similar to: Boot R

Hi,   I'm using lars package to run some regression analysis and my doubt now is how can I predict my model to another dataset? Let me explain a little better: I have a dataset from which I withhold some data. With the data that wasn't withheld, I create the model. Now, what I'm not being able to do is apply the model back to the data that I withheld. Any suggestions?   Here it goes

Hello, Somewhat new to rails here. But have used Ruby for years and thus have used ruby-debug before with success. My years of gdb experience were helpful. I like how rails development is easy to do with Vim and command line. They only time I yearn for a GUI tool is when debugging. I do MS MVC dev at work, and VS is nice for debugging, even if I am not nuts about the rest of it. Anyone

Ronaldo Your mathematical question is of interest to me too. But I am particularly interested in a translation into American English of the pun attached to you email. Could you try to explain O Flamengo e o Bangu terminaram o jogo em 0 x 0. Quem fez o gol? A Volkswagen My rough translation into English is: Two soccer teams ended play 0 to 0. Who got the goal? A Volkswagen. I need all the

I''m using ruby 1.8.6 p111. But some people seem to think that version 1.8.5 is better. Should I give it a whirl? --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To post to this group, send email to rubyonrails-talk-/JYPxA39Uh5TLH3MbocFFw@public.gmane.org To unsubscribe

Is possible to integrate this diferential equation: dN/dt = Nr(1-(N/K)) in R using the integrate() function? Or any other diferential equation? If yes, how? If no, anybody know any software on linux that make this? Inte Ronaldo -- O problema de ter os dois p??s bem firmes no ch??o ?? que voc?? n??o vai conseguir tirar as cal??as. --An??nimo -- |> // | \\

Hi, I have these vectors: > WEEK <- rep(c(1:52),2) > YEAR <- rep(c(2000,1999),c(52,52)) How to make a vector of Date with weeks in years? I try as.date from survival package, but it dont work with weeks, just only with days, months etcs. Thanks Ronaldo -- "Realmente minha cidade e muito facultativa" --Elivelton, ao rep?rter da Jovem Pan que falava das muitas

Hi, I have the follow function: function() { ## Init of function ... for(i in test) { ... while(j <= test2) { ... } } } The problem is that sometimes, naturally, the while is not possible to be resolved, and so the program abort. In this case I need that program return to the init of function and run again. How I can make this? Abort the while, abort the for

Hi, I have some data that have this behaviour: | |******* | * | * | * | * |---------------- What is the best and simpler way to fit this in R? Thanks Ronaldo -- Ela pilotava um Continenal 2001 com igni????o autom??tica Magiclic... -- |> // | \\ [***********************************] | ( ?? ?? ) [Ronaldo Reis J??nior ] |>

Hi, look this: > summary(fam??lia) Anacardiaceae Annonaceae Bombacaceae Cecropiaceae 2 4 1 3 Chrysobalanaceae Clusiaceae Euphorbiacaea Fabacea 1 1 4 3 Fabaceae Flacourtiaceae Humiriaceae indeterminada

Hi, I try to run the example of Crawley's Book on the page 661, but it fail, look > repmeasures <- read.table("../Packages/Crawley/data/repmeasures.txt",header=T) > attach(repmeasures) > rep <- as.factor(rep) > library(nlme) > model <- lme(height~seed,random=~time|rep/seed) Erro em lme.formula(height ~ seed, random = ~time | rep/seed) : iteration limit

Hi, the question on subject is possible? example: m1 <- lmer(y~1+(1|subject)) m2 <- update(m1,.~.+x) I try but dont work, exist any other method for this? Thanks Ronaldo -- He won a Toyota now, eh? -- pal?ndromo -- |> // | \\ [***********************************] | ( ? ? ) [Prof. Ronaldo Reis J?nior ] |> V [UNIMONTES/Depto. Biologia

