similar to: Help with stripplot

-----Original Message----- From: Ghosh, Sandeep Sent: Thursday, June 30, 2005 5:43 PM To: 'Berton Gunter' Subject: plot legend outside the grid Thanks for the pointers... I managed to get everything to look and feel the way I want except for the legend to plot outside the grid... Thanks for the note on the par, but I'm not able to it to plot outside the plot grid.. dataFrame <-

Thanks Bert for all the help. I got the legend figured out Friday but left early becoz of long weekend so didn't get a chance to reply.. I modified the plot margins a little bit and Here's what I finally had... par(mar=c(c(10, 6, 6, 10) + 0.1)); par(xpd=FALSE); with (dataFrame, stripchart(marbles_buried ~ genotype, method="jitter", vertical=TRUE, col = c('blue',

I want to make a 2x2 plot on a single page, using stripplot() and boxplot(). I tried the following two alternatives with mfrow() and layout(), but none of them worked. library(lattice) par(mfrow=c(2,2)) boxplot(X1 ~ Y, data=tst1, horizontal=T, las=1) boxplot(X2 ~ Y, data=tst1, horizontal=T, las=1) stripplot(Y ~ X1, data=tst1) stripplot(Y ~ X2, data=tst1) par(mfrow=c(1,1)) nf <-

For the following example, > library(lattice) > df<-data.frame(i=1:100,p=runif(100),id=rep(c('a','b'),100)) > summary(df[,'p']) Min. 1st Qu. Median Mean 3rd Qu. Max. 0.01165 0.33580 0.57520 0.53290 0.74540 0.98610 > stripplot(p~i|id,df) The plot that is output is as expected with the exception that the values are scaled by a factor of 100 in

I needed to compute a complicated cross tabulation to show weighted means and standard deviations and the only method I could get that worked uses a series of nested for next loops. I know that there must be a better way to do so, but could use some assistance pointing the way. Here is my working, but inefficient script: library(Hmisc) rm(list=ls()) load('NHTS.Rdata') day.wt <-

Hi, I have binary (0,1) data for a trait as my response variable, and a dependent variable, genotype, with three classes (AA, AB, BB). I would like to plot this data so that across the three genoytpes, even though the points are all either 0 or 1, i want them to stack up or be seen using 'jitter'. So far I have been able to do this using xyplot {lattice} (code below) but could not get

hi, I want to plot a dotplot graph but unfortunately R does not have it any more. It suggest to use either the stripchart or the dotchart and i prefer to play around with the stripchart graph. Sadly, the result is not like i want where I'm actually wants the plots/points were scattered around the x-axis. Plus, from the results shows that and the x-axis gave a very large scale, i.e

Hello, I am trying to plot age distribution data for a certain condition that runs in families. Below is a simplified view of the dataset, i.e. in this case there are four families, each line corresponding to one individual with age at diagnosis and sex. > famdata family age sex 1 fam1 2.1 f 2 fam1 2.3 f 3 fam1 1.0 m 4 fam2 7.3 f 5 fam2 4.1 f 6 fam2 1.2 f 7

Hi I'm doing a xyplot and I wand to reduce the number of tick marks in the x axis. My x axis are month and I want to reduce the 12 tick marks to 4. I used the scales argument but it doesn't seem to work, althougth it works on y axis if I use scales=list(tick.number=4).

Hi All. I have the commands below to create a stripchart/plot. I was hoping to color the points in the plot by yr, and use a symbol that varied with resp. However, the outcome makes it appear as though the point by point col and pch data is not being passed properly. Any suggestions? And truthfully, I?d rather be doing this with Lattice, but I?ve tried several variations of stripplot and can?t

Hi everybody, I'm a new member of the list. I'm just starting to use R. I'm looking for information about stripcharts. I didn't find a lot on the web. Outside http://www.maths.lth.se/help/R/.R/library/graphics/html/stripchart.html there isn't much I found. I'm trying to create three vertical stripcharts "glued" to one another. I succeeded to create one

#Hello, #I have a question about obtaining results from a loop I have written. #Below is a sample of individual genotypes from a genetic question I am working on called "P.genotype.sample ". P.genotype.sample<-matrix(10,10,10) P.genotype.sample[,1]<-c(2,2,1,5,1,1,5,6,1,3) P.genotype.sample[,2]<-c(6,3,3,6,8,1,6,7,2,3) P.genotype.sample[,3]<-c(2,2,2,3,3,2,2,2,3,3)

#Hello, #I have would like to paste a single column of a matrix # in pair wise fashion with other columns based upon # even and odd column numbers. # I can do it in a very clunky fashion and I know there # must be a better way. below is a sample matrix and my extremely # clunky code that gets the job done for a small matrix, but i plan to # do this on a much grander scale. any help would be very

Hi. I was wondering if anyone might have some suggestions about how I can overcome a problem of "iteration limit reached without convergence" when fitting a mixed effects model. In this study: Outcome is a measure of heart action Age is continuous (in weeks) Gender is Male or Female (0 or 1) Genotype is Wild type or knockout (0 or 1) Animal is the Animal ID as a factor

Hello, My R skills are somewhere between novice and intermediary, and I am hoping that some of you very helpful forum members, whom I've seen work your magic on other peoples' problems/questions, can help me here. I have a matrix with the following format: (i) individual plants comprising many different genotype groups (i.e., a plant is genotype 1 or genotype 2 or genotype 3, etc). The

Hi, I am conducting an association analysis of genotype and a phenotype such as cholesterol level as an outcome and the genotype as a regressor using multiple linear regression. There are 3 possibilities for the genotype AA, AG, GG. There are 5 people with the AA genotype, 100 with the AG genotype and 900 with the GG genotype. I coded GG genotype as 1, AG as 2 and AA as 3 and the p-value for the

Dear R users, I have a problem with something called "NaNs" in a nested mixed model. The background is that I have studied the number of insect nymphs emerging from replicated Willow genotypes in the field. I have 15 replicates each of 4 Willow genotypes belonging two 2 Willow species. Now I want to elucidate the effect of Willow genotype on the number of emerging nymphs. Previously I

Hi, Could someone tell me if this is the correct model syntax for the following dataset: lme(height~treatment+genotype+treatment*genotype,drought,random=~genotyp e) The dataset has two factors: one fixed - treatment, and one random - genotype. I need to test the effect of both factors to identify their significance. There are multiple (but not equal) replicates at each level of genotype (the

Dear Sir, I am attempting to get a Broad Band Modem working on: sony# uname -a FreeBSD sony.family.hom 6.2-PRERELEASE FreeBSD 6.2-PRERELEASE #2: Tue Dec 19 16:55:50 EST 2006 root@sony.family.hom:/usr/obj/usr/src/sys/SONY01 i386 The device is a Sprint PC5740 pc card. When I perform a "man umodem" the card is listed (vendor = Curitel) UMODEM(4)

Hello R Users, I am investigating the basic use of the LME function, using the following example; Response is Weight, covariate is Age, random factor is Genotype model.lme <- lme (Weight~Age, random=~ 1|Genotype) After summary(model.lme), I find that the estimate of Age is 0.098 with p=0.758. I am comparing the above model with the AOV function; model.aov <- aov (Weight~Age + Genotype)