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...n object either). I'm not sure I'm really clear because it's difficult for me to explain it, but I hope you'll understand (and let me know what you would help you to understand) Thank you in advance Ivan -- Ivan CALANDRA PhD Student University of Hamburg Biozentrum Grindel und Zoologisches Museum Abt. S?ugetiere Martin-Luther-King-Platz 3 D-20146 Hamburg, GERMANY +49(0)40 42838 6231 ivan.calandra at uni-hamburg.de ********** http://www.for771.uni-bonn.de http://webapp5.rrz.uni-hamburg.de/mammals/eng/mitarbeiter.php

...s one only with IPS2, IPS3,... > > The command: > >> SA1<-as.vector(SA$"Reponse IPS1") > > Returns > >> NULL > > As do several variations I have tried. Any ideas. -- Ivan CALANDRA PhD Student University of Hamburg Biozentrum Grindel und Zoologisches Institut und Museum Abt. S?ugetiere Martin-Luther-King-Platz 3 D-20146 Hamburg, GERMANY +49(0)40 42838 6231 ivan.calandra at uni-hamburg.de ********** http://www.for771.uni-bonn.de http://webapp5.rrz.uni-hamburg.de/mammals/eng/1525_8_1.php

Hello everyone, I have versions 2.7.2 and 2.10.1 installed on a machine that has no access to internet. In 2.7.2 I can use ? to get help on functions, which in 2.10.1 that does not work, all I see is "starting httpd help server...done" and then nothing. Have I downloaded 2.10.1 incorrectly (=forgot to tick some box for local help file repository) or is the internet help now the

Hello, How can I read a xlsx file using xlsx package? Thanks Albert [[alternative HTML version deleted]]

...#39;t found anything helpful. Maybe I'm just on the wrong path to do it or missed something obvious... I hope my question is clear. If not, please let me know what would help you to understand. Thanks in advance Ivan -- Ivan CALANDRA PhD Student University of Hamburg Biozentrum Grindel und Zoologisches Museum Abt. S?ugetiere Martin-Luther-King-Platz 3 D-20146 Hamburg, GERMANY +49(0)40 42838 6231 ivan.calandra at uni-hamburg.de ********** http://www.for771.uni-bonn.de http://webapp5.rrz.uni-hamburg.de/mammals/eng/mitarbeiter.php

...ut in which column(s) are the mismatches and how many (here 1). But my datasets are 2000+ rows, and I would like to know the row number(s) where mismatches occur. How can I do that? Thank you for your help! Regards, Ivan -- Ivan CALANDRA PhD Student University of Hamburg Biozentrum Grindel und Zoologisches Museum Abt. S?ugetiere Martin-Luther-King-Platz 3 D-20146 Hamburg, GERMANY +49(0)40 42838 6231 ivan.calandra at uni-hamburg.de ********** http://www.for771.uni-bonn.de http://webapp5.rrz.uni-hamburg.de/mammals/eng/mitarbeiter.php

...;select number ") select number 0.2 ## in the console, not really visible b [1] "0.2" I would like both "free" input and a pop-up window. Is there a function for this? Thanks in advance, Ivan -- Ivan CALANDRA PhD Student University of Hamburg Biozentrum Grindel und Zoologisches Museum Abt. S?ugetiere Martin-Luther-King-Platz 3 D-20146 Hamburg, GERMANY +49(0)40 42838 6231 ivan.calandra at uni-hamburg.de ********** http://www.for771.uni-bonn.de http://webapp5.rrz.uni-hamburg.de/mammals/eng/1525_8_1.php

sorry I had a mistake sending my question without a subject. I do resend again. Please excuse me. > Hello > I have a data array with soil variables (caperf), in which the variable "clay" is factor (as I see entering str(caperf)) . I need to do a regression model, so I need to have arcilla (=clay) as a numeric variable. For that I have entered > >

Hi. In a data set I have a variable that takes values from 1 to 14. For each subgroup of values of this variable, I would like to obtain some descriptive statistics of other variables present in the data set. I've been trying with a "for" loop but I couldn't get nothing. Could you please suggest me some lines? -- View this message in context:

Hi, I have tried looking at the archives but havent found any answer that works till now (Sorry if i have missed anything) I am a newbie to R and i am trying to carry out hierarchical clustering using hclust -> as.dendrogram and then plotting the results as a dendrogram using the plot function plot(object). My question is : In the function "plot", can one decrease the leaf label

