search for: ta2

...2 2 idA2 uu 0 3 idA3 ee 3 4 idA4 tt 2 5 idA5 uu 4 6 idA1 gg 3 7 idA2 tt 0 8 idA3 bb 1 9 idA4 gg 0 10 idA5 ee 5 My desired outputs (5 arrays/lists classified according to distinct "id" field) are as follow: > TA1 bb ee gg tt uu 2 0 3 0 0 > TA2 bb ee gg tt uu 0 0 0 0 0 > TA3 bb ee gg tt uu 1 3 0 0 0 ...... similarly for TA4 & TA5. The above results were produced using TA1 <- c(bb=TA1.bb,ee=TA1.ee,gg=TA1.gg,tt=TA1.tt,uu=TA1.uu), TA2 <- c(bb=TA2.bb,ee=TA2.ee,gg=TA2.gg,tt=TA2.tt,uu=TA2.uu*)* etc for TA3~TA5. Althoug...

...qnorm(((nrow(hit2))/(nrow(twosaved))))-qnorm((nrow(fa2))/(nrow(twodied)))); + hitrate=((nrow(hit2))/(nrow(twosaved))); FArate=((nrow(fa2))/(nrow(twodied))); + zhit2=qnorm(((nrow(hit2))/(nrow(twosaved))));zfa2=qnorm((nrow(fa2))/(nrow(twodied)));B2= -.5*(zhit2+zfa2); + tp2=mean(twosaved$resp); + ta2=mean(twodied$resp); + tpsd2=sd(twosaved$resp); + tasd2=sd(twodied$resp); + dmj2=((tp2-ta2)/((tasd2+tpsd2)/2)); + + L=list(d2=d2,B2=B2,dmj2=dmj2,tpsd2=tpsd2,tasd2=tasd2,tp2=tp2,ta2=ta2,hitrate=hitrate,FArate=FArate) } Jasper Jancik 910.352.7546 -------------- next part -------------- An...

I know there are a lot of reshape questions on the mailing list, but I haven't been able to find an answer to this particular issue. I am trying to get a datafame structured like this: > sub <- rep(1:5) > ta1 <- rep(1,5) > ta2 <- rep(2,5) > tb1<- rep(3,5) > tb2 <- rep(4,5) > DF <- data.frame(sub,ta1,ta2,tb1,tb2) > DF sub ta1 ta2 tb1 tb2 1 1 1 2 3 4 2 2 1 2 3 4 3 3 1 2 3 4 4 4 1 2 3 4 5 5 1 2 3 4 into a form like this: sub time x1 x2 1...

...[1] "key" "AMR.pa1.M" "AMR.pa2.M" "AMR.pa3.M" "AMR.pa4.M" [6] "AMR.pa5.M" "AMR.pa6.M" "AMR.pa7.M" "AMR.pa8.M" "AMR.pa9.M" [11] "AMR.pa10.M" "AMR.ta1.M" "AMR.ta2.M" "AMR.ta3.M" "AMR.ta4.M" [16] "AMR.ta5.M" "AMR.ta6.M" "AMR.ta7.M" "AMR.ta8.M" "AMR.ta9.M" [21] "AMR.ta10.M" "AMR.ka1.M" "AMR.ka2.M" "AMR.ka3.M" "AMR.ka4.M" [26] &q...

...: <sip:21 at 10.0.0.10>;tag=6d8c6ac6 To: <sip:21 at 10.0.0.10> Call-ID: 055f7edd4081e1ec0f176e0a4b395a43 at 10.0.0.4 Contact: <sip:21 at 10.0.0.4:5090> CSeq: 1 SUBSCRIBE Max-Forwards: 70 Expires: 60 Accept: application/simple-message-summary Event: message-summary User-Agent: CM5K-TA2S (810170) Content-Length: 0 <-------------> --- (13 headers 0 lines) --- Creating new subscription Sending to 10.0.0.4 : 5090 (no NAT) list_route: hop: <sip:21 at 10.0.0.4:5090> Found peer '21' for '21' from 10.0.0.4:5090 <--- Transmitting (no NAT) to 10.0.0.4:509...

...that the user the mounted file(system) would be able to change the u/gid in the files? Just a thought... Regards, Tom Worley, Worley Web Solutions RaQ Maintenance http://worleyweb.net RaQ server help: http://uk2raq.com RaQ backup: http://uk2raq.com/backup.php TA2 game: http://totalannihilation2.com Flying Linux in space: http://projectmist.org

Hi everyone, I created a four dimensional vector (dim (128,128,1,8)). This third dimension is necessary for another function somewhere. Now I'd like to perform a t-test on every vector of length 8 in my array on the fourth dimension. I'd like to obtain a new array of three dimensions with dimensions 128x128x1 with all these test statistics. I tried this with a double loop: A <-

...e a3 $7 -#define t0 $8 /* caller saved */ -#define t1 $9 -#define t2 $10 -#define t3 $11 -#define t4 $12 +#define a4 $8 /* arg reg 64 bit; caller saved in 32 bit */ +#define ta0 $8 +#define a5 $9 +#define ta1 $9 +#define a6 $10 +#define ta2 $10 +#define a7 $11 +#define ta3 $11 +#define t4 $12 /* caller saved */ #define t5 $13 #define t6 $14 #define t7 $15 @@ -34,16 +39,17 @@ #define s6 $22 #define s7 $23 #define t8 $24 /* caller saved */ -#define t9 $25 +#define t9...