I have a data set with the following structure (with many more obs.): var1 expt day diameter 1 1 2 0.5 1 1 3 0.9 1 1 4 1.3 1 1 5 1.7 1 2 2 0.3 1 2 3 0.5 1 2 4 0.9 1 2 5 1.6 2 1 2 0.7 2 1 3 1.2 2 1 4 1.6 2 1 5 2.3 2 2 2 0.4 2 2 3 0.8 2 2 4 1.6 2 2 5 3.2 I can get separate regression analysis for each level of var1 and expt with the command: by(data3, data3$var1:data3$expt, function(x)

Hi, I have this: lme(y~x1+x2,random=~1|x1/x2) How to make this random effect using lmer? I try this: lmer(y~x1+x2+(1|x1/x2) But it dont work. Any idea? Thanks Ronaldo -- System halted! -- |> // | \\ [***********************************] | ( ?? ?? ) [Ronaldo Reis J??nior ] |> V [UFV/DBA-Entomologia ] | / \ [36570-000 Vi??osa -

Hi, I make a upgrade to R 2.1.0 and in some analysis I give an error: anova(model,test="F") Analysis of Deviance Table Model: binomial, link: logit Response: landing/total Terms added sequentially (first to last) Df Deviance Resid. Df Resid. Dev F Pr(>F) NULL 16 105.079 trat 1 93.149 15 11.930 93.15 Warning message:

Hi, I try to make an analyses to discover what is the time that an area begin to have spacial autocorrelation. And after, what is the number of individuals responsible for this autocorrelation. The main idea is to discover if exist a contamination of a quadrat from others quadrats and how is the population needed to make this contamination. This is very common to use automata to simulate

Hi, Please, change the brazilian mirror http://www.termix.ufv.br/CRAN/ to http://www.insecta.ufv.br/CRAN/ in R homepage. Thanks ROnaldo -- Se dois homens no mesmo trabalho concordam o tempo todo, um deles ?? demais. Se discordam sem parar, ent??o os dois s??o dispens??veis --Darryl F. Zanuck -- |> // | \\ [***********************************] | ( ?? ?? ) [Ronaldo Reis J??nior

Hi, I make this model using lme m.lme <- lme(Glycogen~Treatment,random=~1|rTrt/Liver) How to make this using lmer? I try > m.lmer <- lmer(Glycogen~Treatment+(1|rTrt/Liver)) Erro em lmer(Glycogen ~ Treatment + (1 | rTrt/Liver)) : entry 0 in matrix[0,0] has row 2147483647 and column 2147483647 Al??m disso: Mensagem de aviso: / not meaningful for factors in: Ops.factor(rTrt, Liver)

Hi, I know that Rsquare in glm or in non-linear models is "wrong", but some people like this. How I make to estimate the Rsquare from a model ajusted with glmmPQL or another GLMM? Thanks for all Ronaldo -- A simplicidade ?? o ??ltimo degrau da sabedoria. -- Victor Hugo -- |> // | \\ [***********************************] | ( ?? ?? ) [Ronaldo Reis J??nior

Hi! How to calculate the correct SE of mean in a nested or spliplot anova? Nested example: --------------------- m <- aov(Glycogen~Treatment+Error(Treatment/Rat/Liver)) > m Call: aov(formula = Glycogen ~ Treatment + Error(Treatment/Rat/Liver)) Grand Mean: 142.2222 Stratum 1: Treatment Terms: Treatment Sum of Squares 1557.556 Deg. of Freedom 2 Estimated

Hi, I try to put a legend in a xyplot graphic. xyplot(y~x|g,ylim=c(0,80),xlim=c(10,40),as.table=T,layout=c(2,3), ylab="N??mero de machos capturados",xlab=expression(paste("Temperatura (",degree,"C)")), key=list(corner=c(0,0),x=0, y=0, text=list(legenda),lines=list(col=cor, lwd = espessura, lty=linha),columns=7,between=0.5,betwen.columns=0.5,cex=0.8)) The problem