similar to: Getting tripped up on NAs in trying to create new variable

Hello, R-helpers. I have a data frame below called df. I want to add a variable c, based on the following logic: if df$a < 5 then the first two times this condition is met place a 1 in c, the next two times this condition is met place a 2 in c and when the condition is not met let c equal df$b. The result would look like, dfnew, shown below. a <- rep(c(3,5,7), 4) b <- rep(c(NA,1,2),

Hello, I am unable to update packages. I am running R version 2.8.1 (2008-12-22) under VISTA. When I start R I get the following error: Type 'demo()' for some demos, 'help()' for on-line help, or 'help.start()' for an HTML browser interface to help. Type 'q()' to quit R. Error in library(package, lib.loc = lib.loc, character.only = TRUE, logical.return = TRUE,

This is a "long" way; i.e., not necessarily efficient: > qs2 [1] 2 1 1 4 4 4 1 1 1 4 2 4 3 1 4 3 3 2 4 3 > qs9 [1] 4 4 1 3 4 3 1 3 1 4 1 2 3 3 4 4 1 4 2 3 > decision <- function(a, b) { + if (a == 1 || b == 1) return(1) + if (a == 2 || b == 2) return(2) + if (a == 3 || b == 3) return(3) + if (a == 4 || b == 4) return(4) + NA + } > mapply(decision,

Hello R-Masters, I have a list 's' with three elements, as shown below. I want to recode a.a, a.a2, and a.a3 to NA if the value in a.a is less than 3. I reivewed my Modern Applied Statistic Book, the online help and did some searching of R-help on the internet. I explored unlist and as.list.data.frame in an attempt to isolate the third element of the list s, but this was not helpful.

I will be involved with an analysis based on a file that will be roughly 25 meg. Assuming I have enough memory, is their any limitations to using R on a file this large. Thank you, Gregory L. Blevins Vice President, Partner The Market Solutions Group, Inc. gblevins at marketsolutionsgroup.com Office phone: 612 392-3163 Cell phone: 612 251-0232

Hello, I have struggled, for longer than I care to admit, with this seemingly simple problem, but I cannot find a solution other than the use of long drawn out ifelse statements. I know there has to be a better way. Here is stripped down version of the situation: I start with: a <- c(1,0,1,0,0,0,0) b <- c(1,1,1,1,0,0,0) c <- c(1,1,0,1,0,0,0) rbind(a,b,c) [,1] [,2] [,3] [,4] [,5]

Hello R experts I am using Hmisc aregImpute and Impute (following example on page 105 of The Hmisc and Design Libraries). *My end goal is to have NAs physically replaced in my dataframe. I have read the help pages and example in above sited pdf file, but to no avail. Here is example of what I did. Ph, my data frame, is attached. > xt <- aregImpute (~ q5 + q22rev02 + q28a, n.impute=10,

I have been wrestling with this function for quite a while, and am not making headway. 1) I want to apply a function to the following columns of a dataframe: myfunction. <- apply(ph5028[,c(83:107)],2,function(x) ... 2) Within each of the above columns there is a single numeric code, 1, 2 or 3 or an NA. 3) My goal is to determine the percent of time each person used a 2 code. So if a person

Hello R experts, The following problem outstrips my current programming knowledge. I have a dataframe with two fields that looks like the following: ID Contract 01 1 01 1 02 2 02 3 02 1 03 2 03 2 03 2 03 1 03 1 03 1 etc... I would like to end up with a dataframe with one row per ID where the value in the contract field would be the

Dear R Masters, I have searched high and low (the help archives and my various R reference material and help files) for a solution to what appears to me to be quite a simple problem. In the following syntax, variable n10 has three levels. I would like the symbols that appear in the graph for these three levels to be different colors. The best I have been able to do is to have the Key display

Hello, I have a data frame that has three fields. Resp# ActCode ProdUsed 100 3 2 100 3 2 100 4 3 100 4 3 101 3 6 102 2 1 102 3 1 103 5 1 103 5 1 103

Hello R folks. 1) The question that generated the data, which I call Qx: Which of the following 5 items have you performed in the past month? (multipe response) 2) How the data is coded in my current dataframe: The first item that a person selected is coded under a field called Qxfirst; the second selected under Qxsecond, etc. For the first Person, the NAs mean that that person only selected

Hello, In the Hmisc package, functions describe and summarize can explicitly take a weight variable. My question is can a weight variable be applied when using 'summary'? For example, using...summary(var1 ~ var2) I would like to weight the data by var 3 (same length). Is this possible? Thanks a lot. Greg Blevins The Market Solutions Group, Inc.

Hello, I am inputing a 17 x 17 symetric matrix to sammon. The matrix is a co-occurance matrix with no missing data. If this is at all relevant, running hclust on this matrix works. > samx <- sammon(q23axproduct) I receive the following error: Error in sammon(q23axproduct) : initial configuration must be complete In addition: Warning messages: 1: some of the first 2 eigenvalues are

Hello, I have spent considerable time trying to figure out that which I am about to describe. This included searching Help, consulting my various R books, and trail and (always) error. I have been assuming I would need to use a loop (looping over columns) but perhaps and apply function would do the trick. I have unsuccessfully tried both. A scaled down version of my situation is as follows:

Hello, I have a df, pp, with five variables: > nobs(pp) q10_1 q10_2 q10_3 q10_4 actcode 1620 1620 1620 1620 1620 I want to create a loop to run four xtabs (the first four variables above by the fifth) and then store the results in a matrix. Below I make my intent clear by showing the output of one xtab which is inserted into a matrix. > a <- xtabs(q10_1 ~

Dear R Community, One thing that always bugged me about R is the abundance of multi-level nested statements, like: cumsum(ifelse(c(1,diff(v)),1,0)) because: a) you have to read them inside out as opposed to left-to-right b) in the console you always have to go back and type the parenthesis if you want to nest your statement I kind of like the UNIX pipe operator as a very good abstraction of a

I have a vector of values -1, 0, 1, say a <- c(0, 1, 0, 1, 1, -1, -1, -1, 0, -1, -1) I want to create a vector of the cumulative sum of this, but I need to set a maximum and minimum value for the cumsum, for example: max_value <- 2 min_value <- -2 the expected result would be (0, 1, 1, 2, 2, 1, 0, -1, -1, -2, -2) The only way I managed to do It, was res <-

Hello, R 2.3.0 Windows XP I have spent quite a bit of time trying to resolve my problem below, which included a R site search. The "vertical bars" syntax below produces a vertical bar chart with the values displayed above each bar. I want to cast this graphic horizontally, but I have not been able to arrive at a suitable outcome. The best I have been able to do, using the second block

Full_Name: Gregory L. Blevins Version: 1.8 OS: Windows 2000 Submission from: (NULL) (65.29.54.28) I see this when I open 1.8 Error in grep("united.states", Sys.getlocale("LC_CTYPE"), TRUE) : 5 arguments passed to "grep" which requires 6. R : Copyright 2003, The R Development Core Team Version 1.8.0 alpha (2003-09-18) R is free software and comes with