Displaying 15 results from an estimated 15 matches for "viennes".
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viernes
1999 Oct 13
1
smbmount --> df: /mnt/Archives: I/O Error
Hi,
I mount //MYSERVER/Archives using
smbmount //MYSERVER/Archives /mnt/Archives -N
(MYSERVER is a NT SERVER box and the Linux box from which I smbmount
is 2.2.13-7mdk.
Everything is fine :
[root@lima linux]# df
Filesystem 1k-blocks Used Available Use% Mounted on
/dev/hda6 1981000 1373871 504718 73% /
/dev/hda7 2873619 1746320 978700 64%
2009 Sep 29
3
sort dates within a factor
Dear List,
I have the following data:
>>
test <- data.frame(date =
as.Date(c('2007-01-01','2008-03-24','2003-03-02','2008-05-03','2002-05-23','2001-06-30','2005-12-04')),
nr = c(2000,2000,2000,2001,2002,2003,2003))
test
date nr
1 2007-01-01 2000
2 2008-03-24 2000
3 2003-03-02 2000
4 2008-05-03 2001
5 2002-05-23 2002
6
2004 Dec 10
1
C access to R libraries
Hi all,
I'm used to code in C and I'm wondering if access to internal R compiled
libraries with C is an easy job under linux. Is anyone has experience
with that ?
Some headers seems rather clear and interesting, but binding may not be
so easy....
Actually, my question is: will I have to manipulate complex R objects in
C to access to raw statistic functions ?
Thanks for your
2008 Oct 17
3
Guitar Pro in Wine?
My uncle recently bought a new computer and he wants me to help him install Guitar Pro.
The thing is, he doesn't have Windows, and I'm thinking of installing Ubuntu with wine on the comp.
Quiz time!
Can you use wine, with GP, and if you can, deos it perform poorly in any ways?
2009 Jul 29
2
quetions about dimensions
hi ,everyone,
I have a script shown as below:
> bj2=bjerrdata$tyerr[bjyearnum[2]+1:bjyearnum[3]]
> length(bj2)
[1] 448
while
> b=bjyearnum[3]
> a=bjyearnum[2]+1
> bj1=bjerrdata$tyerr[a:b]
> length(bj1)
[1] 169
it is different with bj2 and bj1 . and the array bjyearnum is
[1] 0 279 448 633 1021 1365 1813 2237 2839 3314 3798 4157 12
why bj1 is 169 while bj2 is 448
2009 Oct 08
1
To hell with OpenSuse, ditch it and go to Ubuntu
this blog entry
http://www.viggie.com/blog/software/opensuse-ubuntu-usage-experience
, if credible , would seem to suggest that there is no good reason to
choose Suse.
I really don't have time for such nonsense, maybe I'll just reinstall as Ubuntu.
Also, noticed that GCC was not installed when Suse installed. That's
just weird, GCC is part of Linux.
And if you try to install GCC,
2009 Oct 09
2
Problems with code containing a for loop
The following code isn't working and we can't figure out why..
letters = c("A","B","C","D","E","F","G","H","I","J")
numbers = 1:3
for(i in 1:6){ #6 letters
for (j in 1:3) { #3 numbers
for (k in -1:1) {
2005 Sep 11
2
PSP, Protection Center 500, NUT 2.0.2 and Gentoo
Hi,
I recently bought a MGE protection center 500.
I am running a gentoo, and I am currently trying to enable the ups
handling by the os, with no success.
First, I compiled and installe nut 2.0.2 (with usb support) and psp
3.0. I made ebuild for them that I will submit soon to
bugs.gentoo.org.
The ups is connected via usb, and lsusb confirms that the device is
detected (cf end of the mail for
2009 Dec 13
2
Reshape a data set
I am trying to reshape a data set. Could someone please help me with the
reshape, cast, and melt functions? I am new to R and I have tried reading
up on how to use the reshape package, but I am very confused. Here is an
example of what I am trying to do:
subject coder score time
[1,] 1 1 20 5
[2,] 1 2 30 4
[3,] 2 3 10 10
[4,] 2 2
2009 Jun 18
3
QuestÃon regarding the use of write.csv2, write.table ...
Hi all,
I use "write.csv" and "write.table" to write a data frame in a file like
following:
write.csv2(allRandomTestCase_XDroped, "allRandomTestCase.csv")
But in the created file "allRandomTestCase.csv" an additional column with
consecutive numbers is automatically added to the column of the data frame
"allRandomTestCase_XDroped".
That is why my
2009 Aug 05
2
using ddply but preserving some of the outside data
I have a bit of a quandy. I'm working with a data set for which I
have sampled sites at a variety of dates. I want to use this data,
and get a running average of the sampled values for the current and
previous date.
I originally thought something like ddply would be ideal for this,
however, I cannot break up my data by date, and then apply a function
that requires information
2009 Sep 28
4
Running an ANOVA with a BY
I have a simple 1 way anova coded like
summary(ANOVA1way <- aov(Value ~ WellID, data = welldata))
How can I use the BY function to do this ANOVA for each group using another
variable in the dataset?? I tried coding it like this, but it doesn't seem
to work.
summary(ANOVA1way <- by(welldata, Analyte, function(x) aov(Value ~ WellID,
data = welldata)))
In SAS I would code it like this:
2009 Aug 17
3
Reshape package: Casting data to form a grid
Dear R Users,
I'm trying to use the 'cast' function in the 'reshape' package to convert column-format data to gridded-format data. A sample of my dataset is as follows:
head(finalframe)
Latitude Longitude Temperature OrigLat p-value Blaney
1 -90 -38.75 NA -87.75 17.10167 NA
2 -90 135.75 NA -87.75 17.10167 NA
3 -90 80.25
2009 Jun 17
2
Re gression by groups questions
I have a large dataset grouped by a factor and I want to perform a regression
on each data subset based on this factor. There are many ways to do this,
posted here and elsewhere. I have tried several. However I found one method
posted on the R wiki which works exactly as I want, and I like the elegance
and simplicity of the solution, but I don't understand how it works. Its
all in the formula
2009 Jun 16
4
confusion on levels() function, and how to assign a wanted order to factor levels, intentionally?
Dear R-helpers,
I want to make a series of boxplots on several numeric univariates with two
group variables (species and population, population nested in species, and
with population as the X-axis). In order to get a proper order of the
individual populations in X-axis, I need to assign a wanted order to the
factor (population). I used the levels() function to do this assignment, but
it seemed