search for: tidyr

Hi everyone: I?m one of the interns at RStudio this summer working on a project that helps teachers grade student code. I found an unexpected behaviour with the |==| operator when comparing |quote|d expressions. Example 1: |u <- quote(tidyr::gather(key = key, value = value, new_sp_m014:newrel_f65, na.rm = TRUE)) s <- quote(tidyr::gather(key = key, value = value, new_sp_m014:newrel_f65, na.rm = FALSE)) u == s # TRUE u <- quote(tidyr::gather(key = key, value = value, na.rm = TRUE)) s <- quote(tidyr::gather(key = key, value...

1) Definitely yes. They are on CRAN. Just type install.packages( c("dplyr", "tidyr" ) ) at the R console. 2) Don't know, but most likely the answer is yes. Since all R packages on Linux are compiled by R when installed, you either need to activate your virtual machine, compile the packages, and save the state for future use, or you have to build the package library on...

Hi Jeff, 1). I have tried install.packages( c("dplyr", "tidyr" ) ) into the r-script file got below error:- > install.packages( c("dplyr", "tidyr" ) ) Installing packages into ?/tmp/1776492876238396447/lib/portableR-master/site-library? (as ?lib? is unspecified) Error in install.packages(c("dplyr", "tidyr")) :...

Hi all, Today I had an R CMD build that failed while building a vignette because the vignette needs tidyr (>= 1.0, declared in DESCRIPTION Suggests) but my system had a previous version installed. It did not take me too long to figure out the issue (solved by upgrading tidyr) but it would have been even faster / easier if R CMD build failed early, with an error message that says something like &quo...

Hi Team, Please suggest me on below :- 1).are There any linux based library for dplyr and tidyr? I could find these r-libraries for windows and Mac but not for linux. 2). is it possible to add external library to portableR zip(http://nafiux.github.io/portableR/) file if yes then how to add external library to poratbleR zip file? In our application AWS lambda invoking the R-script by using po...

...s: > Hi everyone: > I?m one of the interns at RStudio this summer working on a project that > helps teachers grade student code. I found an unexpected behaviour with > the |==| operator when comparing |quote|d expressions. > Example 1: > |u <- quote(tidyr::gather(key = key, value = value, > new_sp_m014:newrel_f65, na.rm = TRUE)) s <- quote(tidyr::gather(key = > key, value = value, new_sp_m014:newrel_f65, na.rm = FALSE)) u == s # > TRUE u <- quote(tidyr::gather(key = key, value = value, na.rm = TRUE)) s > <- q...

...ink that you quoted. Do you have the directories referred to there in place? -- Sent from my phone. Please excuse my brevity. On July 25, 2017 7:27:31 AM PDT, Ashish Ranjan <aranjan1645 at gmail.com> wrote: >Hi Jeff, > >1). I have tried install.packages( c("dplyr", "tidyr" ) ) into the >r-script >file got below error:- > >> install.packages( c("dplyr", "tidyr" ) ) >Installing packages into >?/tmp/1776492876238396447/lib/portableR-master/site-library? >(as ?lib? is unspecified) >Error in install.packages(c("dpl...

...packages in publications. Type 'demo()' for some demos, 'help()' for on-line help, or 'help.start()' for an HTML browser interface to help. Type 'q()' to quit R. Desktop> library(tidyverse) Loading tidyverse: ggplot2 Loading tidyverse: tibble Loading tidyverse: tidyr Loading tidyverse: readr Loading tidyverse: purrr Loading tidyverse: dplyr Conflicts with tidy packages -------------------------------------------------------------- filter(): dplyr, stats lag(): dplyr, stats Desktop> library(magrittr) Attaching package: ?magrittr? The following object is...

...reproducible example, but want to lay out the high-level issues in case someone recognizes exactly what is happening here. The error is: Error in mut_env_parent(overscope$.top_env, lexical_env) : object 'rlang_mut_env_parent' not found and it occurs in three situations: 1) Using tidyr::nest() on an output from dplyr::group_by() 2) Using tibble::tibble() with <name> = <value> arguments 3) Using dplyr::select() on a tibble to select two columns Any obvious clues as to what's happening here? The only non-base packages loaded are current tidyverse, forca...

...exp(t-0.7)/(1+(exp(t-0.7))) > > ### Con b igual a 2 > > u=exp(t-2)/(1+(exp(t-2))) > > ####unir los datos > b=c(0.3,2,-1,-2) > > datos <- data.frame( > t = t, > l = l, > o = o, > i = i, > u = u > ) > > # ahora usamos gather, del paquete tidyr, porque nos permite pasar del > formato > # "wide" a "long" > library(tidyr) > # install.packages('tidyr') > datos_long <- gather(datos, Curva, Valor, 2:5) > datos_long > > ###Graficos > > ggplot(datos_long, aes(x = t, y = Valor, linetype...

