Displaying 6 results from an estimated 6 matches for "unio".
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2011 Feb 10
1
problem with R (akima, fUtilities) in Ubuntu 10.04
Dear all!
I'm using R 2.12.1 in Ubuntu 10.04.
Problem is that when using functions like interp (package akima) and
akimaInterp (package fUtilities), I get different results every time for
the same data set. I've checked the interpolated results, and two
examples (in attachment) have different sum of NA values. Also when I
subtract the x,y,z values from two interpolations of the same data
2012 Jan 28
2
wireframe_box_axis
Dear all!
I am using wireframe function from lattice package.
Is it possible to remove box around the plot but to keep axis (x, y, z)?
Thanks in advance!
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2011 Nov 26
5
cumsum in 3d arrays
Hello!
Is it posible to apply /cumsum()/ along the 3rd dimension of 3D array?
Something like matrlab function - /cumsum (*A*,dim)/ which returns the
cumulative sum of the elements along the dimension of *A* specified by
scalar dim.
Thanks in advance
?eljka
--
View this message in context: http://r.789695.n4.nabble.com/cumsum-in-3d-arrays-tp4110470p4110470.html
Sent from the R help mailing
2005 May 01
6
win32-changejournal 0.2.0-1 compile error
...hangejournal.c(61) : error C2146: syntax error : missing '';'' before
identifier
''fOk''
changejournal.c(61) : error C2065: ''fOk'' : undeclared identifier
changejournal.c(63) : error C2224: left of ''.UsnJournalID'' must have
struct/unio
n type
changejournal.c(64) : error C2224: left of ''.DeleteFlags'' must have
struct/union
type
changejournal.c(65) : error C2065: ''FSCTL_DELETE_USN_JOURNAL'' :
undeclared ident
ifier
changejournal.c(74) : error C2146: syntax error : missing '')''...
2012 Jan 24
0
lattice wireframe_box around picture
I am using the wireframe function from lattice package. The problem that I
have is very interesting. Namely, this is my code:
x= seq(-pi, pi, len = 20)
y=seq(-pi, pi, len = 20)
xyz= expand.grid(x = x, y = y)
xyz$z=sin(sqrt(xyz$x^2 +xyz$y^2))
trellis.par.set("axis.line",list(col="transparent"))
trellis.par.set("panel", list(col="transparent"))
2011 Apr 17
5
cube root
This is some interesting:
> -8^(1/3)
[1] -2
> x=(-8:8)
> y=x^(1/3)
> y
[1] NaN NaN NaN NaN NaN NaN NaN NaN
0.000000 1.000000
[11] 1.259921 1.442250 1.587401 1.709976 1.817121 1.912931 2.000000
So, can anybody explain this?! (Why is x[1]^(1/3)=y[1]=NaN, but
-8^(1/3)=-2?)
Thx!!!
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