only be available to local clients. Systems: Slackware box:

Hi all, I'm looking for an analytic method to obtain the PDF & CDF of the sampling distribution of a given correlation (rho) at a given sample size (N). I've attached code describing a monte carlo method of achieving this, and while it is relatively fast, an analytic solution would obviously be optimal. get.cors <- function(i, x, y, N){ end=i*N

If you go here, this doc will tell you how to join a winXP Pro machine to a samba domain. http://hr.uoregon.edu/davidrl/samba/samba-pdc.html#JOINDOMAIN Hope that helps.... Dominic Iadicicco --- Patrick Flohr <Flohr.P@t-online.de> wrote: > Date: Wed, 23 Jul 2003 13:43:48 +0200 > From: Flohr.P@t-online.de (Patrick Flohr) > To: samba@lists.samba.org > Subject: Re: [Samba]

On Mon, 21 Aug 2017 22:15:58 +0700 zhia chandra <bentunx at gmail.com> wrote: > hi rowland > > > *OK, you were asked 'Was this pc a member of any NT4 Domain in the > past?'You replied with:'nope ..'* > > well all the pc who had trust relationship problem is new PC with > windows 7 or earlier .. they never connected to PDC in clear OS > > i