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Hi All, I'm trying to format the y-axis in an xyplot to show numbers with a comma separating the thousands but I'm not able to do it using formatNum(y, big.mark=","). This is what I have: library(lattice) year<-c(2003,2004,2005,2006,2007,2008,2003,2004,2005,2006,2007,2008)

If I combine elements into a list b <- c(22.4, 12.2, 10.9, 8.5, 9.2) my.c <- sample.int(round(2*mean(b)), 5) my.list <- list(b, my.c) the names of the elements seems to get lost in the process: > str(my.list) List of 2 $ : num [1:5] 22.4 12.2 10.9 8.5 9.2 $ : int [1:5] 11 8 6 9 20 If I explicitly name the elements at list-creation, I get what I want: my.list <- list(b=b,

Hi, Given a frame with calendar date's: "2005-07-01", "2005-07-02","2005-07-03","2005-07-04","2005-07-05",etc. I want to extract the following from these dates: week number month number year number Any ideas how to accomplish this? Many thanks. Regards, Richard

It is not a pure R question,but I hope some one can give me advices. I want to use analysis my data with the multilevel model.The data has 2 levels---- the second level has 52 units and each second level unit has 19-23 units.I think the sample size is quite small,but just now I can't make the sample size much bigger.So I want to ask if I use the multilevel model to analysis the data set,will

it takes a long time to load the lme4 package.anyone else encounter this problem? > system.time(library(lme4)) 佋佖伻侂佇佽佉仾伒伳伋佁伡伃伆侟仯伜Matrix 佋佖伻侂佇佽佉仾伒伳伋佁伡伃伆侟仯伜lattice [1] 19.90 0.30 25.56 NA NA > version _ platform i386-pc-mingw32 arch i386 os mingw32 system i386, mingw32 status Patched major 2 minor

the data file has such structure: 1992 6245 49 . . 20 1 0 0 8.739536 0 . . . . . . . . "alabama" . 0 . 1993 7677 58 . . 15 1 0 0

data from multilevel units,first sample the class ,and then the student in calss.following is the 2-level model. and the level-1 model deals with the student,and the level-2 model deals with the class level the students belong to. Level-1 Model Y = B0 + B1*(ZLEAD) + B2*(ZBUL) + B3*(ZSHY) + R Level-2 Model B0 = G00 + U0 B1 = G10 + G11*(ZWARMT) + U1 B2 = G20 + G21*(ZWARMT) + G22*(ZABLET) +

-- R Help List -- I am looking for a bivariate normal cdf routine in R. I have some fortran routines for this, which appear to be based on 15-point quadrature. Any guidance/suggestions on making these in loadable R-functions would be appreciated. Thanks, Dan =-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-= Daniel A. Powers, Ph.D. Department of Sociology University of Texas at Austin

entercount an error with demo(scoping). > demo(scoping) demo(scoping) ---- ~~~~~~~ ___snip_____ > ross$balance() Your balance is 120 > try(ross$withdraw(500)) Error in ross$withdraw(500) : You don't have that much money! > version _ platform i486-pc-linux-gnu arch i486 os linux-gnu system i486, linux-gnu status beta major 2 minor

The green book tells:"The basic technique is classic :keep it simple ."A long ,complicated expression or function is less fravorable than" a relatively small computations that combines calls to a few other functions to perform its tasks." But I don't get the point totally.Can anyone give me an example to make me understand this rules totally? ps: Is it mean that f1 is

i study the code of function ave,but i can understand one line of the syntax. > ave function (x, ..., FUN = mean) { n <- length(list(...)) if (n) { g <- interaction(...) split(x, g) <- lapply(split(x, g), FUN) } else x[] <- FUN(x) x } my question is : what does "split(x, g) <- lapply(split(x, g), FUN)" mean? thank you! --

I want to get the logLik to calculate McFadden.R2 ,ML.R2 and Cragg.Uhler.R2, but the value from multinom does not have logLik.So my quetion is : is logLik meaningful to multinomial logistic model from multinom?If it does, how can I get it? Thank you! ps: I konw VGAM has function to get the multinomial logistic model with logLik, but I prefer use the function from "official" R

Hi! Thanks for the replies! I understand people more accustomed to R doesn't like looping much, and that thinking about loops is something I do since I worked with Stata a lot. The syntax from Peter Dalgaard was really clever, and I learned a lot from it, even though it didn't solve my problem (I guess it wasn't very well explained). My problem was basically that I have a data matrix

Um, if you insist on doing it that way, at least use assign(varname, as.vector(get(varname))) -pd > On 4 Dec 2017, at 22:46 , Love Bohman <love.bohman at sociology.su.se> wrote: > > Hi! > Thanks for the replies! > I understand people more accustomed to R doesn't like looping much, and that thinking about loops is something I do since I worked with Stata a lot. The

I am trying to download the R program, but am having trouble. I have read through the instructions, but do not seem to be able to do it properly. Can you tell me the step-by-step instructions? Joanne L. Butler, Post-doctoral Fellow Equity and Technology Research Project c/o Department of Sociology Acadia University Wolfville, N.S. B4P 2R6 phone (902) 585-1535 fax (902) 585-1769

The incorrect result incurs when the file path contains Chinese character. It seems that dirname/basename action on unit of byte instead of char, so the result in the following example is half of what is expected. > g<-"d:\\$BG!2L4^M-CfJ8(B\\$BG!2L4^M-CfJ8(B.txt" > dirname(g) [1] "d:/$BG!2L4^(B" > basename(g) [1] "$BG!2L4^M-(B" -- HUANG Ronggui,

c <- structure(c(2L, 2L, 1L, 3L, 4L, 2L, 3L, 2L, 3L, 2L, 5L), .Label = c("foo", + "bar", "a really really long variable label mostly here to show the need of word-wrapping text in labels", + "a not so important value", "baz"), class = "factor") plot(c) Is there a way to get the long variable labels to automatically wrap so that all

:-) I don't insist on anything, I'm just struggling to learn a new language and partly a new way of thinking, and I really appreciate the corrections. I hope I someday will be able to handle lists in R as easy as I handle loops in Stata... Thanks again! Love -----Ursprungligt meddelande----- Fr?n: peter dalgaard [mailto:pdalgd at gmail.com] Skickat: den 4 december 2017 23:09 Till:

What I want to do is: 1, creat a text box, insert text into that box. 2, select chunk of of the text by mouse, and link it to a lable. so I would like a way to get that chunk of text. Can I do such job with tcltk? Any relavant tutorial materials? Thanks -- HUANG Ronggui Bachelor of Social Work, Fudan University, China Master of sociology, Fudan University, China Ph.D. Student , CityU of

R-users -- I would like to make a single vector out of something like the following: y0 <- rep(0,100) y1 <- rep(1,20) and stack them one on top of the other to a vector y with length 120. Thanks, Dan =-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-= Dan Powers Associate Professor, Sociology University of Texas at Austin