Displaying 5 results from an estimated 5 matches for "wlll".
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will
2008 Jul 11
4
b44 module probe error
Dear All,
I''m trying to configure Xen on a laptop with a BCM4401 ethernet board
The Debian xen kerner 2.6.18-5 is not handling wlll that board
I get the follwing in messages
b44: Probe failed with error -5
Any help is welcome
Regards
Maurice
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2005 Mar 01
2
Fedora core 2 domain trust account fails
Hello,
Having a problem with trust accounts failing after creation. The following is
the system that I'm running Samba on:
Fedora Core 2
(compiled from source)
Samba 3.0.11
OpenLDAP 2.2.23
BerkeleyDB 4.3.27
Windows 2000 client machine
I have a script to add machine trust accounts to LDAP. The first part adds a
posix Account and attributes to LDAP, the second uses smbpasswd to add the Samba
2011 Feb 09
8
Odd error no one seems to know how to fix
First: my apologies if this is posted somewhere else. I have been searching for a couple of months on how to resolve this issue.
My problem: I can not get any games to run on Wine. It is however, only games. Other window based programs run on Wine just fine.
The error message reads as follows:
[The Program lol.launcher.exe has encountered a serious problem and needs to close. We are sorry for the
2017 Jun 15
2
Function Inlining and undef / poison question
...compiler doesn't KNOW that x is undef, and as a result, do_stuff is
guaranteed to execute. If F is inlned, x is known as undef, so the compiler
decides that the comparison is false (despite x always has to be equal to
itself, no matter whether it's value is undef or not), and thus do_stuff
wlll not be called.
Of course, it would be easy to fix this by initializing x, but with some
more complex code, it may not be so easy to follow what is going on and
what the effects will be.
I don't have a good answer as to what to do - I can sort of see both sides
on this one.
--
Mats
>
>...
2017 Jun 15
2
Function Inlining and undef / poison question
Nuno,
One of your recent emails got me thinking about inlining.
I say this function is always well defined,
And it always executes statement S
F(a)
{
If (a == a) S;
}
And that if this function is inlined it must still be well defined,
And still always execute statement S
But if I read your example correctly you feel that the result
of inlining is undefined behavior because “if