search for: styen

...tor. > >You could alternatively use > >x["V2"] > >which should be identical to x[, "V2", drop = FALSE], but some people don't >like that because it doesn't look like matrix indexing anymore. > > >On Sun, Feb 12, 2023, 17:18 Steven T. Yen <styen at ntu.edu.tw> wrote: > >> In the line suggested by Andrew Simmons, >> >> mydata <- mydata[, !grepl("^yr", colnames(mydata)), drop = FALSE] >> >> what does drop=FALSE do? Thanks. >> >> On 1/14/2023 8:48 PM, Steven Yen wrote: >> >...

...at you would normally catch with a subscript out of bounds error but with the extra space it now runs without errors. Tim -----Original Message----- From: R-help <r-help-bounces at r-project.org> On Behalf Of Richard O'Keefe Sent: Thursday, February 29, 2024 5:29 AM To: Steven Yen <styen at ntu.edu.tw> Cc: R-help Mailing List <r-help at r-project.org> Subject: Re: [R] Initializing vector and matrices [External Email] x <- numeric(0) for (...) { x[length(x)+1] <- ... } works. You can build a matrix by building a vector one element at a time this way, and then re...

...Or use <<- assignment I think. (I usually return, but return can only > return one object and I think you want two or more > > v <- 1 > funC <- function() { > v <<- v+1 > } > > funC() > cat (v) > #2 > > On Fri, 9 Aug 2024, 09:03 Steven Yen, <styen at ntu.edu.tw> wrote: > > > Thanks. Hmm. The loop is doing what it is supposed to do. > > > > > try1<-function(joint12=FALSE,marg1=FALSE,marg2=FALSE, > > + cond12=FALSE,cond21=FALSE){ > > + # **************************************************...

You could also do dim(x) <- c(length(x), 1) On Sat, Aug 5, 2023, 20:12 Steven Yen <styen at ntu.edu.tw> wrote: > I wish to stack columns of a matrix into one column. The following > matrix command does it. Any other ways? Thanks. > > > x<-matrix(1:20,5,4) > > x > [,1] [,2] [,3] [,4] > [1,] 1 6 11 16 > [2,] 2 7 12 17 >...

...t may help guide a better answer. -----Original Message----- From: R-help <r-help-bounces at r-project.org> On Behalf Of Eric Berger Sent: Sunday, August 6, 2023 3:34 AM To: Bert Gunter <bgunter.4567 at gmail.com> Cc: R-help Mailing List <r-help at r-project.org>; Steven Yen <styen at ntu.edu.tw> Subject: Re: [R] Stacking matrix columns Stacking columns of a matrix is a standard operation in multilinear algebra, usually written as the operator vec(). I checked to see if there is an R package that deals with multilinear algebra. I found rTensor, which has a function vec()....

...) { v <- v+1 return (v) } v <- funB() cat (v) #2 Or use <<- assignment I think. (I usually return, but return can only return one object and I think you want two or more v <- 1 funC <- function() { v <<- v+1 } funC() cat (v) #2 On Fri, 9 Aug 2024, 09:03 Steven Yen, <styen at ntu.edu.tw> wrote: > Thanks. Hmm. The loop is doing what it is supposed to do. > > > try1<-function(joint12=FALSE,marg1=FALSE,marg2=FALSE, > + cond12=FALSE,cond21=FALSE){ > + # *************************************************** > + # Testing if loop &g...

...s way, and then reshaping it at the end. That only works if you don't need it to be a matrix at all times. Another approach is to build a list of rows. It's not a matrix, but a list of rows can be a *ragged* matrix with rows of varying length. On Wed, 28 Feb 2024 at 21:57, Steven Yen <styen at ntu.edu.tw> wrote: > > Is there as way to initialize a vector (matrix) with an unknown length > (dimension)? NULL does not seem to work. The lines below work with a > vector of length 4 and a matrix of 4 x 4. What if I do not know > initially the length/dimension of the vector/...

...ipt out of bounds error but with the extra space it now runs without errors. > > Tim > > > > -----Original Message----- > From: R-help <r-help-bounces at r-project.org> On Behalf Of Richard O'Keefe > Sent: Thursday, February 29, 2024 5:29 AM > To: Steven Yen <styen at ntu.edu.tw> > Cc: R-help Mailing List <r-help at r-project.org> > Subject: Re: [R] Initializing vector and matrices > > [External Email] > > x <- numeric(0) > for (...) { > x[length(x)+1] <- ... > } > works. > You can build a matrix by building...

...definitely not "our" problem, so I suggest you start looking for a consultant if this issue is that important to you. Such is the nature of volunteer-developed open source software... so support your local experts. >> >>> On October 8, 2020 10:22:54 AM PDT, Steven Yen <styen at ntu.edu.tw> wrote: >>> Thanks for the help. I have a reason to continue with R-3.0.3. I used >>> maxLik to estimate econometric models and some of them are better >>> handled with R-3.0.3 (but not later)----a sad reality I do not like. >>> >>> Her...

Hi Steven Which optimisation algorithms in maxLik work better under R-3.0.3 than under the current version of R? /Arne On Thu, 8 Oct 2020 at 21:05, Steven Yen <styen at ntu.edu.tw> wrote: > > Hmm. You raised an interesting point. Actually I am not having problems with aod per se?-it is just a supporting package I need while using old R. The essential package I need, maxLik, simply works better under R-3.0.3, for reason I do not understand?specifically...

