Displaying 11 results from an estimated 11 matches for "tranposed".
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transposed
2008 Dec 23
1
aggregate / tranpose data
Dear R-Users,
Suppose I have data in the following format:
CODE_NAME ZIP_CODE
John 12345
John 23456
John 34567
Jane 13242
Jane 22123
I want to transpose / convert it into:
CODE_NAME ZIP_CODE
John 12345,23456,34567
Jane 13242,22123
Any idea/pointer is appreciated.
2010 Jan 05
3
Tranpose and Aggregate Data
Hi,
I need to transpose and aggregate the 4th and 5th column of this data
set (below). The period is 1 to 100 years and some period has 1 entry
as shown in the example below.
Any ideas how to do this. Thanks in advance.
Noli
~~~~~~~~~~
From:
P_ID CROP Period Ini_Age Area_Cut
83 SORI 1 31 528.2465512
84 SORI 1 32 74.55179899
85 SORI 1 33
2004 Feb 16
4
Matrix mulitplication
ABCD are four matrix.
A * Inverse((Transpose(A)*Tranpose(B)*B*A+C)) * Transpose(A) * Transpose(B) * D
how to write in R in an efficient way?
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2009 Jul 31
1
Matrix Integral
Hi,
Any help on this would be appreciated:
I need to integrate where K is a 4x4 matrix, and SIGMA is a 4x4 matrix from
say a to b, i.e. 0 to 5:
integral MatrixExp(-K * s) %*% SIGMA %*% t(SIGMA) %*% MatrixExp(t(-K) s) ds
t is tranpose , %*% : matrix mult , MatrixExp : matrix exponential
I've use integrate before on univariate functions like f(x) = x^2 which is
fine but when doing this on
2010 Jun 17
2
help for reshape function
...sue" is not needed. I use the
following syntax to perform this task:
tdata<- reshape(data, varying=names(data)[-c(1,2)],direction="long", timevar
="label",v.names="value",time=names(data)[-c(1,2)]);
however, i lose the column "gene" in the resulting tranposed dataset. I did
my best to go through the help doc for reshape. however, I am frustrated
that the examples used in the help doc is kind o hard to follow to me. Can
anyone help me modify the code to keep the column "gene" in the resulting
table?
Any constructive suggestion is welcome.
th...
2009 Oct 02
1
How to select a subset <number of dimensions matter>
Hi guys,
I need your help.
I would like to select a subset from a dataset.
This is the dimension of the dataset.
> dim(data1)
[1] 72 36 1916
so, it's like.. there are 1916 of 72 * 36 matrix. ==> looks like 72 * (
36*1916 )
**
*1)*
And I would like to select the first 72*36 matrix. This is how I did:
> two=data1[,1:36]
Error in data1[, 1:36] : incorrect number of dimensions
2008 Aug 20
1
FYI: APL in R
http://idisk.mac.com/jdeleeuw-Public/utilities/apl/apl.R
Dedicated to the IBM 2741.
Implemented for general multidimensional arrays:
drop, take, reshape, shape, rank, select, generalized inner product,
generalized
outer product, representation, base value, join, expand, reduce, scan,
member of, ravel, compress, tranpose, rotate
Basically, the APL-I part is complete, and after some testing
2007 Jul 31
0
AsteriskNOW and Custom VoIP
Guys,
I've downloaded AsteriskNOW few days ago so I'm new to this product.
The first issue is on service provider area.
I've already used a VoIP account already configured with my ISP, it
works fine!
This configuration has been used until now with the client SJphone,
Now I would use this profile as main VoIP service provider to setup
in AsteriskNOW.
Here are the profile detail as
2008 Apr 15
2
Transposing Data Frame does not return numeric entries
x <- read.table("LittleGarvin.csv", sep=",", header=TRUE)
y <- t(x)
str(y)
chr [1:193, 1:288] "oligocha" "0" " 0" " 0" " 0" "0" ...
- attr(*, "dimnames")=List of 2
..$ : chr [1:193] "X" "upwd1201" "upwd0502" "upwd0702" ...
..$ : NULL
x is a data frame with
2006 Aug 16
3
separate row averages for different parts of an array
I have an array with 44800 columns and 24 rows I would like to compute the
row average for the array 100 columns at a time, so I would like to end up
with an array of 24 rows x 448 columns. I have tried using apply(dataset, 1,
function(x) mean(x[])), but I am not sure how to get it to take the average
100 columns at a time. Any ideas would be welcomed.
thanks,
Spencer
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2004 Oct 19
2
Matrix/Table col headings R 2.0.0
I have been looking at some 'table' examples in Peter Dalgaard's ISwR book, and I am confused by how to get right justification of my table headings when I use the tables() command. Compare the following:
# Produces right justfified column names
caff.marital=matrix(c(652,1537,598,242,36,46,38,21,218,327,106,67),nrow=3,byrow=T)