similar to: Stepwise Discriminant... in R

I don't understand which is the problem Could you help me please? Thanks in advance Marta > str(data_indiciN2) 'data.frame': 200 obs. of 36 variables: $ gruppo: Factor w/ 2 levels "0","1": 2 2 2 2 2 2 2 2 2 2 ... $ I001N2: num 19.32 8.22 28.35 7.24 14.7 ... $ I002N2: num 2.92 2.54 0.11 1.6 7.12 ... $ I003N2: num -22.362 -0.222 -19.291

Dear all, I have some additionale question concerning the spgrass6 package. * When you set a region in GRASS, does the readGRASS6 function in R only load data contained in the zoomed region or the whole map ? * When you have a MASK map in grass, does the readGRASS6 function in R only load data contained inside the MASK area ? Could this be the problem ? Thanks, Jessica

I have used the greedy.wilks to stepwise discriminant analysis, but it doesn't work with my dataset. I don't understand which is the problem Could you help me please? Thanks in advance Marta > str(data_indiciN2) 'data.frame': 200 obs. of 36 variables: $ gruppo: Factor w/ 2 levels "0","1": 2 2 2 2 2 2 2 2 2 2 ... $ I001N2: num 19.32 8.22 28.35 7.24

Well im thoroughly frustrated after 25 minutes of checking and rechecking my path. What do i not know about loading a mdb that is keeping me from loading my data. i have loaded the Hmisc library and pointed it too my data using mdb.get and continue to get the following error. Error in system(paste("mdb-tables -1", file), intern = TRUE) : 'mdb-tables' not found Which i

Hi all. I have the problem, that the labels from a factor variable in a tree object, (more exact, the node - labels) is labeled in a plot with letters a,b,c... instead of the numerical levels. when I run >labels(tree.object) It gives me the correct labels (the problem concerns 'landuse': [1] "root" "landuse:1,2,3,4,5,6,7,8,9,10" [3]

Dear forum members, hope you can understand my unprofessionell English. I have never been working with RStudio before (even not with R), so I immediately need some help, because I want to carry out an automated multiple stepwise linear regression between temperatures and different surface parameters. Data can be found in several .xls- or .csv-files within one folder. Files are named

Hi! I am trying to make a stepwise regression in the multivariate case, using Wilks' Lambda test. I've tried this: > greedy.wilks(cbind(Y1,Y2) ~ . , data=my.data ) But it only returns: Error in model.frame.default(formula = X[, j] ~ grouping, drop.unused.levels = TRUE) : variable lengths differ (found for 'grouping') What can be wrong here? I have checked and all variables

en fait je vous renvoi ce message car maintenant la taille de la police change au bout de 500 lignes environ, alors que j''avais reussi à garder la taille jusqu''à environ 5000 lignes. Je ne comprend pas. Est-ce que c''est instable? le bout de code que vous m''avez envoyer ne marche pas. merci Sebastien _______________________________________________ wxruby-users

Hi all, is it possible to do stepwise discriminant analysis (linear amnd non-linear) in R? If yes- which package does it|? Thanks Janine -------------------------------------------- "El gesto y la palabra son el pensamiento del hombre" Isabel Allende Janine Illian lecturer in statistics SIMBIOS School of Computing University of Abertay Dundee Bell Street Dundee, DD1 1HG Scotland,

Dear R users, I have some environmental variables and I need to find the best combination of them in order to separate two main groups (coded 1 and 2). I have performed a discriminant analysis using the stepclass function as a method for selecting the most relevant environmental variables. The problem is that this function includes a parameter (start.vars) and my results change a lot when I

Dear R-users, I'm wondering how to obtain Wilks-lambda values when discriminant analyses have only one discriminant function (i.e. 2 categories to discriminate between). The use of manova(predictions~groups, test="Wilks") asks for multiple response and the use of anova(lm(predictions~groups), test="Wilks") simply does not consider the last term. (The alternative

bonjour, je rencontre quelques soucis au niveau de l'utilisation des fonctions arima.forecast/predict; en effet elles sont dites inconnues alors que j'ai bien install?? et charg?? le package "ts". Aussi, j'aimerai savoir comment visualiser le graphique des pr??visions avec arima et celui des donn??es brutes dans la m??me fen??tre. Tout en vous souhaitant bonne r??ception

Bonjour, je voudrais savoir si il est possible de désactiver le bouton de fermeture en haut a droite (le bouton rouge avec une croix blanche), sans se servir de "FRAME_NO_WINDOW_MENU", car j''ai besoin des autres boutons. Merci. Sebastien _______________________________________________ wxruby-users mailing list wxruby-users@rubyforge.org

Dear R users: Could you please help me out how to use R to get and interpret Standardized discriminant functions and structure coefficients for sex, Degree_Program, and Enrol_USM Please find the data file at: http://www.usm.maine.edu/~aaboueissa/Rhelps/Rhelps.html data files are (xls file: dataforRxls or txt file: dataforRtxt) Output looks like this table. Standardized

Hello. Here is my R code. I used the functional data . Now I need to use the functional data by applying the kernels instead of the xi, yi functions. Bonjour. Voici mon code en R . J'ai utiliser les donn?es fonctionnelles . Maintenant j'ai besoin d'utiliser les donn?es fonctionnelles en appliquant les noyaux ? la place des fontions xi, yi library(MASS)

Hello, I''m trying to implement something like the following scenario. I''ve got "Alloys" (blends of metals), "Metals" and "Percentages" I want to implement this using a join model, not using a has_and_belongs_to_many relationship. (If i''m wrong about that, let me know). Basically, i have the following tables: Metals id name Alloys

Bonjour, Quelqu''un envoie des sms à partir de son application? Vous avez des fournisseurs à conseiller. Le plus simple c''est d''envoyer à partir d''un email puis le fournisseur transforme ça en sms. Niveau tarif ça va du simple au triple apparement. Merci pour vos suggestions -- Posted via http://www.ruby-forum.com/. -- You received this message because you

Lo folks, I got a little question. Ive set up samba 3.0.0 + RH 8. And since ACL within samba only works on share niveau i wanted to implement POSIX ACL. I was thinking what is the difference between "full" access and "change" on a NT4 server. As far as i could think the difference is that "full" acces can delete a file and "change" can only change it. So i

Complete event id of : > But still, events log show a warning about kerberos ticket from LsaSrv > source and right after a permission denied on GPT.ini And a getfacl of the problem GPO SID please, i'll check. And a output of ipconfig /all on the problem pc. And question, dedicated IP or dhcp IP? Greetz, Louis > -----Oorspronkelijk bericht----- > Van: samba

Dear R-users, I need some help concerning the plotting of dendrograms for hierarchical agglomerative clustering. The agglomeration niveau of each step should be displayed at the branches of the dendrogram. For this I need the x/y coordinates of the branch-agglomerations of the dendrogram. The y-values are known (the heights of the agglomeration), but how can I get the x-values? > mydata