Displaying 1 result from an estimated 1 matches for "smoothlist".
Did you mean:
smoothest
2006 Sep 18
0
Question on apply() with more information...
...' <petr.pikal at precheza.cz>
>Cc: r-help at stat.math.ethz.ch
>Subject: Re: [R] Question on apply() with more information...
I think you want something like below but it
probably needs some fixing up because i don't recall
the syntax exactly.
predictdata<-lapply(i=1:length(Smoothlist),function predict (smthlist[[i]],xarry[i,])smthlist= SmoothList,xarry=Xarry)
>Hi,
>
>I tried both ideas, but it isn't that what I'm looking for.
>I want to avoid for loop, because the matrix is of big size(1200*1200
>entries)
>
>With a loop I would do:
>
>for...