search for: unpromoted

...; void bar() { if (P == &foo) { ... } } void baz() { P = &foo; } b.cc: … bar(); … If bar() is imported into b.cc (and gets inlined), then b.cc will have a reference to static foo(). It we then import foo() and leave the imported copy local/unpromoted, the imported P==&foo comparison will fail (assume baz() is not referenced by or imported into b.cc). That is because P will point to the a.cc::foo() and the imported comparison will compare against the imported copy b.cc::foo(). This is avoided by promoting address taken static functions, in b...

...C C compiler is concerned about this line in TOKEN.C 4 22136 temp_byte = (char) n >> 8; ........................................1 %CC-I-RIGHTSHIFTOVR, (1) In this statement, the right shift count "8" is greater than or equal to the size of the unpromoted operand "(char)n". If I am interpreting this right, the value n is an integer, and is being cast to be a 8 bit size. And this results in all the higher bits being discarded. So the >> should shift out all 8 remaining significant bits. Since this is a signed value, it app...

...) { > > P = &foo; > > } > > > > b.cc: > > … bar(); … > > > > > > If bar() is imported into b.cc (and gets inlined), then b.cc will have a > reference to static foo(). It we then import foo() and leave the imported > copy local/unpromoted, the imported P==&foo comparison will fail (assume > baz() is not referenced by or imported into b.cc). That is because P will > point to the a.cc::foo() and the imported comparison will compare against > the imported copy b.cc::foo(). This is avoided by promoting address taken > st...