search for: transposed

Hello everybody When one is working with complex matrices, "transpose" very nearly always means *Hermitian* transpose, that is, A[i,j] <- Conj(A[j,i]). One often writes A^* for the Hermitian transpose. I have only once seen a "real-life" case where transposition does not occur simultaneously with complex conjugation. And I'm not 100% sure that that wasn't a

...sive analysis that uses every line (vector) of a matrix in a loop. In the model, I need to transpose those vectors that are extracted from a matrix. Using simple vectors (no matrix involved) the transpose function works fine: simplevector <-matrix(1:3,3,1) tsimplevector <-t(simplevector) #transposed dim(simplevector) #3x1 matrix (vector) dim(tsimplevector)#1x3 PROBLEM: However, when the vector is extracted from a matrix, its dimension is NULL. In this case the transposed dimension is correct, but you'll see the next example, that if a row was extracted, the dimension would be wrong: i...

...10 POLICE 101920 CKM 8840.4 31-Mar-10 POLICE 101920 CKM 8986.25 24-May-10 POLICE 101920 CKM 34252.2 30-Jun-10 POLICE 101920 CKM 8913.35 30-Apr-10  POLICE   Ideally i would like a row to have one row of  ACCT_NUM and TranAmount and Date be transposed to columns. Thanks Kind regards, Tabitha Mundia , Project Management Office, Equity Bank Limited,P.O. Box 75104-00200 Head Office, Upper hill, NHIF BLDG, 14th Floor, Nairobi, Kenya Direct Extension : +254732112721   Mobile: +254722309538...

Hello All, I was wondering if it's possible to reshape data from long to wide in R without using a "timevar". I've pasted some sample data below along with some code. The data are sorted by Subject and Drug. I want to transpose the Drug variable into multiple columns in alphabetical order. My data have a variable called "RowNo" that functions almost like a

Hi All, I want to ask if there is a transpose function for data frame like the procedure of transpose in SAS? Because I want to partially transpose a data frame which contains 5 columns (siteid, date, time, obs, mod), what I want to do is to put time as the column variables along with siteid, and date, and put obs and mod in the row names. specifically to transpose a data frame: siteid date

I want to transpose a dataframe like level 2006 2007 2008 A .... B ..... C ........ into level year A 2006 A 2007 A 2008 B 2006 B 2007 ...... There is a procedure in SAS can do this, is there any function in R can do this? -- View this

I am just starting to code in R and need some help as I am used to doing this in SAS. I have a dataset that looks like this: Chemical Well1 Well2 Well3 Well4 BOD 13.2 14.2 15.5 14.2 O2 7.8 2.6 3.5 2.4 TURB 10.2 14.6 18.5 17.3 and so on with more chemicals.... I would like to transpose my data so that it looks like this: Chemical WellID Value BOD Well1 13.2 BOD Well2 14.2 BOD Well3 15.5 BOD

...ot; 0" "0" ... - attr(*, "dimnames")=List of 2 ..$ : chr [1:193] "X" "upwd1201" "upwd0502" "upwd0702" ... ..$ : NULL x is a data frame with a whole bunch of numeric vectors I would like for the rows and columns to be reversed == transposed but with the same attributes. I am trying to feed the transposed data frame to metaMDS(vegan). I am stumped- sorry for the large attached file- I am at a loss. Stephen Sefick -- Let's not spend our time and resources thinking about things that are so little or so large that all they really...

Hi, New to R, using version 2.0.1 (2004-11-15) on debian Linux (sid), kernel 2.6.8-2-686. I have data in files with separate vectors on each row of the file, e.g., $ cat /tmp/stats freq,0,1,2,3,4,5,6,7,8,9,16,17,18,19,20,... noise,49,47,48,48,50,47,48,47,46,50,48,54,49,47,49,... signal,99,0,100,0,0,100,0,100,100,0,100,101,100,0,0,... pctrcv,5,0,5,0,0,5,0,5,11,0,5,5,5,0,0,...

