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...eply. I am using Friedman racing test. According the the book "Pratical Nonprametric Statistic" by WJ Conover, after computing the statistics, he suggested to use chi-squared or F distribution to accept or reject null hypothesis. After looking into the source code, I found that R uses chi-sqaured distribution as below: PVAL <- pchisq(STATISTIC, PARAMETER, lower = FALSE) but still I cant figure out why they are using this pschisq insted of dchisq. Sorry I am wrong!! Thanking you truly Prasanna > >----- Original Message ----- >From: "Dimitris Rizopoulos"...

I am working with a RCB 2x2x3 ANCOVA, and I have noticed a difference in the calculation of sum of squares in a Type III calculation. Anova output is a follows: > Anova(aov(MSOIL~Forest+Burn*Thin*Moisture+ROCK,data=env3l),type=3) Anova Table (Type III tests) Response: MSOIL Sum Sq Df F value Pr(>F) (Intercept) 22.3682 1 53.2141 3.499e-07 *** Forest

Dear Rs: outer(1:3, 1:3, function(df1, df2) qf(0.95, df1, df2)) I compare this F distribution results with the table, the answers were perfect. But I need to see for chi-sqaured distribution. When I employed the similar formula outer(1:3, 1:3, function(df1, df2) qchisq(0.95, df1, df2)) , I am getting unexpected results. I need to see the following values: p=0.750 ..... 1 1.323 2 2.773 3 4.108 Thanking you Prasanna Prasanna Balaprak...

I wanna to do a Regression type 2 or Regression with X measured with error....anybody knows how can i make it in R?? thanks! -- View this message in context: http://r.789695.n4.nabble.com/Regression-type-2-x-measured-with-error-tp3251875p3251875.html Sent from the R help mailing list archive at Nabble.com.

All: Any ideas on how to do variance component estimation, or at least get Expected Mean Sqaures out of the modeling commands. Thanks. Tony Tony Long Ecology and Evolutionary Biology Steinhaus Hall University of California at Irvine Irvine, CA 92697-2525 Tel: (949) 824-2562 (office) ****NOTE NEW AREA CODE**** Tel: (949) 824-5994 (lab) ****NOTE NEW AREA CODE***...

...rix of all days of all people for all drugs. So since there are 26 drugs, I am expected to form a 26x26 matrix for all this data. I am not even sure if this is possible. Can anyone point me in the right direction? PS: If I make individual matrix and combine them using cbind(), it is not a 26x26 sqaure matrix. Any help would be greatly appreciated. Thanks

...uot;ftable" with percentages on the wishlist. The "mcl" package is for estimating multinomial logistic models using conditional logistic regression. This gives greater flexibility in imposing restrictions on the dependent variable. One application is to estimate loglinear models for sqaure tables (e.g. quasi-independence, quasi-symmetry) with covariates. The mcl package therefore contains a number of functions for models for square tables as well. A caveat is that "clogit" in R doesn't produce the same estimates as "multilog", although the likelihood functio...

...r(1:3, 1:3, function(df1, df2) qchisq(0.95, df1)) ^^^^^^^^^^^^^^^^^^^^ Regards, Vito you wrote: Dear Rs: outer(1:3, 1:3, function(df1, df2) qf(0.95, df1, df2)) I compare this F distribution results with the table, the answers were perfect. But I need to see for chi-sqaured distribution. When I employed the similar formula outer(1:3, 1:3, function(df1, df2) qchisq(0.95, df1, df2)) , I am getting unexpected results. I need to see the following values: p=0.750 ..... 1 1.323 2 2.773 3 4.108 Thanking you Prasanna ===== Diventare costru...

...eply. I am using Friedman racing test. According the the book "Pratical Nonprametric Statistic" by WJ Conover, after computing the statistics, he suggested to use chi-squared or F distribution to accept or reject null hypothesis. After looking into the source code, I found that R uses chi-sqaured distribution as below: PVAL <- pchisq(STATISTIC, PARAMETER, lower = FALSE) but still I cant figure out why they are using this pschisq insted of dchisq. Sorry I am wrong!! Thanking you truly Prasanna ===== Diventare costruttori di soluzioni Became solutions' constructors &q...

...be chosen (like a tickbox in a html form). The data captured on a mobile device and is supplied in a format where every option is a separate variable (logical). I want to develop a generic function to process these questions. As part of the analysis I want make a matrix of the p-value from the Chi-sqaure test for all combinations of options for each question. I tried to make a dataframe with all possible combinations and then use that in a loop to get the p-values with chisq.test() . It works if I specify the combination by hand but not in the loop. What am I doing wrong? ( I would appreciate any...

Hi !! <p> I am just now reading Vorbis I specifications . I ahve some quries in that regading overlap add and sqaure polar mapping . I am writting this mail with the hope that ,some one will resolve my quries. <p> 1. After IMDCT , to remove the aliasing , we do overlap and add . For that the window should have following properties -------------> hk = h2n-1-k and (hk* hk) + (...

hi I''m making a chess board app in Rails using the scriptaculous drag and drop stuff. A couple of questions, I am having trouble putting the chess pieces in the correct place - simply it seems that when i make somethign draggable it changes its positioning to relative - not so good for putting pieces on a board. Why is this ? Also i can''t see an OnDrop callback in the API

Hello everybody, Could someone please send me a very simple example using Fortran from R? Say pass a value to an executable and get the result in R. Actually it seems it may be possible to call an *.f file ?? or I am wrong again? The manual is very terse on the subject. Thank you very much Stephen Elijah -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help

Hi R- User I have very big data set (5000 rows). I wanted to make classes based on a column of that table (that column has the data which is continuous .) After converting into different class, this class would be Unique ID. I want to run regression for each ID. For example I have a data set > dput(dat) structure(list(ID = c(0.1, 0.8, 0.1, 1.5, 1.1, 0.9, 1.8, 2.5, 2, 2.5, 2.8, 3, 3.1, 3.2,

CRAN (and crantastic) updates this week New packages ------------ * disclapmix (0.1) Maintainer: Mikkel Meyer Andersen Author(s): Mikkel Meyer Andersen and Poul Svante Eriksen License: GPL-2 http://crantastic.org/packages/disclapmix disclapmix makes inference in a mixture of Discrete Laplace distributions using the EM algorithm. * EstSimPDMP (1.1) Maintainer: Unknown Author(s):