similar to: How to be taken out of the queue?

I'm trying to set up queueing on my system and for the most part it works fine. However, I'm trying to give the user the ability to break out of the queue. Putting the "H" option into queue() doesn't seem to work. That seems to hang up from the extension that was being dialed and then after the delay start ringing them again. Looking at the mailing list archives, others

We tried to remove vq poll from wait queue, but do not check whether or not it was in a list before. This will lead double free. Fixing this by switching to use vhost_poll_stop() which zeros poll->wqh after removing poll from waitqueue to make sure it won't be freed twice. Cc: Darren Kenny <darren.kenny at oracle.com> Reported-by: syzbot+c0272972b01b872e604a at

We tried to remove vq poll from wait queue, but do not check whether or not it was in a list before. This will lead double free. Fixing this by switching to use vhost_poll_stop() which zeros poll->wqh after removing poll from waitqueue to make sure it won't be freed twice. Cc: Darren Kenny <darren.kenny at oracle.com> Reported-by: syzbot+c0272972b01b872e604a at

Hello group, I tried a lot to enlarge the frequency (i.e. more announces, low wait between). according to config, every 30 seconds the announcement should take place. In fact, the first periodic announce is done after 2 minutes? What is my fault? Thank you Regards Paul # zypper if asterisk Loading repository data... Reading installed packages... Information for package asterisk:

Hi. I was wondering how can I make incoming calls to wait if the phone operator is busy. I've 8 incoming lines, with 30 extensions. What I need is if the operator is busy with call nr #1 , the new incoming call waits until the op. is free. Looking into app_queue seems the way to go. So I want to ask if I'm right or wrong: I set up only a queue , is to say operatorq, where the only member

On Tue, Mar 27, 2018 at 08:50:52PM +0800, Jason Wang wrote: > We tried to remove vq poll from wait queue, but do not check whether > or not it was in a list before. This will lead double free. Fixing > this by switching to use vhost_poll_stop() which zeros poll->wqh after > removing poll from waitqueue to make sure it won't be freed twice. > > Cc: Darren Kenny

Hi list, I'd like to have the callers to listen to the advertisement (music on hold) before the agents answer them. So, I have wrapuptime=10 in queue.conf, but the call still goes straight to the agents without delay. Here's my queue.conf: [general] persistentmembers = yes [738] musiconhold = empty ;musiconhold = default ;announce = q-738 ;strategy = ringall strategy = rrmemory

Has anyone used the H option for Queue() with Callback queues? I want customers in my queues to be able to jump out to voicemail when they get tired of waiting, but in my setup when I pretend to be a customer and press '*' [when I am waiting in the queue] I see the message 'User hit * to disconnect call.' but then just jump out to the outer loop where queued callers wait to

I am having a problem with the Call Queue Feature. If I let a user into the Queue prior to an agent being available for them to take the call, they experience the following: 1) they hear that they are the first in line 2) when the agent finally logs in (the caller on hold in the queue is sent to the users phone) 3) the AGENT is still in the login phase hearing that they are "successfully

On 2018?03?27? 17:28, Darren Kenny wrote: > Hi Jason, > > On Tue, Mar 27, 2018 at 11:47:22AM +0800, Jason Wang wrote: >> We tried to remove vq poll from wait queue, but do not check whether >> or not it was in a list before. This will lead double free. Fixing >> this by checking poll->wqh to make sure it was in a list. > > This text seems at odds with the code

Hi to all, I have a question about the callerid (msn number) off calls comming FROM a queue. This is my setup: - ISDN using zap (zaphfc) - Incomming calls arrive in a queue - One of the members of the queue is my cell phone... member => Zap/g1/XXX73XX19 (X to protect my privacy ;-)) The problem is the call from the queue to my cell phone. In a dailplan i can set the outgoing msn using

Hi, I am getting the following error when I'm running jags.model() > meas1 <- jags.model(file="measurement.bug",data=dat.test) syntax error, unexpected '}', expecting ',' or ')' Error in jags.model(file = "measurement.bug", data = dat.test) : Parse error on line 1 Below is my JAGS model. Please cc me as I'm a digest subscriber if

Hi folks, I'm forwarding this to the list as my email to nita was about getting her code to the list. Additionally, I'm running Linux and have no experience with WinBUGS. Jim -------- Original Message -------- Subject: Re: [R] Help with winbugs code Date: Thu, 23 Jun 2011 16:49:33 +0700 From: nita yalina <tayalin at gmail.com> To: Jim Lemon <jim at bitwrit.com.au>

Greetings, I am running a factor analysis model in rjags and have received the following error Error parsing model file: syntax error on line 5 near "" Line 5 is model { Here is my syntax. Any insight would be greatly appreciated. require(rjags) modelstring = " model { for (i in 1 : nData) { for (j in 1 : nIndicators) { y[i,j] ~ dnorm(mu[i,j],psi[j]) ephat[i,j] <-

Dear friends. On p 95 in 3. ed. MASS a zero-truncated Poisson distribution is analyzed. I understand the probability distribution and expected mean. The Newton iteration scheme is Lam(m+1)=Lam(m)-[Lam(m)-Ybar(1-exp(-Lam(m))]/[1-Ybar*exp(-Lam(m)], and I suppose the latter part should be f(Lam(m))/f ' (Lam(m)) and f(Lam(m)) is Lam(m)/(1-exp(-Lam(m)), right ? But then f ' (Lam(m)) is

Hi, I've been trying here to install Rmpi on an SGI IA-64 machine with 64 processors, running SuSE Linux Enterprise Server 9, R 2.4.0 and lam-mpi 7.1.3. While I've read of similar problems on this list, I think I've got an entirely new set of error messages to contribute (see below). I'm not sure what the actual error is and what the @gprel relocation message is about. Any help

Hello all, I've been working on a package to do various things related to the Conway-Maxwell-Poisson distribution and wanted to be able to make fast random draws from the distribution. My R code was running quite slow so I decided to give Rcpp a bash. I had used it before but only for extremely basic stuff and always using inline. This time I decided to give making a proper package a go.

A yum update to lam 7.1.4 (from 7.1.2) broke Rmpi for me this last week and quite a few changes were needed to repair this, so I'm reporting here in case it helps others. This was an x86_64 system - adjust 'lib64' suitably for 32-bit systems. There seems to me to be major organizational changes for a 'patchlevel' update to a setup that previously worked out of the box.

I can also confirm that the latest https://hub.docker.com/_/r-base has the correct behaviour. On Tue, May 26, 2020 at 5:05 PM Kenny Bell <kmbell56 at gmail.com> wrote: > I was actually able to reproduce this on a relatively fresh install of > 18.04 (a virtualbox). Paul, did you run apt update && apt upgrade before > trying to reproduce? > > On Tue, May 26, 2020 at

Hi there, I wrote a function that wraps MASS::boxcox as: bc <- function(vec) { lam <- boxcox(lm(vec ~ 1)) lam <- lam$x[which.max(lam$y)] (vec^lam - 1)/lam } When I invoke it as: > x <- runif(20) > bc(x) Error in eval(predvars, data, env) : object 'vec' not found I have googled, and rewrote the above function as: bc <- function(vec) { dat <<-