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Dear R Group I had an observation that in some cases, when I use the randomForest model to create partialPlot in R using the package "randomForest" the y-axis displays values that are more than -1! It is a classification problem that i was trying to address. Any insights as to how the y axis can display value more than -1 for some variables? Am i missing something! Thanks Regards

Dear R Group I have a character vector from which I want to select a few elements and create a new character vector. I need a GUI to do this in R Script. Can someone help? a<-c("A","B","C","D","E") ## I want to have a GUI in R that will display elements in "object a" as a drop down list.. from there I want to be able to select a

...Dr Riyad Ismail GIS / Remote Sensing Analyst Sappi Forests (Reg No 1976/02426/07) Tel +27 (0)33 347 6650 Fax +27 (0)33 347 6790 E-mail: riyad.ismail@sappi.com The opinions contained in this message are those of the sender only and do not reflect those of Sappi Limited or any of its subsidiary or associated companies. "This message, including any attachment(s), may contain information which is private, privileged or confidential and is intended solely for the use of the individual or entity named in this message. If you are not the intended recipient of this message, please notify...

Dear R Group Can any body point me to a link from where I can get zip archive of the package HH for R 2.12.0? Thanks & Regards Vijayan Padmanabhan "What is expressed without proof can be denied without proof" - Euclide. Please visit us at www.itcportal.com ****************************************************************************** This Communication is for the exclusive use

Dear Group I have to populate a column in a R dataframe containing say 99 rows, where for every 3 row one row (randomly determined) of the column should take the value 1 and the other 2 row of that column should take the value 0. I used the command dataframe$new<-rep(sample(c(0,1,0),3,replace=FALSE),99) This command repeats the same patter of response across the entire column.. I would

Dear R-Users, I've written a number of functions in a .R/script file. I would like to call those functions from another script file. How can I execute all the code in a script file so that the functions are available for use in my other script file ? I have tried help.search("script") and various Google alternatives but couldn't come up with anything. Thanks in advance,

Dear R Users, I am trying to get plot.zoo to place monthy tickmarks/labels for a time series which spans daily data going back a bit over a year. Right now, I am getting only one tick mark on the x-axis for the beginning of 2008. How can I force plot.zoo to place more regular x-axis tick marks on a monthly basis ? Thanks in advance, Tolga Generally, this communication is for informational

It has always been my understanding that deviance for GLMs is defined by; D = -2(loglikelihood(model) - loglikelihood(saturated model)) and this can be calculated by (or at least usually is); D = -2(loglikelihood(model)) As is done so in the code for 'polr' by Brian Ripley (in the package 'MASS') where the -loglikehood is minimised using optim; res <-

Dear R Users, A bit of an elementary question, but somehow, I haven't been able to figure it out. I'd like to changes the column names of a data frame, so I am looking for something like col.names (as in row.names). Could someone please show me how to change the column names of a data frame ? Thanks, Tolga Generally, this communication is for informational purposes only and it is

Hello all, I have an ordered factor that I would like to include in the linear predictor of a binomial glm, where the estimated coefficients are constrained to be monotonic. Does anyone know how to do this? I've tried using an ordered factor but this does not have the desired effect, an (artificial) example of this follows; n <- 100 strings <- sample(c("low",

Last year I sent the email below describing a bug in openssh 5.6p1. I just noticed this bug still exists in 5.9p1. Probably my earlier email was treated as spam because it was in HTML format. -- Robert Dugal Team Lead SSL & PKI Group Certicom Corp. A Subsidiary of Research In Motion 4701 Tahoe Blvd., Building A Mississauga, ON L4W 0B5 rdugal at certicom.com direct??????? +1.289.261.4148 mobile?????? +1.416.276.8062 main ??? ???? +1.905.507.4220 fax?? ?????????? +1.905.507.4230 www.certicom.com F...

Dear R Users, I would like to get the pdf() command to create graphics in landscape mode, as I am plotting 8 graphs in 2 rows and 4 columns. This is being generated for an a4 printer (so I also use the paper="a4" command). Is there a way I can ask pdf() to generate the document in landscape mode ? Thanks, Tolga Generally, this communication is for informational purposes only and it

Dear R Users, Can anyone point me to a package for R vrsion 2.7.1 which implements some Hurst exponent estimation methods ? Thanks in advance, Tolga Generally, this communication is for informational purposes only and it is not intended as an offer or solicitation for the purchase or sale of any financial instrument or as an official confirmation of any transaction. In the event you are

...5 Pr evClose : $0.18 Rec ommendation: ST RON G-B UY WATCH THIS STO CK GO HIGHER AND HIGHER DON'T MI SS THIS INVE STM ENT MOMENT, PLACE CRSVF ON THE PORT FO LIO!!! About Capital Reserve Canada: CRC is an oil, gas services company based in Edmonton, Alberta. Through its wholly owned subsidiary, KCP Innovative Services, Inc., CRC offers technologically tools for use in several areas of the industry. The first aids in development & testing of newly found resources; another measure existing wells' productivity; and the third hastens well abandonment, ensuring compliance with regula...

Hi all, I''m having two tables: contacts (belongs_to) company details. The problem is this. In the company table I have a field "pid" (parent id). Which relates a company (being a possible subsidiary) to it''s parent e.g. a bigger enterprise. Does the belongs_to work when related to the same model (table). The relation is upwards only for now. I don''t want to see all subsidiaries of an enterprise (yet). Do I need a seperate table to establisch this link properly in my data...

Dear R user, I have a simple question for you: I have created a global function that evoke other subsidiary functions. when I run the global function I want to store the outcomes of the of each subsidiary function into a variables. an examples my.fun=function(vector, index){ a=fun.a(vector, index) b=fun.b(vector, index) } if i use return() I can only retrive one single results. what can I...

...5 Pr evClose : $0.18 Rec ommendation: ST RON G-B UY WATCH THIS STO CK GO HIGHER AND HIGHER DON'T MI SS THIS INVE STM ENT MOMENT, PLACE CRSVF ON THE PORT FO LIO!!! About Capital Reserve Canada: CRC is an oil, gas services company based in Edmonton, Alberta. Through its wholly owned subsidiary, KCP Innovative Services, Inc., CRC offers technologically tools for use in several areas of the industry. The first aids in development & testing of newly found resources; another measure existing wells' productivity; and the third hastens well abandonment, ensuring compliance with regula...

Dear R Users, I am trying to do something quite simple: replace the elements of a zoo object. For some reason, the following code does not seem to work. How can I replace the value for the 14th of Dec of 2008 in the zoo object x below with 1 (it is currently NA). > x 2008-12-11 2008-12-12 2008-12-13 2008-12-14 2008-12-15 2008-12-16 361.667 389.875 NA NA 397.822

That's problem. AHCI is the standard for SATA, running modern SATA drives, especially SSD require the AHCI command structure. Running modern SATA drives in IDE (ATA) mode is not readily supported. -Jason -- -=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=- - - - Jason Pyeron PD Inc.

fit lwr upr 1 218.4332 90.51019 346.3561 2 218.3906 90.46133 346.3198 3 218.3906 90.46133 346.3198 4 161.3982 44.85702 277.9394 5 192.4450 68.39903 316.4909 6 179.8056 56.49540 303.1158 7 219.5406 91.52707 347.5542 8 162.6761 46.65760 278.6945 9 193.8506 70.59838 317.1029 10 181.3816 58.11305 304.6502 11 221.2871 92.14366 350.4305 12 164.2947 47.91081 280.6785 13