Dear group, I am trying to write functions, but as a beginner, everything is not so obvious. Let's say I want the results in a list of elemts like this : tot1, tot2, etc Here is a function: toto <- function(x,y) { for(i in x:y){ paste(c("tot",i),collapse="")<-(i*2) } } If I type this : >toto(1,5) I get this message error: Error in paste(c("tot",

Hey all, I am writing a function in which I will have a matrix of 4 columns and a variable amount of rows. The first to columns will always contain be of the Character type, the third and fourth columns can be a variation of data types, usually characters and integers, but sometimes lists or matrices. At one point the code makes, for each row, a copy of that row, then it makes some adjustments

...tsts_slope,"X",sep="")), lty=1, col=mycol) >>>>>> } >>>>>> >>>>> -- >>>>> Ivan CALANDRA >>>>> PhD Student >>>>> University of Hamburg >>>>> Biozentrum Grindel und Zoologisches Museum >>>>> Abt. S?ugetiere >>>>> Martin-Luther-King-Platz 3 >>>>> D-20146 Hamburg, GERMANY >>>>> +49(0)40 42838 6231 >>>>> ivan.calandra at uni-hamburg.de >>>>> >>>>> ********** >&g...

...lect)[ind.xvar], ylab=names(select)[k], las=1) points(select_mean[[ind.xvar-diff_len]], select_mean[[k-diff_len]], pch=18, cex=2) two_reg(dat=select, xvar=ind.xvar, yvar=k) } dev.off() ------------------------- -- Ivan CALANDRA PhD Student University of Hamburg Biozentrum Grindel und Zoologisches Museum Dept. Mammalogy Martin-Luther-King-Platz 3 D-20146 Hamburg, GERMANY +49(0)40 42838 6231 ivan.calandra at uni-hamburg.de ********** http://www.for771.uni-bonn.de http://webapp5.rrz.uni-hamburg.de/mammals/eng/1525_8_1.php

Greetings, I am a very novice user with R, and in the course of running a linking procedure : P.old<- function (a, c, b, xi){ #a contains a parameters #c contains c parameters #b contains b parameters #xi is a one column vector containing quadrature points for xi(=theta-gamma)for one item tmp <- a*(xi-b)

Dear All If I have the following dataset V1 V2 x y y x z b a c b j d l c o How do I use R command to get the total number of different letter in column "V1" column "V1" has 7 different letters. Thank you -- View this message in context: http://r.789695.n4.nabble.com/Summing-up-Non-numeric-column-tp3077710p3077710.html Sent from the R help mailing list archive

...$coef[2], digits=3) abline(tsts$coef, lty=1, col=mycol) legend(x=pos, legend=c(paste("TSTS ",name.dat,": Y=",tsts_inter,"+",tsts_slope,"X",sep="")), lty=1, col=mycol) } -- Ivan CALANDRA PhD Student University of Hamburg Biozentrum Grindel und Zoologisches Museum Abt. S?ugetiere Martin-Luther-King-Platz 3 D-20146 Hamburg, GERMANY +49(0)40 42838 6231 ivan.calandra at uni-hamburg.de ********** http://www.for771.uni-bonn.de http://webapp5.rrz.uni-hamburg.de/mammals/eng/1525_8_1.php

It's often difficult to figure out what a problem data set looks like when someone pastes a mess of output from R into an e-mail. The dput command, used judiciously?I would hope no one would send a 1 M data set?can make life much easier. I wonder if it would be useful to add a hint in the instructions at the bottom of the posting page, where the list asks for self-contained reproducible

Simple one here ... but can't get it to work ... for (i in 1:4){ paste("stuff",[i]),sep="") <- 3 + i } ls() rm(list=ls()) I just want it to create 4 new variables called stuff1, stuff2, stuff3, stuff4 with the corresponding assignments. I realise that there are more elegant functions but this is just a model of a bigger situation. Thanks Jim

Hi all, probably a simple problem for you but I am stuck. This simple function adds columns (with differing length) to data frames: add.col <- function(df, new.col) { n.row <- dim(df)[1] length(new.col) <- n.row cbind(df, new.col) } Now I would like to extend that method. A new parameter 'name' shouild allow people to pass in a name for that new column. Is that possible and