[A repost under a new topic since the other seems to have been lost in
the noise]
I am basically down to one unresolved compilier diagnostic.
The HP/COMPAQ/DEC C compiler is concerned about this line in TOKEN.C
4 22136 temp_byte = (char) n >> 8;
........................................1
%CC-I-RIGHTSHIFTOVR, (1) In this statement, the right shift count
"8" is greater than or equal to the size of the unpromoted operand
"(char)n".
If I am interpreting this right, the value n is an integer, and is being
cast to be a 8 bit size. And this results in all the higher bits being
discarded. So the >> should shift out all 8 remaining significant bits.
Since this is a signed value, it appears to leave what should be the
high byte of a word either set to zero, or with possibly all bits set to
the value of the sign bit for the character that resulted from the cast.
Is this really what is intended? Or should there be parenthesis around
(n >> 8) to make sure that it happens before the most significant part
of "n" is discarded?
The actual assembly code generated is:
LDL R10, n ; R10, 16(FP)
SLL R10, 56, R10
SRA R10, 63, R10
STQ R10, temp_byte ; R10, 8(FP)
-John
wb8tyw@qsl.network
Personal Opinion Only