...gt; > marg1 <-T > > if (joint12) { > ? print ("joint 12") > ? cat (joint12) > } > > if (marg1) { > ? print("marg 1") > ? cat(marg1) > } > > Would probably be my diagnostic approach > > > On Fri, 9 Aug 2024, 04:45 Steven Yen, <styen at ntu.edu.tw> wrote: > > Can someone help me with the if loop below? In the subroutine, I > initialize all of (joint12,marg1,marg2,cond12,cond21) as FALSE, > and call > with only one of them being TRUE: > > ,...,joint12=FALSE,marg1=FALSE,marg2=FALSE,cond...

...18 19 20 > > ## well, you get it... > > -- Bert > > On Sat, Aug 5, 2023 at 5:21?PM Iris Simmons <ikwsimmo at gmail.com> wrote: > > > > You could also do > > > > dim(x) <- c(length(x), 1) > > > > On Sat, Aug 5, 2023, 20:12 Steven Yen <styen at ntu.edu.tw> wrote: > > > > > I wish to stack columns of a matrix into one column. The following > > > matrix command does it. Any other ways? Thanks. > > > > > > > x<-matrix(1:20,5,4) > > > > x > > > [,1] [,2] [,3] [...

...t; grepl(glob2rx("yr*"), colnames(mydata)) > > Then you might write something like this to remove the columns starting with yr: > > mydata <- mydata[, !grepl("^yr", colnames(mydata)), drop = FALSE] > >> On Sat, Jan 14, 2023 at 1:56 AM Steven T. Yen <styen at ntu.edu.tw> wrote: >> >> I have a data frame containing variables "yr3",...,"yr28". >> >> How do I remove them with a wild card----something similar to "del yr*" >> in Windows/doc? Thank you. >> >>> colnames(mydata)...

which(grepl(....)) looks odd. Doesn't grep by itself return the correct vector of indices? Regards, Jorgen Harmse.? Message: 5 Date: Fri, 12 Jul 2024 17:42:05 +0800 From: Steven Yen <styen at ntu.edu.tw <mailto:styen at ntu.edu.tw>> To: Uwe Ligges <ligges at statistik.tu-dortmund.de <mailto:ligges at statistik.tu-dortmund.de>>, R-help Mailing List <r-help at r-project.org <mailto:r-help at r-project.org>> Cc: Steven Yen <syen04 at gmail.com <mai...

? Fri, 4 Oct 2024 20:28:01 +0800 Steven Yen <styen at ntu.edu.tw> ?????: > Suppose I have two vectors, x and y. Is there a way > to do the covariance matrix with ?apply?. There is no covariance matrix for just two samples (vectors) 'x' and 'y'. You can only get one covariance value for these. If you had a pair of vector...

...ve uhat<-m%*%y but when the package is built (successfully), the matrix multiplication part does not show up in the documentation. The line become (missing %*% y) uhat<-m === \examples{ x<-c(1,2,3,4,5) y<-c(1,1,2,2,4) x<-cbind(1,x) m<-mmat(x) uhat<-m%*%y dstat(uhat) } ?-- styen at ntu.edu.tw (S.T. Yen) [[alternative HTML version deleted]]

...swer. > > -----Original Message----- > From: R-help <r-help-bounces at r-project.org> On Behalf Of Eric Berger > Sent: Sunday, August 6, 2023 3:34 AM > To: Bert Gunter <bgunter.4567 at gmail.com> > Cc: R-help Mailing List <r-help at r-project.org>; Steven Yen <styen at ntu.edu.tw> > Subject: Re: [R] Stacking matrix columns > > Stacking columns of a matrix is a standard operation in multilinear > algebra, usually written as the operator vec(). > I checked to see if there is an R package that deals with multilinear > algebra. I found rTensor...

...ossibly thousands of times and figuring out some slick way to summarize all those runs without thousands of printouts that you are not going to wade through anyway and would only slow the computer down (printing really does slow the computer down!) On March 25, 2024 9:00:49 PM PDT, Steven Yen <styen at ntu.edu.tw> wrote: >I just like the subroutine to spit out results (Mean, Std.dev, etc.) and also be able to access the results for further processing, i.e., > >v$Mean > >v$Std.dev > >On 3/26/2024 11:24 AM, Richard O'Keefe wrote: >> Not clear what you mean by &q...

mydata[, -grep("^yr",colnames(mydata))] On Sat, Jan 14, 2023 at 8:57 AM Steven T. Yen <styen at ntu.edu.tw> wrote: > I have a data frame containing variables "yr3",...,"yr28". > > How do I remove them with a wild card----something similar to "del yr*" > in Windows/doc? Thank you. > > > colnames(mydata) > [1] "year"...

I have a data frame containing variables "yr3",...,"yr28". How do I remove them with a wild card----something similar to "del yr*" in Windows/doc? Thank you. > colnames(mydata) ? [1] "year"?????? "weight"???? "confeduc"?? "confothr" "college" ? [6] ... ?[41] "yr3"??????? "yr4"???????