Suppose this is my list of transactions: set.seed(200) tran=random.transactions(100,3) inspect(tran) items transactionID 1 {item80} trans1 2 {item8, item20} trans2 3 {item28} trans3 I want to get the 'transpose' of the data, i.e. transactionID items 1 {trans2} item8 2 {trans2} item20 3 {trans3} item28 4 {trans1} item80 I

I decided to do a direct comparison of transpose and sweep. library(microbenchmark) NN <- matrix(c(1, 2, 3, 4, 5, 6), nrow = 2, byrow = TRUE) # Example matrix lambda <- c(2, 3, 4) # Example vector colNN <- t(NN) microbenchmark( sweep = sweep(NN, 2, lambda, "/"), transpose = t(t(NN)/lambda), colNN = colNN/lambda ) Unit: nanoseconds expr min lq

...k you very much! MyData<-data.frame(names=c("John","Mary","Paul","Debby"),jan=c(10,15,20,25),feb=c(1,2,3,4)) (MyData) months<-names(MyData)[-1] people<-as.character(MyData[[1]]) ### Creating a temp matrix with people as columns and months as rows: transposed<-apply(MyData[-1],1,t) ### Putting vertical data (months as rows) - for each person - into a list: list.of.stacked<-list() for(i in 1:ncol(transposed)){ list.of.stacked[[i]]<-as.data.frame(matrix(ncol=3,nrow=length(months))) names(list.of.stacked[[i]])<-c("month","valu...

Hi guys, I need your help!! My goal is to make a csv file from ncdf file. This is the code i've used : > hyo=open.ncdf("C:/CRUTEM3.nc") > hyo [1] "file C:/CRUTEM3.nc has 4 dimensions:" [1] "longitude Size: 72" [1] "latitude Size: 36" [1] "unspecified Size: 1" [1] "t Size: 1916" [1] "------------------------"

Hi I'm trying to use ouch's hansen and brown functions but I get the error: > brown(logflatnodes,archotreeouch) Error in backsolve(l, x, k = k, upper.tri = upper.tri, transpose = transpose) : NA/NaN/Inf in foreign function call (arg 1) and with hansen also: Error in optim(par = c(sqrt.alpha, sigma), fn = function(par) { : function cannot be evaluated at initial parameters

Hi Listers, Is there a way that I can transpose an array... Suppose I have the following array... x<-array(c(1,2,3,4),dim=c(1,2,2)) , , 1 [,1] [,2] [1,] 1 2 , , 2 [,1] [,2] [1,] 3 4 And I would like to get the following result... , , 1 [,1] [1,] 1 [,2] 2 , , 2 [,1] [,2] [1,] 3 [,2] 4 Thanks in advance, Marcio -- View this message in context:

Hi Everyone, I have a dataset like this mean sd 0% 25% 50% 75% 100% n BODY TEMPERATURE 36.41099 0.4015699 35.1 36.22222 36.5 36.66667 37.1 89 DIASTOLIC BLOOD PRESSURE 73.60079 9.4656186 50.0 67.00000 73.0 80.00000 95.0 253 HEIGHT 171.94000 9.2011670 153.5 166.50000 173.0 176.25000 190.0

...by: array(x, c(2,3,2)) because breaks the structure (e.g. 1,3,5 is type mismatch) array(1:12,c(2,3,2)) , , 1 [,1] [,2] [,3] [1,] 1 3 5 [2,] 2 4 6 ... Of course following R's indexing order (rowIndex is the fastest) retains the structures, but X and Y dimensions are transposed. (note, c (2,3,2) => (3,2,2)) array(1:12, c(3,2,2)) , , 1 [,1] [,2] [1,] 1 4 [2,] 2 5 [3,] 3 6 Its like converting into Japanese vertical reading. It is not that I cannot get used to it, but I guess it is less error prone if I have the same order as in the data files....

I have a dataset in "long" format that looks something like this: ID TEST RESULT 1 A 17 1 A 12 1 B 15 1 C 12 2 B 8 2 B 9 Now what I would like to do is transpose it like so: ID TEST A TEST B TEST C 1 17 15 12 1 12 . . 2

hello, everybody, i have several unresolved issues: 1. how to do a matrix transpose? i cant find how to do it in the documentation. 2..suppose i have an object named as lm1 from linear regression, how could i refer to it by paste("lm",1,sep="") ? 3. to save a matrix 100 x 30, how to have a text file with 100 lines and 30 cols, instead of stacking them? thanks. best regards

I HAVE A VERY BIG DATA OF 67 COLMS AND 25000 ROWS AND WOULD LIKE TO TRANSPOSE IT THE R HELP WAS NOT ENOUGH INFORMATION BECOUSE I AM NOT A PROGRAMMER AND FIRST TIME R USER. SO CAN YOU GIVE SOME HINTS OF CODING, AA TT GG GG CC AA TT GG GG CC AA TT GG GG CC AA TT GG GG CC AA TT GG GG CC TO AA AA AA AA AA TT TT TT TT TT GG GG GG GG GG GG GG GG GG GG CC CC CC CC CC [[alternative HTML