...39;demo()' for some demos, 'help()' for on-line help, or > 'help.start()' for an HTML browser interface to help. > Type 'q()' to quit R. > > Desktop> library(tidyverse) > Loading tidyverse: ggplot2 > Loading tidyverse: tibble > Loading tidyverse: tidyr > Loading tidyverse: readr > Loading tidyverse: purrr > Loading tidyverse: dplyr > Conflicts with tidy packages -------------------------------------------------------------- > filter(): dplyr, stats > lag(): dplyr, stats > Desktop> library(magrittr) > > Attaching...

...e high-level >issues in case someone recognizes exactly what is happening here. > >The error is: > >Error in mut_env_parent(overscope$.top_env, lexical_env) : > object 'rlang_mut_env_parent' not found > >and it occurs in three situations: > > >1) Using tidyr::nest() on an output from dplyr::group_by() > >2) Using tibble::tibble() with <name> = <value> arguments > >3) Using dplyr::select() on a tibble to select two columns > >Any obvious clues as to what's happening here? The only non-base >packages loaded...

...[mailto:jdnewmil at dcn.davis.ca.us] Sent: 10 July 2017 03:52 PM To: r-help at r-project.org; Mangalani Peter Makananisa; r-help at r-project.org Cc: Vito Ricci (vito_ricci at yahoo.com) Subject: Re: [R] dplyr help I am pretty sure that this is not a question about dplyr... it is a question about tidyr. Look at the help file ?tidyr::spread. If I understand your question (I may not, because you gave no example of input/output data), the answer is no, the column names come from the column named by the key parameter and the values that fill those columns come from the column named by the value par...

I am pretty sure that this is not a question about dplyr... it is a question about tidyr. Look at the help file ?tidyr::spread. If I understand your question (I may not, because you gave no example of input/output data), the answer is no, the column names come from the column named by the key parameter and the values that fill those columns come from the column named by the value par...

Buenas tardes, estoy haciendo una gráfica de múltiples lineas pero no he podido generar las legendas. Alguno de ustedes me podría colaborar. library(ggplot2) #### Con b=-2 t=seq (-4, 4, by=0.01) l=exp(t+2)/(1+(exp(t+2))) ##con b igual a -1 t=seq (-4, 4, by=0.01) o=exp(t+1)/(1+(exp(t+1))) ### Con b igual a 0.7 t=seq (-4, 4, by=0.01) i=exp(t-0.7)/(1+(exp(t-0.7))) ### Con b igual a 2 t=seq

....us] >Sent: 10 July 2017 03:52 PM >To: r-help at r-project.org; Mangalani Peter Makananisa; >r-help at r-project.org >Cc: Vito Ricci (vito_ricci at yahoo.com) >Subject: Re: [R] dplyr help > >I am pretty sure that this is not a question about dplyr... it is a >question about tidyr. Look at the help file ?tidyr::spread. > >If I understand your question (I may not, because you gave no example >of input/output data), the answer is no, the column names come from the >column named by the key parameter and the values that fill those >columns come from the column na...

Another approach: ######## library(tidyr) L <- list( A = data.frame( x=1:2, y=3:4 ) , B = data.frame( x=5:6, y=7:8 ) ) D <- data.frame( Type = names( L ) , stringsAsFactors = FALSE ) D$data <- L unnest(D, data) #> Type x y #> 1 A 1 3 #> 2 A 2 4 #> 3 B 5 7...

On Wed, May 2, 2018 at 11:53 AM, Jeff Newmiller <jdnewmil at dcn.davis.ca.us> wrote: > Another approach: > > ######## > library(tidyr) > L <- list( A = data.frame( x=1:2, y=3:4 ) > , B = data.frame( x=5:6, y=7:8 ) > ) > D <- data.frame( Type = names( L ) > , stringsAsFactors = FALSE > ) > D$data <- L > unnest(D, data) > #> Type x y > #>...

Buenos días , por favor alguien me puede ayudar necesito separar en tres columnas una columna fecha que viene en el siguiente formato (01/01/1983) Muchas gracias Saludos [[alternative HTML version deleted]]

Buenas Os queria preguntar que ventaja le veis a las tibbles frente a los data.table, ya que para mi, quitando el uso de librerias como tidyr o purrr, en el resto prefiero usar data.table. Me parece igual de potente y mucho más rápido, y no le veo las supuestas ventajas, pero quiero conocer vuestra opinion. Gracias Jesús [[alternative HTML version deleted]]