search for: suds

Hello. I am probably wrong... I am wondering if it could have a mistake in the code of the ansari.test function. For me, it seems that the function do not recover the p value at the correct side of the normal law N(0, 1) when it use the normal approximation (presence of ties) in a one tailed test. Exemple : quanti<-c(197, 205, 228, 234, 237, 195, 233, 226, 244, 227, 259, 185, 198, 253, 207,

CentOS Errata and Enhancement Advisory 2011:1006 Upstream details at : https://rhn.redhat.com/errata/RHEA-2011-1006.html The following updated files have been uploaded and are currently syncing to the mirrors: ( md5sum Filename ) i386: 691220228b9f0771061f382de6df1cb1 python-suds-0.4.1-2.el5.noarch.rpm Source: 3f3d528b8c1c69dab069483f225e78c1 python-suds-0.4.1-2.el5.src.rpm -- Karanbir Singh CentOS Project { http://www.centos.org/ } irc: z00dax, #centos at irc.freenode.net

CentOS Errata and Enhancement Advisory 2011:1006 Upstream details at : https://rhn.redhat.com/errata/RHEA-2011-1006.html The following updated files have been uploaded and are currently syncing to the mirrors: ( md5sum Filename ) x86_64: e8fb32c5b267df7121fb7cf40433b3cf python-suds-0.4.1-2.el5.noarch.rpm Source: 3f3d528b8c1c69dab069483f225e78c1 python-suds-0.4.1-2.el5.src.rpm -- Karanbir Singh CentOS Project { http://www.centos.org/ } irc: z00dax, #centos at irc.freenode.net

Dear All, I am trying to perform MANOVA. I have table with 504 columns(species) and 36 rows) with two grouping (season and location) Zx <- Z[c(4:504)] Zxm <- as.matrix(Z) m<- manova(Zxm~Season*location, data=Z) when I do summary.aov, I get respond for each species but summary.manova summary.manova(m) :" residuals have rank" 24<501. What can it be the reason for this error

Hi, do you know, a method to convert an decimal value (integer) to the corresponding hexadecimal value ? thinks for help. Romain -- Lorrilli?re Romain UMR 8079 Laboratoire Ecologie, Syst?matique et Evolution B?t. 362 Universit? Paris-Sud 91405 Orsay cedex France tel : 01 69 15 56 85 fax : 01 69 15 56 96 mobile : 06 81 70 90 70 email : romain.lorrilliere at ese.u-psud.fr

I am trying to install the python-onvif package on C7. I did: pip install onvif Requirement already satisfied (use --upgrade to upgrade): onvif in /usr/lib/python2.7/site-packages Requirement already satisfied (use --upgrade to upgrade): suds>=0.4 in /usr/lib/python2.7/site-packages (from onvif) Requirement already satisfied (use --upgrade to upgrade): suds-passworddigest in /usr/lib/python2.7/site-packages (from onvif) You are using pip version 8.1.2, however version 19.0.1 is available. You should consider upgrading via the 'pi...

Hi everybody, I have a data set with a value and a status (positive or negative case) and I want make a ROC Analysis. So, with ROCR Package, I have got the ROC curve (True Positive Fraction [tpf] according 1-True Negative Fraction [1-tnf]). http://r.789695.n4.nabble.com/file/n4469203/01.png But, now I want a new graphic which show the sum of true positive fraction and true negative fraction

Hi useRs, I'm trying for the first time to use a sem. The model finally runs, but gives a warning saying : "In sem.default(ram = ram, S = S, N = N, param.names = pars, var.names = vars, : Could not compute QR decomposition of Hessian. Optimization probably did not converge. " I found in R-help some posts on this warning, but my attemps to modify the code didn't change

Hello, R for Dummies. How can I exclude the first 1000 values of a vector (length 12000)? More generally all the values up to the ith? Thanks for your help, Dr Olivier Charansonney Cardiologue Centre Hospitalier Sud-Francilien, Corbeil-Essonnes, France [[alternative HTML version deleted]]

Rails documentation gives examples of using option_groups_from_collection_for_select with two tables/objects. How could it be done with one? Example that almost works: I have a form to enter address from both the United States and Canada. It has the following: ====new.html.erb==== <%= select_tag( :state, option_groups_from_collection_for_select( State.countries, :country,

Dear members, I have a series of values in a vector and some value are missing and replaced with NA. For example: a <- c(27, 25, NA, NA, 24, 26, 27, NA, 26) I would like to replace the NAs with the value taken from the previous value that is non-NA. The output would be in this case: 27 25 25 25 24 26 27 27 26 Now I do that with a for loop, but I try to eliminate all the loops to gain in

Hello, I need to read a vector containing names of different variables from a text file (a unique column). Among them one is called "T". When I use the function read.table with default arguments and when I call the element of the data frame corresponding to name of this variable it returns me the logical value "TRUE" whereas I was expected it to return the character

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Hello, I'm apologize to have made failure before. I wrote this : p<-scan("teststat.txt") on R and R returns Error in scan ("teststat.txt") : "scan" expected a real, got "x". I don't really understand,because teststat has been created, so........ Thanks a lot. Sandrine

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*This message was transferred with a trial version of CommuniGate(tm) Pro* Hello, I'm new to Linux, I work on a PC, Mac, and now Linux network. I have been looking for somthing like samba that will work on Xwindows. If you could point me in the right direction I would be thankfull. Hope to hear from you soon, Zeek Bower.

Hi, I am seeing a strange behavior on windows XP pro with CopSSH installed. Every time I run the activate.sh and create a ssh account and subsequently when attempted to delete the folder or any files in the folder windows doesn't seem to allow any change to the directory. To fill in some background info here's what I am doing. I am changing the root directory for the SSH user by changing

Hello list I use a samba (version 3.0.14) PDC and Cups (1.2.7) for sharing printers with windows clients. When I create a new printer in Cups i have to wait a long time (abour 20 minutes) to see the printer in Samba's sharing Here is my Print sectin of the smb.conf [printers] path = /tmp print ok = yes browseable = yes printable = yes printer admin = @users, root [print$] path =

Hello, Is it possible to build a function, a posteriori, by getting the names of the arguments and the formula in a list or a vector ? When I use the function as.function(), I don't know how to define explicitly the names of my variables as formal arguments. Thanks _______________________________________ Florent BATY CNRS UMR 5558 Dynamique des Populations Bact?riennes Facult? de

Hello R-helpers, I'm trying to customize a graphic in lattice using the 'legend' argument to add labels on my plot but in the process I'm losing the legend drawn by 'auto.key', despite the fact that I'm actually not sticking these on the same sides of the graphic. I worked up a quick and simple example with the iris data : ### here's the basic graph