search for: substrings

Hi all, (and especially hi to Tomas Kalibera who accepted my patch sent yesterday) I believe that I have found another bug, this time in the substring function. The use case that I am concerned with is when there is a single (character scalar) text/subject, and many substrings to extract. For example substring("AAAA", 1:4, 1:4) or more generally, N=1000 substring(paste(rep("A", N), collapse=""), 1:N, 1:N) The problem I observe is that the time complexity is quadratic in N, as shown on this figure https://github.com/tdhock/namedCapture-ar...

...especially hi to Tomas Kalibera who accepted my patch sent >> yesterday) >> >> I believe that I have found another bug, this time in the substring >> function. The use case that I am concerned with is when there is a single >> (character scalar) text/subject, and many substrings to extract. For example >> >> substring("AAAA", 1:4, 1:4) >> >> or more generally, >> >> N=1000 >> substring(paste(rep("A", N), collapse=""), 1:N, 1:N) >> >> The problem I observe is that the time complexity is quad...

Hi, I have a buster system configured as a DC running 4.11.13 from Louis's repo. I am trying to get https://wiki.samba.org/index.php/Configure_DHCP_to_update_DNS_records_with_BIND9 working. Mostly it seems to work but there seems to be a problem with what dhcpd writes into the leases file in the "on release" stanza. When dhcpd writes the On Release stanza I get something like the

...: > Hi all, (and especially hi to Tomas Kalibera who accepted my patch sent > yesterday) > > I believe that I have found another bug, this time in the substring > function. The use case that I am concerned with is when there is a single > (character scalar) text/subject, and many substrings to extract. For example > > substring("AAAA", 1:4, 1:4) > > or more generally, > > N=1000 > substring(paste(rep("A", N), collapse=""), 1:N, 1:N) > > The problem I observe is that the time complexity is quadratic in N, as > shown on this fi...

Hi, According to its man page substring() "expands (its) arguments cyclically to the length of the longest _provided_ none are of zero length". So, as expected, I get an error here: > substring("abcd", first=2L, last=integer(0)) Error in substring("abcd", first = 2L, last = integer(0)) : invalid substring argument(s) But I don't get one here:

Dear all, I have a string, let's say "testing", and I would like to extract in sequence each letter (character) from it. But when I use substr() I only properly get the first character, the rest is empty (""). What am I getting wrong? For example, I have this code: >>> x <- "testing" k <- nchar(x) for (i in 1:k) { y <- substr(x, i, 1)

Hi, A noobie question: I'm simply trying to run a conditional statement that evaluates if a substring is found within a larger string. I find that if it IS found, my function returns TRUE (great!), but if not, the condition does not evaluate to FALSE. ex): if( grep("hi", "hop", fixed = TRUE) ) print('yes, your substring is in your string') else

In y <- substr(x, i, 1) your third integer needs to be the location not the number of digits, so change it to y <- substr(x, i, i) and you should get what you want. Cheers, Tim > Date: Sun, 21 Jan 2018 10:50:31 -0500 > From: Ek Esawi <esawiek at gmail.com> > To: Luigi Marongiu <marongiu.luigi at gmail.com>, r-help at r-project.org > Subject: Re: [R] substr

Hi there, I'm pretty sure that it's written down somewhere but I cannot find it so far. The little example shows different approaches to replace a substring. Only the last one works. I think it has something to do with the fact that "substr" is used on the left side. Can anybody refer to an explanation for this behaviour? Thanks a lot in advance! Antje values <-

Hello together, i have a question for "substring". I know i can filter a number like this one: bill$No<-substring(bill$Customer,2,4) in this case i get the 2nd, 3rd and 4th number of my Customer ID. But how can i do this, if i want the 2nd, 3rd and 4th number of a column. Like this one. I have: Mercedes_02352 Audi_03555 and now i want to filter this data.frame to 235 355 can you

Hi, Do anybody know when and why the below error we get? Error in substr(x, as.integer(start), as.integer(stop)) : invalid substring argument(s) in substr() Thanks in advance, Shubha [[alternative HTML version deleted]]

Hi All, I'm looking for a way to get many substrings from a longer string and then stitch them together. But, since the longer string is really, really long (like 250 MB long), I don't want to do this in a loop and load and re-load the longer string many times. Does anybody have an idea? Maybe I could pass in two vectors (the first would have...

Hi, In R < 3.0.0, we used to get: > substring(c(A="abcdefghij", B="123456789"), 2, 6:2) A B A B A "bcdef" "2345" "bcd" "23" "b" But in R >= 3.0.0, we get: > substring(c(A="abcdefghij", B="123456789"), 2, 6:2) [1] "bcdef"

Hi, Given a date, how do I get the last date of that month? I have data in the form YYYYMM, that I've read as a date using > x$Date <- as.Date(ISOdate(substr(x$YearEnd,1,4),substr(x$YearEnd,5,6),1)) But this gives the first day of the month. To get the last day of the month, I tried > as.Date(as.yearmon(x$Date,frac=0)) But I don't get the last day of the month here. (Tried

Hi, (First, apology for my earlier incorrectly addressed "subscribe" post.) Can somebody tell me what exactly is going on below. Basically, I am running into some kind of "string truncation" problem when I try to get a substring starting past the 8192nd character (see sample session below). There doesn't appear to be any problem creating the string, and nchar()

Hi, Is there an easy way to test if a substring exists in a string? I''m using this check: if mystring.index(substring) > 0 but it doesn''t seem to be working.... Thanks! -- Posted via http://www.ruby-forum.com/.

Dear R Users, I am trying to replace a substring in a string with something else. For example: if we have "abc.degg.hijk" I would like to replace all the "." with a SPACE to become "abc degg hijk" I have tried the replace.substring.wild function in the Hmisc package but get this error: > replace.substring.wild("abc.degg.hijk","*.*","

Dear R users, I am trying to fill in arrays (5 different according to distinct "id") from objects produced from arbitrary data set below. a <-

... when the replacement string is shorter than the portion of the string to be replaced? The documentation to substr (in R 1.3.1) gives me: If the portion to be replaced is longer than the replacement string, then only the portion the length of the string is replaced. And so I try: R> x <- "abcdef" R> substr(x,2,3) <- "xy" #ok R> x [1]

... when the replacement string is shorter than the portion of the string to be replaced? The documentation to substr (in R 1.3.1) gives me: If the portion to be replaced is longer than the replacement string, then only the portion the length of the string is replaced. And so I try: R> x <- "abcdef" R> substr(x,2,3) <- "xy" #ok R> x [1]